Time and Distance is one of the key topics in the IBPS PO Prelims exam. Here you can download free Time and Distance questions PDF with answers for IBPS PO Prelims 2022 by Cracku. These questions will help you to practice and solve the Time and Distance questions in the IBPS PO exams. Utilize this best PDF practice set which includes the answers in detail. Click on the below link to download the Time and Distance Usage MCQ questions PDF for IBPS PO Prelims 2022 for Free.<\/p>\n
Download Time and Distance Questions for IBPS PO Prelims<\/a><\/p>\n Download IBPS PO Previous Papers<\/a><\/p>\n Question 1:\u00a0<\/b>Places A and are 45 km apart from each other. A car starts from place A and another car starts from place at the same time. If they move in the same direction, they meet in 4 and a half hour and if they move towardseach other, they meet in 27 minutes. Whatis the speed (in km\/h) of the car which moves faster?<\/p>\n a)\u00a056<\/p>\n b)\u00a055<\/p>\n c)\u00a045<\/p>\n d)\u00a050<\/p>\n 1)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Question 2:\u00a0<\/b>A boat can cover 336 km distance downstream in 4.2 hours. The same boat can cover the same distance in still water in 6.72 hours. Find out the speed of the stream.<\/p>\n a)\u00a035 km\/h<\/p>\n b)\u00a025 km\/h<\/p>\n c)\u00a040 km\/h<\/p>\n d)\u00a030 km\/h<\/p>\n 2)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Solution:<\/b><\/p>\n The same boat can cover the same distance in still water in 6.72 hours. Question 3:\u00a0<\/b>Find the average speed of a car traveling at 12km\/hr for 40km and the same distance at 15km\/hr?<\/p>\n a)\u00a0$\\dfrac {40}{3}$ km\/hr<\/p>\n b)\u00a0$\\dfrac {20}{3}$ km\/hr<\/p>\n c)\u00a0$\\dfrac {25}{3}$ km\/hr<\/p>\n d)\u00a0None of the above<\/p>\n 3)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Solution:<\/b><\/p>\n The average speed covered by the car traveling the same distance for two speeds let x and y is given as Question 4:\u00a0<\/b>A boat covers a 20 km distance towards downstream in 4 hours. If the speed of the boat is 1.5 times the speed of the current then find the time taken by the boat to cover the same distance in upstream.<\/p>\n a)\u00a022 hours<\/p>\n b)\u00a020 hours<\/p>\n c)\u00a025 hours<\/p>\n d)\u00a0Can\u2019t be determined<\/p>\n 4)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Solution:<\/b><\/p>\n Let the speed of the boat and speed of the stream be x km\/hr and y km\/hr respectively. Time taken to cover 20 km in upstream, let it be \u2018T\u2019 Question 5:\u00a0<\/b>One pipe P can fill a tank in 24 hours. Two pipes Q and R with equal efficiency are opened along with P and hence the tank is filled in 12 hours. Find the time taken by R alone to fill the complete tank alone.<\/p>\n a)\u00a036 hours<\/p>\n b)\u00a032 hours<\/p>\n c)\u00a048 hours<\/p>\n d)\u00a024 hours<\/p>\n 5)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Solution:<\/b><\/p>\n Time taken by P alone to fill the tank = 24 hours Take Free IBPS PO Mock Tests<\/a><\/p>\n Question 6:\u00a0<\/b>The ratio between the speed of bus and truck is 6:7 respectively. A bus can cover d km distance in 7 hours. A truck can cover (d-140) km distance in 5 hours. Then find out the value of d.<\/p>\n a)\u00a0840<\/p>\n b)\u00a0700<\/p>\n c)\u00a0660<\/p>\n d)\u00a0980<\/p>\n 6)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Solution:<\/b><\/p>\n The ratio between the speed of bus and truck is 6:7 respectively. $\\frac{d}{42} = y$ Eq.(i)<\/p>\n A truck can cover (d-140) km distance in 5 hours. $\\frac{(d-140)}{35} = y$ Eq.(ii)<\/p>\n Equating Eq.(i) and Eq.(ii). $\\frac{(d-140)}{5} = \\frac{d}{6}$<\/p>\n 6d – 840 = 5d Question 7:\u00a0<\/b>A boat can cover 720 km distance downstream in 40 hours. The speed of boat in still water is double the speed of the stream. Then find out the time taken by boat to cover 480 km distance in upstream.<\/p>\n a)\u00a0100 hours<\/p>\n b)\u00a060 hours<\/p>\n c)\u00a040 hours<\/p>\n d)\u00a080 hours<\/p>\n 7)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Solution:<\/b><\/p>\n Let’s assume the speed of boat in still water and the speed of stream is B and C respectively. B+C = 18 km\/h Eq.(i) = $\\frac{480}{6}$<\/p>\n = 80 hours Question 8:\u00a0<\/b>Pipe P and pipe Q together can fill a tank in 31.5 hours. Pipe R alone can empty the tank in 63 hours. Find out the time taken by all the three pipes together to fill 33.33% of the tank.<\/p>\n a)\u00a035 hours<\/p>\n b)\u00a028 hours<\/p>\n c)\u00a042 hours<\/p>\n d)\u00a021 hours<\/p>\n 8)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Solution:<\/b><\/p>\n Let\u2019s assume the total capacity of the tank is 504. Question 9:\u00a0<\/b>The time taken by the pipes A and B together to fill the tank is 30% of the time taken by the pipe C alone to fill the same tank. The time taken by pipe\u00a0A alone to fill the same tank is 4 hours more than the time taken by pipe\u00a0B alone to fill the tank. If the time taken by pipe\u00a0A alone to fill the tank is 12 hours, then find the time taken by pipe\u00a0C alone to fill the tank.<\/p>\n a)\u00a08 hours<\/p>\n b)\u00a016 hours<\/p>\n c)\u00a012 hours<\/p>\n d)\u00a010 hours<\/p>\n 9)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Solution:<\/b><\/p>\n Time taken by A to fill the tank alone = 12 hours. Question 10:\u00a0<\/b>A boat can cover 390 km distance upstream in 78 hours. The speed of the stream is 44.44% of the speed of the boat. Then find out the time taken by boat to cover the same distance downstream.<\/p>\n a)\u00a030 hours<\/p>\n b)\u00a035 hours<\/p>\n c)\u00a025 hours<\/p>\n d)\u00a020 hours<\/p>\n 10)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Solution:<\/b><\/p>\n Let\u2019s assume the speed of the boat in still water is B and the speed of the stream is C. $\\frac{5}{9}\\times B = 5$ = 30 hours Question 11:\u00a0<\/b>Three pipes A, C and B can fill a tank in 12 hours, 24 hours and 18 hours respectively. If in the first hour, A and B are opened and in the second hour, A and C are opened and in the third hour, all three pipes are opened and this process is repeated till the tank is filled, then how much time does it take to fill the tank?<\/p>\n a)\u00a08.46 hours<\/p>\n b)\u00a06.8 hours<\/p>\n c)\u00a09.42 hours<\/p>\n d)\u00a08.48 hours<\/p>\n 11)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Solution:<\/b><\/p>\n Let the total capacity of the tank be 72 units (LCM of 12, 24 and 18). A and B are opened in the first hour, A and C are opened in the second hour, A, B and C are opened in the third hour. Hence, The tank will be filled in 6+0.8 = 6.8 hours.<\/p>\n Question 12:\u00a0<\/b>Pipes P and Q can fill the tank together in 11.52 hours. Pipes Q and R can fill the tank together in 19.2 hours. Pipes P and R can fill the tank together in $13\\dfrac{1}{11}$ hours. Find the time taken by all the three pipes to fill the tank together.<\/p>\n a)\u00a09.29 hours<\/p>\n b)\u00a010.67 hours<\/p>\n c)\u00a08.33 hours<\/p>\n d)\u00a09.84 hours<\/p>\n 12)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Solution:<\/b><\/p>\n Pipes P and Q can fill the tank together in 11.52 hours. Let the total capacity of the tank be 288 units. Efficiency of P+Q+R = 31 units.<\/p>\n Hence, The tank will be filled by P, Q and R together in $\\dfrac{288}{31} = 9.29$ hours.<\/p>\n Question 13:\u00a0<\/b>Pipe A and B can together fill a tank in 12 hours and pipe B and C can together fill a tank in 15 hours. If the efficiency of A is two times that of C, then find the time taken by Pipe B alone to fill the tank completely.<\/p>\n a)\u00a016.33 hours<\/p>\n b)\u00a024.5 hours<\/p>\n c)\u00a020 hours<\/p>\n d)\u00a013 hours<\/p>\n 13)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Solution:<\/b><\/p>\n According to the question, Now on comparing both the equation 1 and 2, we get Question 14:\u00a0<\/b>If the man can row 800m in 20 minutes against the current of the river, and returns the same distance in 10 minutes , then find the speed of man and speed of the river respectively.<\/p>\n a)\u00a01, $\\frac{1}{3}$ m\/s<\/p>\n b)\u00a03, 5 m\/s<\/p>\n c)\u00a02, $\\frac{1}{2}$ m\/s<\/p>\n d)\u00a0None of the above<\/p>\n 14)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Solution:<\/b><\/p>\n According to the question, On solving this we get, Question 15:\u00a0<\/b>Two cars each from point X and Y respectively start travelling with the constant speed, where the distance between point X and Y is 150km then find the speed of the car with greater speed, given that if the cars move in the same direction they must meet in 6 hours and if they move towards each other then they must meet after 120 minutes.<\/p>\n a)\u00a040 km\/h<\/p>\n b)\u00a045 km\/h<\/p>\n c)\u00a035 km\/h<\/p>\n d)\u00a050 km\/h<\/p>\n 15)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Solution:<\/b><\/p>\n According to the question,
\nSpeed of the boat in still water = $\\frac{336}{6.72}$ = 50 km\/h
\nA boat can cover 336 km distance downstream in 4.2 hours.
\n$\\frac{336}{50 + \\text{speed of the stream}} = 4.2$
\n80 = 50 + speed of the stream
\nspeed of the stream = 80-50 = 30 km\/h
\nHence, option d is the correct answer.<\/p>\n
\n= 2xy\/(x+y)
\n= $\\dfrac {(2 \\times 12 \\times 15)}{12+15}$
\n= $\\dfrac {360}{27}$
\n= $\\dfrac {40}{3}$ km\/hr<\/p>\n
\nATQ,
\nDistance = Speed x Time
\nUpstream speed = x-y
\nDownstream speed = x+y
\n20 = 4(x+y)
\nx+y = 5
\nGiven x=1.5y,
\nSo,
\n1.5y + y = 5
\n2.5y = 5
\ny = 2km\/hr
\nx = 3 km\/hr<\/p>\n
\n20 = T(x-y)
\n20 = T x 1
\nT = 20 hours<\/p>\n
\nTime taken by P, Q and R to fill the tank = 12 hours.
\nLet the capacity of the tank be 48 units.
\nEfficiency of P = $\\dfrac{48}{24}$ = 2 units per hour
\nEfficiency of P, Q and R together = $\\dfrac{48}{12} = 4$ units per hour.
\nEfficiency of Q and R together = 4-2 = 2 units per hour.
\nHence, Efficiency of Q and R = 1 unit per hour each.
\nTherefore, R can fill the tank in $\\dfrac{48}{1} = 48$ hours.<\/p>\n
\nLet’s assume the speed of bus and truck is 6y and 7y respectively.
\nA bus can cover d km distance in 7 hours.
\n$\\frac{d}{7} = 6y$<\/p>\n
\n$\\frac{(d-140)}{5} = 7y$<\/p>\n
\n$\\frac{(d-140)}{35} = \\frac{d}{42}$<\/p>\n
\n6d-5d = 840
\nd = 840 km
\nHence, option a is the correct answer.<\/p>\n
\nA boat can cover 720 km distance downstream in 40 hours.
\nB+C = $\\frac{720}{40}$<\/p>\n
\nThe speed of boat in still water is double the speed of stream.
\nB = 2C Eq.(ii)
\nPut Eq.(ii) in Eq.(i).
\n2C+C = 18 km\/h
\n3C = 18 km\/h
\nC = 6 km\/h Eq.(iii)
\nPut Eq.(iii) in Eq.(ii).
\nB = $2\\times6$ = 12 km\/h
\nThe time taken by boat to cover 480 km distance in upstream = $\\frac{480}{B-C}$
\n= $\\frac{480}{12-6}$<\/p>\n
\nHence, option d is the correct answer.<\/p>\n
\nPipe P and pipe Q together can fill a tank in 31.5 hours.
\nEfficiency of pipe P and Q together = 504\/31.5 = 16
\nPipe R alone can empty the tank in 63 hours.
\nEfficiency of pipe R = 504\/63 = – 8 (Here negative sign is for emptying the tank.)
\n33.33% of the tank = \u2153 of 504 = 168
\nTime taken by three pipes together to fill the tank = 168\/(16-8) = 168\/8 = 21 hours
\nHence, option d is the correct answer.<\/p>\n
\nThen, Time taken by B alone to fill the tank = 12-4 = 8 hours.
\nLet the capacity of the tank be 48 units (LCM of 12 and 8).
\nEfficiency of A = 4 units per hour.
\nEfficiency of B = 6 units per hour.
\nTime taken by A and B together to fill the tank = $\\dfrac{48}{4+6} = \\dfrac{48}{10} = 4.8$ units per hour.
\nThen, Time taken by C alone to fill the tank = $\\dfrac{4.8}{30\\%} = 16$ hours.<\/p>\n
\nThe speed of the stream is 44.44% of the speed of the boat.
\nC = 44.44% of B
\n$C = \\frac{4}{9}\\times B$ Eq.(i)
\nA boat can cover 390 km distance upstream in 78 hours.
\n$\\frac{390}{78} = B – C$
\nB – C = 5 Eq.(ii)
\nPut Eq.(i) in Eq.(ii).
\n$B – \\frac{4}{9}\\times B = 5$<\/p>\n
\nB = 9 km\/h Eq.(iii)
\nPut Eq.(iii) in Eq.(ii).
\n9 – C = 5
\nC = 9 – 5 = 4 km\/h
\nTime taken by boat to cover the same distance downstream = $\\frac{390}{9+4}$
\n= $\\frac{390}{13}$<\/p>\n
\nHence, option a is the correct answer.<\/p>\n
\nEfficiency of A = $\\dfrac{72}{12} = 6$ units.
\nEfficiency of B = $\\dfrac{72}{18} = 4$ units.
\nEfficiency of C = $\\dfrac{72}{24} = 3$ units.<\/p>\n
\nThen, in three hours, 6+4+6+3+6+4+3 = 32 units of the tank will be filled.
\nThen, 64 units of the tank will be filled in 6 hours.
\nRemaining 8 units of the tank will be filled by A and B together in $\\dfrac{8}{10} = 0.8$ hours.<\/p>\n
\nP+Q \u2192 11.52 = $\\dfrac{288}{25}$ units.
\nPipes Q and R can fill the tank together in 19.2 hours.
\nQ+R \u2192 19.2 = $\\dfrac{96}{5}$ or $\\dfrac{288}{15}$ units.
\nPipes P and R can fill the tank together in $13\\dfrac{1}{11}$
\nP+R \u2192 $\\dfrac{144}{11}$ or $\\dfrac{288}{22}$ units.<\/p>\n
\nEfficiency of P+Q = 25 units.
\nEfficiency of Q+R = 15 units.
\nEfficiency of P+R = 22 units.
\nEfficiency of 2(P+Q+R) = 62 units.<\/p>\n
\nLet the total work = (LCM 12,15) = 60
\nEfficiency of A + B = 60\/12 = 5 units per hour
\nEfficiency of B + C = 60\/15 = 4 units per hour
\nEfficiency of A = 2 $\\times$ efficiency of C
\nEfficiency of A = 5 – efficiency of B —— eq 1
\nEfficiency of C = 4 – efficiency of B
\nEfficiency of A = 8 – 2 $\\times$ efficiency of B —— eq 2<\/p>\n
\n5 – efficiency of B = 8 – 2 $\\times$ efficiency of B
\nEfficiency of B = 3 units per hour
\nSo,
\nTime taken by B to fill the tank = 60\/3 = 20 hours.<\/p>\n
\nLet the speed of the man be m, and the speed of the river be b
\nOn rowing against the current,
\nm – b = $\\frac{800}{20\\times 60} = \\frac{2}{3}$
\nOn rowing downstream,
\nm + b = $\\frac{800}{10\\times 60} = \\frac{4}{3}$<\/p>\n
\n2m = 2, m = 1m\/s
\nb = $\\frac{1}{3}$ m\/s<\/p>\n
\nDistance = 150 km
\nLet the speed of the car starting from point X be x km\/hr
\nAnd Y be y km\/hr
\nWhen moving is same direction,
\nx – y = 150\/6 , x – y = 25
\nWhen moving towards each other
\nx + y = 150\/2, x + y = 75
\nSolving this we get,
\n2x = 100, x = 50 km\/hr
\ny = 25km\/hr<\/p>\n