Download DI with Data Connected Sets for CAT<\/a><\/p>\n Enroll for CAT 2022 Crash Course<\/a><\/p>\n Instructions<\/b><\/p>\n Red, Yellow, Green and Violet costs are allocated to different retail formats. These costs are apportioned in the ratio of number of units consumed by each retail format. The number of units consumed by each retail format is given in the table below:<\/p>\n Question 1:\u00a0<\/b>Which retail format gives the highest profit for BnC?<\/p>\n a)\u00a0BookStore<\/p>\n b)\u00a0Supermarket<\/p>\n c)\u00a0Online<\/p>\n d)\u00a0All are equally profitable.<\/p>\n e)\u00a0Cannot be determined from given information.<\/p>\n 1)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Solution:<\/b><\/p>\n The ratio of supermarket sales and book store sales is 1:2<\/p>\n Supermarket sales = (30000*1)\/3 = 10000<\/p>\n Bookstore sales =\u00a0(30000*2)\/3 = 20000<\/p>\n Initial costs for online = 50% of total initial costs\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 (Initial cost is allocated in ratio of sales)<\/p>\n = 50% of 39000 = 19500<\/p>\n Initial costs for supermarket =\u00a0 (19500*1)\/3 = 6500\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 (Initial cost is allocated in ratio of sales)<\/p>\n Initial costs for bookstore =\u00a0(19500*2)\/3 = 13000<\/p>\n For online:<\/p>\n Additional costs = Red + Yellow + Green + Violet\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0for online)\u00a0 \u00a0 \u00a0….(1)<\/p>\n Total red costs = 5500<\/p>\n Red costs for online = 5500*(200\/275) = 4000<\/p>\n Similarly,<\/p>\n Yellow costs for online = 3100*(52\/100) =\u00a0 1612<\/p>\n Green costs for online = 4800*(50\/80)\u00a0= 3000<\/p>\n Violets costs for online = 2400*(50\/80)\u00a0= 1500<\/p>\n Addition costs for online = 4000+1612+3000+1500 = 10112\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 From (1)<\/p>\n Profit = Sales – Initial costs – Additional costs = 30000-19500- 10112 = 388<\/p>\n For Supermarket:<\/p>\n Additional costs = Red + Yellow + Green + Violet<\/p>\n =\u00a05500*(65\/275) + 3100*(20\/100) +4800*(21\/80)+2400*(21\/80) = 3810<\/p>\n Profit = 10000-6500- 3810<\/p>\n = -310<\/p>\n For Bookstore:<\/p>\n Additional costs = Red + Yellow + Green + Violet<\/p>\n =\u00a05500*(10\/275) + 3100*(30\/100) +4800*(9\/80)+2400*(9\/80)<\/p>\n Profit = 20000-13000-1940 = 5060<\/p>\n Question 2:\u00a0<\/b>Which retail format is least profit making for BnC?<\/p>\n a)\u00a0Online<\/p>\n b)\u00a0Supermarket<\/p>\n c)\u00a0Book Store<\/p>\n d)\u00a0All formats are loss making. E. All formats are profit making.<\/p>\n 2)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Solution:<\/b><\/p>\n Sales from online = 50% of total sales = 50% of 60000 = 30000<\/p>\n The ratio of supermarket sales and book store sales is 1:2<\/p>\n Supermarket sales = (30000*1)\/3 = 10000<\/p>\n Bookstore sales =\u00a0(30000*2)\/3 = 20000<\/p>\n Initial costs for online = 50% of total initial costs\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 (Initial cost is allocated in ratio of sales)<\/p>\n = 50% of 39000 = 19500<\/p>\n Initial costs for supermarket =\u00a0 (19500*1)\/3 = 6500\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 (Initial cost is allocated in ratio of sales)<\/p>\n Initial costs for bookstore =\u00a0(19500*2)\/3 = 13000<\/p>\n For online:<\/p>\n Additional costs = Red + Yellow + Green + Violet\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0for online)\u00a0 \u00a0 \u00a0….(1)<\/p>\n Total red costs = 5500<\/p>\n Red costs for online = 5500*(200\/275) = 4000<\/p>\n Similarly,<\/p>\n Yellow costs for online = 3100*(52\/100) =\u00a0 1612<\/p>\n Green costs for online = 4800*(50\/80)\u00a0= 3000<\/p>\n Violets costs for online = 2400*(50\/80)\u00a0= 1500<\/p>\n Addition costs for online = 4000+1612+3000+1500 = 10112\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 From (1)<\/p>\n Profit = Sales – Initial costs – Additional costs = 30000-19500- 10112 = 388<\/p>\n For Supermarket:<\/p>\n Additional costs = Red + Yellow + Green + Violet<\/p>\n =\u00a05500*(65\/275) + 3100*(20\/100) +4800*(21\/80)+2400*(21\/80) = 3810<\/p>\n Profit = 10000-6500- 3810<\/p>\n = -310<\/p>\n For Bookstore:<\/p>\n Additional costs = Red + Yellow + Green + Violet<\/p>\n =\u00a05500*(10\/275) + 3100*(30\/100) +4800*(9\/80)+2400*(9\/80)<\/p>\n Profit = 20000-13000-1940 = 5060<\/p>\n Supermarket is making least profit for BnC.<\/p>\n Question 3:\u00a0<\/b>What is the profit\/loss from “online” sales? (Use data from previous question if needed)<\/p>\n a)\u00a00<\/p>\n b)\u00a0-310<\/p>\n c)\u00a0+20<\/p>\n d)\u00a0+388<\/p>\n e)\u00a0Cannot be determined from given information<\/p>\n 3)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Solution:<\/b><\/p>\n Sales from online = 50% of total sales = 50% of 60000 = 30000<\/p>\n Initial costs for online = 50% of total initial costs\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 (Initial cost is allocated in ratio of sales)<\/p>\n = 50% of 39000 = 19500<\/p>\n Additional costs = Red + Yellow + Green + Violet\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0for online)\u00a0 \u00a0 \u00a0….(1)<\/p>\n Total red costs = 5500<\/p>\n Red costs for online = 5500*(200\/275) = 4000<\/p>\n Similarly,<\/p>\n Yellow costs for online = 3100*(52\/100) =\u00a0 1612<\/p>\n Green costs for online = 4800*(50\/80)\u00a0= 3000<\/p>\n Violets costs for online = 2400*(50\/80)\u00a0= 1500<\/p>\n Addition costs for online = 4000+1612+3000+1500 = 10112\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 From (1)<\/p>\n Profit = Sales – Initial costs – Additional costs = 30000-19500- 10112 = 388<\/p>\n Question 4:\u00a0<\/b>Read the following statements: a)\u00a0Statement I alone is sufficient to calculate the profit\/loss.<\/p>\n b)\u00a0Statement II alone is sufficient to calculate the profit\/loss.<\/p>\n c)\u00a0Both statements I and Il are required to calculate the profit\/loss.<\/p>\n d)\u00a0Either of the two statements is sufficient to calculate the profit\/loss.<\/p>\n e)\u00a0Neither Statement I nor Statement Il is sufficient to calculate the profit\/loss.<\/p>\n 4)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Solution:<\/b><\/p>\n Sales for online = 50% of 60000 = 30000<\/p>\n Remaining sales = 60000-30000 = 30000<\/p>\n The ratio of supermarket sales and book store sales is 1:2<\/p>\n Supermarket sales = (30000*1)\/3 = 10000<\/p>\n Bookstore sales =\u00a0(30000*2)\/3 = 20000<\/p>\n Profit = Sales – Initial costs – Additional costs<\/p>\n Sales and Additional costs can be calculated from the table. But no information about distribution of initial costs among different retails formats. From statement 2 the distribution of initial costs is clear.<\/p>\n Hence both statements will be used to calculate profit for different retail formats.<\/p>\n Instructions<\/b><\/p>\n Answer the questions based on the following information. Mulayam Software Co., before selling a package to its clients, follows the given schedule.<\/p>\n The number of people employed in each month is:<\/p>\n Question 5:\u00a0<\/b>Which five consecutive months have the lowest average cost per man-month under the new technique?<\/p>\n a)\u00a01-5<\/p>\n b)\u00a09-13<\/p>\n c)\u00a011-15<\/p>\n d)\u00a0None of these<\/p>\n 5)\u00a0Answer\u00a0(C)<\/strong><\/p>\n View Video Solution<\/a><\/p>\n Solution:<\/b><\/p>\n Lowest cost per person is for coding and maintenance i.e. 10 rs. Checkout: CAT Free Practice Questions and Videos<\/strong><\/a><\/em><\/p>\n Question 6:\u00a0<\/b>Under the new technique, which stage of software development is most expensive for Mulayam Software Co.?<\/p>\n a)\u00a0Testing<\/p>\n b)\u00a0Specification<\/p>\n c)\u00a0Coding<\/p>\n d)\u00a0Design<\/p>\n 6)\u00a0Answer\u00a0(D)<\/strong><\/p>\n View Video Solution<\/a><\/p>\n Solution:<\/b><\/p>\n Total incurred cost for testing = $(4+1)\\times 15 = 75$ Hence design is most expensive for the company.<\/p>\n Question 7:\u00a0<\/b>What is the difference in cost between the old and the new techniques?<\/p>\n a)\u00a0Rs. 30,000<\/p>\n b)\u00a0Rs. 60,000<\/p>\n c)\u00a0Rs. 70,000<\/p>\n d)\u00a0Rs. 40,000<\/p>\n 7)\u00a0Answer\u00a0(B)<\/strong><\/p>\n View Video Solution<\/a><\/p>\n Solution:<\/b><\/p>\n In new technique, increment in 5th month cost (‘000) \u00a0= $(5 \\times 20 – 4 \\times 10)$ = 60<\/p>\n Question 8:\u00a0<\/b>With reference to the above question, what is the cost incurred in the new \u2018coding\u2019 stage? (Under the new technique, 4 people work in the sixth month and 5 in the eighth.)<\/p>\n a)\u00a0Rs. 1,40,000<\/p>\n b)\u00a0Rs. 1,50,000<\/p>\n c)\u00a0Rs. 1,60,000<\/p>\n d)\u00a0Rs. 1,70,000<\/p>\n 8)\u00a0Answer\u00a0(A)<\/strong><\/p>\n View Video Solution<\/a><\/p>\n Solution:<\/b><\/p>\n As coding is done in 6-8 months, Question 9:\u00a0<\/b>Due to overrun in \u2018design\u2019, the design stage took 3 months, i.e. months 3, 4 and 5. The number of people working on design in the fifth month was 5. Calculate the percentage change in the cost incurred in the fifth month. (Due to improvement in \u2018coding\u2019 technique, this stage was completed in months 6-8 only.)<\/p>\n a)\u00a0225%<\/p>\n b)\u00a0150%<\/p>\n c)\u00a0275%<\/p>\n d)\u00a0240%<\/p>\n 9)\u00a0Answer\u00a0(B)<\/strong><\/p>\n View Video Solution<\/a><\/p>\n Solution:<\/b><\/p>\n In given table, value of cost for 5th month = $(N) \\times (C)$ (No.of employer for 5th month = N and\u00a0cost per person for 5th month = C) Question 10:\u00a0<\/b>If the sum of the roots of the equation $\\frac{(x+p)}{(x+p+r)}$ + $\\frac{(x-q)}{(x-q+r)}$ = 1 is zero, which of the following options is correct?<\/p>\n a)\u00a0p + q = 0<\/p>\n b)\u00a0p + q + r = 0<\/p>\n c)\u00a0p + q = 2r<\/p>\n d)\u00a0p = q<\/p>\n 10)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Solution:<\/b><\/p>\n Expanding the equation on both sides,<\/p>\n $\\frac{(x+p)}{(x+p+r)}$ + $\\frac{(x-q)}{(x-q+r)}$ = 1<\/p>\n 1 – $\\frac{(r)}{(x+p+r)}$ + 1 –\u00a0$\\frac{(r)}{(x-q+r)}$ = 1<\/p>\n $\\frac{(r)}{(x+p+r)}$ +\u00a0$\\frac{(r)}{(x-q+r)}$ = 2-1 = 1<\/p>\n $\\frac{(r)(2x+2r+p-q)}{(x+p+r)(x-q+r)}$ = 1<\/p>\n 2rx + $2r^2$ + pr – qr = $x^2$ – qx + rx + px – pq + pr + rx – qr +\u00a0$r^2$<\/p>\n $x^2$+ (p-q)x – pq- $r^2$ = 0<\/p>\n Sum of the roots = 0<\/p>\n -(p-q)\/1 = 0<\/p>\n q = p<\/p>\n Question 11:\u00a0<\/b>If y is a real number, what is the difference in the maximum and minimum values obtained by $\\frac{y+5}{y^2+5y+25}$ ?<\/p>\n a)\u00a02\/15<\/p>\n b)\u00a04\/15<\/p>\n c)\u00a01\/5<\/p>\n d)\u00a01\/15<\/p>\n 11)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Solution:<\/b><\/p>\n Let $\\frac{y+5}{y^2+5y+25} = k$<\/p>\n So, $ky^2+5ky+25k-y-5=0$<\/p>\n For the above quadriatic equation to have real roots, its discriminant should be greater than or equal to zero.<\/p>\n $(5k-1)^2 \\geq 4*k*5*(5k-1)$ solving we get So, the difference in the maximum and minimum value is 4\/15<\/p>\n Question 12:\u00a0<\/b>How many integral solutions exist for the inequality |x-5| + |y-4| < 4?<\/p>\n a)\u00a010<\/p>\n b)\u00a015<\/p>\n c)\u00a025<\/p>\n d)\u00a033<\/p>\n 12)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Solution:<\/b><\/p>\n Let x-5 = a and y-4 = b. Question 13:\u00a0<\/b>If a,b and c are three whole numbers such that |a-1|+|b-2|+|c-3|=3, what is the maximum value of (a+1)(b+2)(c+3)?<\/p>\n a)\u00a0120<\/p>\n b)\u00a0144<\/p>\n c)\u00a0112<\/p>\n d)\u00a0105<\/p>\n 13)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Solution:<\/b><\/p>\n There are fifteen solutions to the equation |a-1|+|b-2|+|c-3|=3. Instructions<\/b><\/p>\n The first table gives the number of saris (of all the eight colours) stocked in six regional showrooms. The second gives the number of saris (of all the eight colours) sold in these six regional showrooms. The third table gives the percentage of saris sold to saris stocked for each colour in each region. The fourth table gives the percentage of saris of a specific colour sold within that region. The fifth table gives the percentage of saris of a specific colour sold across all the regions. Study the tables and for each of the following questions, choose the best alternative.<\/p>\n Table 1<\/p>\n Table 2<\/p>\n Table 3<\/p>\n Table 4<\/p>\n Table 5<\/p>\n a)\u00a02<\/p>\n b)\u00a03<\/p>\n c)\u00a01<\/p>\n d)\u00a04<\/p>\n 14)\u00a0Answer\u00a0(A)<\/strong><\/p>\n View Video Solution<\/a><\/p>\n Solution:<\/b><\/p>\n From Table 5, we can see that out of all the regions, the maximum number of blue saries were sold in region 2<\/p>\n Question 15:\u00a0<\/b>Out of its total sales, which region sold the minimum percentage of green saris?<\/p>\n a)\u00a01<\/p>\n b)\u00a04<\/p>\n c)\u00a06<\/p>\n d)\u00a02<\/p>\n 15)\u00a0Answer\u00a0(B)<\/strong><\/p>\n View Video Solution<\/a><\/p>\n Solution:<\/b><\/p>\n Given we have 6 regions where sales are defined in the table number two . Now given that we need to find the region where green saris as a percentage of the total sales is lowest . In order to do that we calculate Green saris sold in a region\/ Total sales of a particular region by considering the values from table 2 .<\/p>\n Now for option 1 which is region 1 the value is (164\/788)*100\u00a0 = 20.81 %<\/p>\n For option 2 which is region 4 the value is (85\/511)*100 = 16.63 %<\/p>\n For option 1 which is region 6 the value is (3\/18)*100 = 16.66 %<\/p>\n For option 1 which is region 2\u00a0 the value is (200\/676)*100 = 29.58\u00a0 % .<\/p>\n Hence among the given options the percentage of region 4 is lowest which is option 2 .<\/p>\n Question 16:\u00a0<\/b>Which region sold the maximum percentage of magenta saris out of the total sales of magenta saris?<\/p>\n a)\u00a03<\/p>\n b)\u00a04<\/p>\n c)\u00a02<\/p>\n d)\u00a01<\/p>\n 16)\u00a0Answer\u00a0(D)<\/strong><\/p>\n View Video Solution<\/a><\/p>\n Solution:<\/b><\/p>\n Since table 2 gives us the sales values of saris Question 17:\u00a0<\/b>Which colour is the most popular in region1?<\/p>\n a)\u00a0Blue<\/p>\n b)\u00a0Brown<\/p>\n c)\u00a0Green<\/p>\n d)\u00a0Violet<\/p>\n 17)\u00a0Answer\u00a0(B)<\/strong><\/p>\n View Video Solution<\/a><\/p>\n Solution:<\/b><\/p>\n As the most popular colours will have more sale than any other colour Question 18:\u00a0<\/b>Which region-colour combination accounts for the highest percentage of sales to stock?<\/p>\n a)\u00a0(1, Brown)<\/p>\n b)\u00a0(2, Yellow)<\/p>\n c)\u00a0(4, Brown)<\/p>\n d)\u00a0(5, Red<\/p>\n 18)\u00a0Answer\u00a0(C)<\/strong><\/p>\n
\nb. You can buy books from supermarket,
\nc. You can order books over the Internet (Online).Your manager has an interesting way of classifying expenses: some of the expenses are classified in terms of size: Big, Small and Medium; and others are classified in terms of the colors, Red, Yellow, Green and Violet. The company has a history of categorizing overall costs into initial costs and additional costs. Additional costs are equal to the sum of Big, Small and Medium expenses. There are two types of margins, contribution (sales minus initial costs) and profit (contribution minus additional costs). Given below is the data about sales and costs of BnC:
\n
\nEach of the Big, Small and Medium cost is categorized by the manager into Red, Yellow, Green and Violet costs. Breakdown of the additional costs under these headings is shown in the table below:<\/p>\n<\/p>\n
<\/figure>\n
<\/del>Sales from online = 50% of total sales = 50% of 60000 = 30000<\/p>\n<\/del>Bookstore gives highest profit for BnC.<\/p>\n
\nStatement I. Online store accounted for 50% of the sales at BnC and the ratio of supermarket sales and book store sales is 1:2.
\nStatement II. Initial Cost is allocated in the ratio of sales. If you want to calculate the profit\/loss from the different retail formats, then<\/p>\n![\"\"](\"https:\/\/cracku.in\/media\/uploads\/2016\/12\/30\/1056_UmUL6VW.JPG\")
<\/p>\n![](\"https:\/\/cracku.in\/media\/uploads\/5_lSuJFI5.PNG\")
<\/p>\n
\nBut for consecutive five months avg. for coding and any other will be more than consecutive 5 months for maintenance.
\nSo avg. cost for five months of maintenance is = $\\frac{(3+3+1+1+1) \\times 10}{9} = 10$
\nWhich is lowest among all others<\/p>\n
\nIncurred cost for specification = $(2+3) \\times 40 = 200$
\nIncurred cost for coding = $(4+5+5) \\times 10 = 140$
\nIncurred cost for design = $(3+4+5) \\times 20 = 240$<\/p>\n
\nSo total person employed = 4+5+5 = 14
\ncost per person for 6-8 month = 10000
\nTotal cost will be = $(14 \\times 10000)$ = 140,000<\/p>\n
\nSo value of cost for 5th month before overrun = $4 \\times 10 = 40$
\nvalue of cost for 5th month after overrun = $ 5 \\times 20 = 100 $
\nChange = 60
\n%change = $\\frac{60}{40} \\times 100$ = 150<\/p>\n
\n$25k^2-10k+1\\ge20k\\left(5k-1\\right)$
\n$25k^2-10k+1\\ge100k^2-20k$
\n$75k^2-10k-1\\le0$<\/p>\n
\n$(15k+1)(5k-1)\\leq 0 $
\nSo $-1\/15 \\leq k \\leq 1\/5$<\/p>\n
\nSo, the number of solutions to the inequality equals that of the inequality |a|+|b|<4
\nIf |a|+|b|=0, number of integral solutions is 1 i.e. {0,0}
\nIf |a|+|b|=1, number of integral solutions is 4 i.e. {1,0},{0,1},{-1,0},{0,-1}
\nIf |a|+|b|=2, number of integral solutions is 8\u00a0i.e. {2,0},{1,1},{0,2},{1,-1},{-1,1},{-1,-1},{-2,0},{0,-2}
\nIf |a|+|b|=3, number of integral solutions is 12\u00a0i.e. {3,0}x2, {0,3}x2, {2,1}x4, {1,2}x4
\nTotal is 25<\/p>\n
\nLet |a-1| be x, |b-2| be y and |c-3| be z.
\nx, y and z are whole numbers.
\nx +\u00a0y +\u00a0z = 3.
\nTherefore, the number of solutions to this equation will be n+r-1 C r-1 = 3+3-1C2 = 5C2 = 10.
\nThere are 10 solutions to the equation x+y+z = 3.
\nAfter enumerating them, we find that (a+1)(b+2)(c+3) is maximum when a=b=c=3 and its maximum value is 120.<\/p>\n![\"\"](\"https:\/\/cracku.in\/media\/uploads\/2016\/12\/29\/screenshot-from-2016-12-29-121451.png\")
<\/p>\n![\"\"](\"https:\/\/cracku.in\/media\/uploads\/2016\/12\/29\/screenshot-from-2016-12-29-121801.png\")
<\/p>\n![\"\"](\"https:\/\/cracku.in\/media\/uploads\/2016\/12\/29\/screenshot-from-2016-12-29-121849.png\")
<\/p>\n![\"\"](\"https:\/\/cracku.in\/media\/uploads\/2016\/12\/29\/screenshot-from-2016-12-29-121927.png\")
<\/p>\n![\"\"](\"https:\/\/cracku.in\/media\/uploads\/2016\/12\/29\/screenshot-from-2016-12-29-122005.png\")
\nQuestion 14:\u00a0<\/b>In which region is the maximum percentage of blue saris sold?<\/p>\n
\nHence, for the magenta\u00a0sari, Region1 has the maximum number of sales out of total magenta sales.
\nI.e. 71 out of 161.<\/p>\n
\nSince table 2 gives us value of sales, Brown colour in region 1 has maximum no. of sales
\nHence, our answer will be Brown.<\/p>\n