Here you can download a free Ratio and Proportion questions PDF with answers for IBPS PO and IBPS RRB PO 2022 by Cracku. These are some tricky questions in the IBPS PO and IBPS RRB PO 2022 exam that you need to find the Ratio and Proportion for the given questions. These questions will help you to do practice and solve the Ratio and Proportion questions in the IBPS PO and IBPS RRB PO exams. Utilize this best PDF practice set<\/strong> which is included answers in detail. Click on the below link to download the Ratio and Proportion MCQ<\/strong> PDF for IBPS PO and IBPS RRB PO 2022 for free.<\/p>\n Download Ratio and Proportion Questions for IBPS RRB and PO Prelims<\/a><\/p>\n Download IBPS PO Previous Papers<\/a><\/p>\n Question 1:\u00a0<\/b>A tank contains 120 litres of milk and 80 litres of water. If __ litres of mixture is taken out from the tank and __ litres of milk is added to the tank then the final quantity of milk is 57.14% more than the final quantity of water. a)\u00a0Only (ii) and (iii)<\/p>\n b)\u00a0Only (i) and (ii)<\/p>\n c)\u00a0All (i), (ii) and (iii)<\/p>\n d)\u00a0Only (iii)<\/p>\n e)\u00a0Only (i) and (iii)<\/p>\n 1)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Solution:<\/b><\/p>\n The final quantity of milk is 57.14% more than the final quantity of water. (i) 60, 4 (ii) 95, 3 (iii) 140, 2 Question 2:\u00a0<\/b>A certain number of toffees are divided among four people such that the ratio between the number of toffees obtained by B to C is 9:8 respectively. The number of toffees obtained by A is 20% less than the number of toffees obtained by D. The ratio between the number of toffees obtained by A and B is 4:3 respectively. If the number of toffees obtained by C is 40, then find out the sum of the number of toffees obtained by A, B and D.<\/p>\n a)\u00a0145<\/p>\n b)\u00a0175<\/p>\n c)\u00a0180<\/p>\n d)\u00a0160<\/p>\n e)\u00a0None of the above<\/p>\n 2)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Solution:<\/b><\/p>\n The ratio between the number of toffees obtained by B to C is 9:8 respectively. Question 3:\u00a0<\/b>An Organisation distributed chocolates to its employees on an occasion. The number of chocolates received by employee Y is 77.77% of the number of chocolates received by employee X. Ratio of the number of chocolates received by employees Y and Z is 9:8. If the average of the number of chocolates received by X, Y and Z is 66$\\frac{2}{3}$, then what is the number of chocolates received by Z?<\/p>\n a)\u00a081<\/p>\n b)\u00a072<\/p>\n c)\u00a063<\/p>\n d)\u00a056<\/p>\n e)\u00a0None of the above<\/p>\n 3)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Solution:<\/b><\/p>\n The number of chocolates received by employee Y is 77.77% of the number of chocolates received by employee X. Ratio of the number of chocolates received by employees Y and Z is 9:8. Average of the number of chocolates received by X, Y and Z is 66$\\frac{2}{3}$. Question 4:\u00a0<\/b>Certain amount of money was divided among four people such that the ratio between the amount obtained by B and C is 13:14 respectively. The difference between the amount obtained by A and D is Rs. 300. If the average of the amount obtained by C and D is Rs. 4900 and the amount obtained by A is 25% less than the amount obtained by B, then find out the average of the amount obtained by all the four people.<\/p>\n a)\u00a04195<\/p>\n b)\u00a04365<\/p>\n c)\u00a04725<\/p>\n d)\u00a04575<\/p>\n e)\u00a04945<\/p>\n 4)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Solution:<\/b><\/p>\n The ratio between the amount obtained by B and C is 13:14 respectively. Question 5:\u00a0<\/b>Certain amount is divided among P, Q and R such that the amount obtained by Q is 11.11% less than the amount obtained by P. The amount obtained by P is 14.28% more than the amount obtained by R. If the total amount divided among them is \u20b91194, then what is the amount obtained by R?<\/p>\n a)\u00a0\u20b9400<\/p>\n b)\u00a0\u20b9432<\/p>\n c)\u00a0\u20b9384<\/p>\n d)\u00a0\u20b9378<\/p>\n e)\u00a0None of the above<\/p>\n 5)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Solution:<\/b><\/p>\n Let the amount obtained by P = 72p Question 6:\u00a0<\/b>There are two tanks A and B which contain a mixture of milk and water. Tank A contains milk and water in the ratio of 4 : 1 and tank B contains milk and water in the ratio of 3 : 1. The total quantity of mixture is 60 litres when $\\frac{1}{5}$ of mixture from tank A and $\\frac{1}{4}$ of mixture from tank B are mixed. The initial quantity of milk in tank A is 40 litres more than the initial\u00a0quantity of water in tank B. What is the initial quantity of water in tank A?<\/p>\n a)\u00a020 litres<\/p>\n b)\u00a024 litres<\/p>\n c)\u00a016 litres<\/p>\n d)\u00a012 litres<\/p>\n e)\u00a0None of the above<\/p>\n 6)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Solution:<\/b><\/p>\n Ratio of milk and water in tank A is 4 : 1 Instructions<\/b><\/p>\n Ravi and kavitha take x ml, y ml of drink which is a mixture of Tonic and Water. The ratio of Tonic to water in Ravi is 3:1 and that of in kavitha’s drink is 9:2. Both pay a total amount of Rs. 1200and the price of each ml is Rs. 20. If Ravi mixes 10ml more\u00a0water in his drink then quantiy of his drink becomes equals to\u00a0 kavitha’s drink<\/p>\n Question 7:\u00a0<\/b>What is the total amount costed for\u00a0Tonic in both Ravi and Kavitha’s drink ?<\/p>\n a)\u00a0845\/-<\/p>\n b)\u00a0756.4\/-<\/p>\n c)\u00a0936.6\/-<\/p>\n d)\u00a0786.8\/-<\/p>\n e)\u00a0990.8\/-<\/p>\n 7)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Solution:<\/b><\/p>\n The ratio of Tonic and water in Ravi’s drink is 3:1<\/p>\n Let this be 3x:x<\/p>\n in Kavitha’s drink is 9:2<\/p>\n let this be 9y :2y<\/p>\n The amount paid by both = 1200 1200\/20 = 60<\/p>\n 3x+x+9y+2y = 60<\/p>\n 4x+11y = 60 ——-(1)<\/p>\n Given that If Ravi mixes 10ml of water in his drink then qty of drink becomes half of kavitha<\/p>\n 4x+10 =1 1y——(2)<\/p>\n solving both equations,<\/p>\n x = 6.25ml y = 3.12ml<\/p>\n so the amount of Tonic and water in Ravi’s drink is 3(6.25) = 18.75<\/p>\n and 6.25mlml<\/p>\n amount of tonic = 18.75ml and amount of water = 6.25ml<\/p>\n The ratio of Tonic and water<\/p>\n in Kavitha’s drink is 9:2<\/p>\n 9y :2y<\/p>\n 9(3.12) = 28.08<\/p>\n 2(3.12) = 6.24<\/p>\n Tonic = 28.08ml Water = 6.24ml<\/p>\n So, the total amount of tonic is 18.75+28.08 =\u00a0 = 46.83<\/p>\n Given that price per ml is Rs. 20<\/p>\n 936.6 rupees<\/p>\n Hence answer is option a<\/p>\n Question 8:\u00a0<\/b>What is the amount of Tonic and water in Kavitha’s drink ?<\/p>\n a)\u00a028.08ml , 6.24ml<\/p>\n b)\u00a08.4ml, 37.8ml<\/p>\n c)\u00a05.5ml, 4ml<\/p>\n d)\u00a04.8ml, 15ml<\/p>\n e)\u00a015ml, 4.8ml<\/p>\n 8)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Solution:<\/b><\/p>\n The ratio of Tonic and water in Ravi’s drink is 3:1<\/p>\n Let this be 3x:x<\/p>\n in Kavitha’s drink is 9:2<\/p>\n let this be 9y :2y<\/p>\n The amount paid by both = 1200 1200\/20 = 60<\/p>\n 3x+x+9y+2y = 60<\/p>\n 4x+11y = 60 ——-(1)<\/p>\n Given that If Ravi mixes 10ml of water in his drink then qty of drink becomes half of kavitha<\/p>\n 4x+10 =1 1y——(2)<\/p>\n solving both equations,<\/p>\n x = 6.25ml y = 3.12ml<\/p>\n The ratio of Tonic and water<\/p>\n in Kavitha’s drink is 9:2<\/p>\n 9y :2y<\/p>\n Tonic = 28.08ml Water = 6.24ml<\/p>\n Hence answer is option a<\/p>\n Question 9:\u00a0<\/b>What is the amount of Tonic and Water in Ravi’s drink ?<\/p>\n a)\u00a018.75 ml, 6.25ml<\/p>\n b)\u00a014.2ml, 9.9ml<\/p>\n c)\u00a015.5ml, 6.4ml<\/p>\n d)\u00a016.4ml, 5.5ml<\/p>\n e)\u00a018.5ml, 4.5ml<\/p>\n 9)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Solution:<\/b><\/p>\n The ratio of Tonic and water in Ravi’s drink is 3:1<\/p>\n Let this be 3x:x<\/p>\n in Kavitha’s drink is 9:2<\/p>\n let this be 9y :2y<\/p>\n The amount paid by both = 1200 1200\/20 = 60<\/p>\n 3x+x+9y+2y = 60<\/p>\n 4x+11y = 60 ——-(1)<\/p>\n Given that\u00a0\u00a0If Ravi mixes 10ml more water in his drink then qty of drink becomes equal to\u00a0 kavitha’s drink<\/p>\n 4x+10 =1 1y——(2)<\/p>\n solving both equations,<\/p>\n x = 6.25ml y = 3.12ml<\/p>\n so the amount of\u00a0\u00a0Tonic and water in Ravi’s drink is 3(6.25) = 18.75ml<\/p>\n and 6.25ml<\/p>\n amount of tonic = 18.75ml and amount of water = 6.25ml<\/p>\n Hence answer is option a<\/p>\n Question 10:\u00a0<\/b>In a drum A, the ratio between the quantity of milk and water is 23:13 respectively. In drum B, the quantity of milk is 28.57% more than the quantity of water. If both the mixture of both of the drums are mixed together with \u2018y\u2019 litres of water, then the ratio of milk and water in the new mixture is 5:4 respectively. Find out the value of \u2018y\u2019. It is assumed that the sum of the quantities of milk from both the drums together is 800 litres.<\/p>\n a)\u00a0180<\/p>\n b)\u00a0240<\/p>\n c)\u00a0160<\/p>\n d)\u00a0140<\/p>\n e)\u00a0Cannot be determined<\/p>\n 10)\u00a0Answer\u00a0(E)<\/strong><\/p>\n Solution:<\/b><\/p>\n It is assumed that the sum of the quantities of milk from both the drums together is 800 litres. Take Free IBPS PO Mock Tests<\/a><\/p>\n Question 11:\u00a0<\/b>An amount was divided among three people such as the ratio between the amount obtained by Anu and Chotu is 3:2 respectively. The amount obtained by Bindu is 83.33% more than the amount obtained by Chotu. The average of the amount obtained by Anu and Bindu is 12000. If the amount will be divided between two people Anu and Bindu such as that Anu got Rs. 2600 less than Bindu, then find out the amount obtained by Anu is how much more than the amount obtained by her earlier.<\/p>\n a)\u00a0Rs. 3900<\/p>\n b)\u00a0Rs. 3500<\/p>\n c)\u00a0Rs. 3000<\/p>\n d)\u00a0Rs. 3200<\/p>\n e)\u00a0None of the above<\/p>\n 11)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Solution:<\/b><\/p>\n When divided among three people \u21d2 Question 12:\u00a0<\/b>In a 50 litres mixture of milk and water, percentage of water is 20%. The milkman sold 10 litres of this mixture and added 32 litres of milk and 24 litres of water in the remaining mixture. What is the percentage of water in the new mixture?<\/p>\n a)\u00a033$\\frac{1}{3}$%<\/p>\n b)\u00a031$\\frac{1}{3}$%<\/p>\n c)\u00a031$\\frac{2}{3}$%<\/p>\n d)\u00a033$\\frac{2}{3}$%<\/p>\n e)\u00a0None of the above<\/p>\n 12)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Solution:<\/b><\/p>\n Total initial mixture = 50 litres Question 13:\u00a0<\/b>An amount of Rs. 4410 was divided among three people Aman, Bhanu and Chandu such as the ratio between the amount obtained by Aman and Chandu is 1:2 respectively. The amount obtained by Bhanu is 25% less than the amount obtained by Aman. Find out the sum of the amount obtained by Bhanu and Chandu.<\/p>\n a)\u00a0Rs. 3520<\/p>\n b)\u00a0Rs. 3234<\/p>\n c)\u00a0Rs. 3300<\/p>\n d)\u00a0Rs. 3410<\/p>\n e)\u00a0None of the above<\/p>\n 13)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Solution:<\/b><\/p>\n The ratio between the amount obtained by Aman and Chandu is 1:2 respectively. Question 14:\u00a0<\/b>In a mixture of 280 litres, the quantity of water is 25% less than the quantity of juice. If 20 litres and \u2018y\u2019 litres of juice and water are added into the initial mixture, then the quantity of juice and water in the new mixture will be 9:8 respectively. Find out the value of \u2018y\u2019.<\/p>\n a)\u00a025<\/p>\n b)\u00a040<\/p>\n c)\u00a050<\/p>\n d)\u00a035<\/p>\n e)\u00a0None of the above<\/p>\n 14)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Solution:<\/b><\/p>\n In a mixture of 280 litres, the quantity of water is 25% less than the quantity of juice. $\\frac{180}{120+y} = \\frac{9}{8}$<\/p>\n $\\frac{20}{120+y} = \\frac{1}{8}$<\/p>\n 160 = 120+y Question 15:\u00a0<\/b>A tank contains a mixture of milk and water in the ratio of 9 : 7 respectively. 32 litres of mixture is taken out and the tank is filled with 90 litres of milk, the ratio between milk and water becomes 2 : 1 respectively. What is the initial quantity of water in the tank?<\/p>\n a)\u00a0210 litres<\/p>\n b)\u00a0180 litres<\/p>\n c)\u00a0280 litres<\/p>\n d)\u00a0140 litres<\/p>\n e)\u00a0150 litres<\/p>\n 15)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Solution:<\/b><\/p>\n Initial ratio of milk and water = 9 : 7<\/p>\n Let the initial quantity of milk and water is 9p and 7p<\/p>\n 32 litres of mixture is taken out. The quantity of milk and water taken out will be in the same ratio 9 : 7.<\/p>\n Quantity of milk taken out = $\\frac{9}{9+7}\\times32$ = 18 litres<\/p>\n Remaining quantity of milk = 9p – 18<\/p>\n Quantity of water taken out = $\\frac{7}{9+7}\\times32$ = 14 litres<\/p>\n Remaining quantity of water = 7p – 14<\/p>\n According to the problem,<\/p>\n $\\frac{9p-18+90}{7p-14}=\\frac{2}{1}$<\/p>\n $9p+72=14p-28$<\/p>\n $5p=100$<\/p>\n $p=20$<\/p>\n $\\therefore$ Initial quantity of water = 7p = 7 x 20 = 140<\/p>\n Hence, the correct answer is Option D<\/p>\n Question 16:\u00a0<\/b>In a mixture, the initial quantity of milk and water is 4:1 respectively. If ‘y\u2019 and (y-15) litres of milk and water are poured into the mixture respectively, then in the mixture the new ratio of milk and water will be 7:2 respectively. If 40 litres of mixture is taken out from the initial mixture and (y-3) and (y-7) litres of milk and water are poured into the mixture respectively, then in the mixture, the new ratio of milk and water will be 49:15 respectively. Find out the value of \u2018y\u2019.<\/p>\n a)\u00a050<\/p>\n b)\u00a045<\/p>\n c)\u00a030<\/p>\n d)\u00a040<\/p>\n e)\u00a0Cannot be determined<\/p>\n 16)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Solution:<\/b><\/p>\n In a mixture, the initial quantity of milk and water is 4:1 respectively. $\\frac{4z-35+y}{z-15+y} = \\frac{49}{15}$ Question 17:\u00a0<\/b>In bucket A, the quantity of milk and water is 4:3 respectively. If 20 litres of milk is poured into the bucket A, then the ratio between the quantity of milk and water will become 3:2 respectively. In bucket B, the quantity of water is 30 litres less than the quantity of water in bucket A. If the total initial quantity of mixture in both the buckets together is 520 litres, then find out the quantity of milk in bucket B.<\/p>\n a)\u00a0110 litres<\/p>\n b)\u00a0120 litres<\/p>\n c)\u00a0140 litres<\/p>\n d)\u00a0180 litres<\/p>\n e)\u00a0None of the above<\/p>\n 17)\u00a0Answer\u00a0(E)<\/strong><\/p>\n Solution:<\/b><\/p>\n In bucket A, the quantity of milk and water is 4:3 respectively. If 20 litres of milk is poured into the bucket A, then the ratio between the quantity of milk and water will become 3:2 respectively. Question 18:\u00a0<\/b>In 2024 litres of the mixture, the ratio between the quantity of milk and water is 5:3 respectively. If (y+44) litres of milk and \u2018y\u2019 litres of water is poured into the mixture, then the ratio between the quantity of milk and water will be 27:16 respectively. Find out the value of (y+8).<\/p>\n a)\u00a049<\/p>\n b)\u00a041<\/p>\n c)\u00a045<\/p>\n d)\u00a047<\/p>\n e)\u00a0None of the above<\/p>\n 18)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Solution:<\/b><\/p>\n In 2024 litres of the mixture, the ratio between the quantity of milk and water is 5:3 respectively. $\\frac{1265+(y+44)}{759+y} = \\frac{27}{16}$<\/p>\n $\\frac{1309+y}{759+y} = \\frac{27}{16}$<\/p>\n 20944+16y = 20493+27y Question 19:\u00a0<\/b>A certain amount of money was divided among three persons P, Q, and R in the ratio 6:4:3 respectively. The amount obtained by P was further divided between his two sons in the ratio 7:5 respectively such that the elder son got more amount than the younger son. If the difference between the amount obtained by the elder son and that of the younger son of P is Rs.1786, then find the difference between the amount obtained by Q and that of R.<\/p>\n a)\u00a0Rs.3572<\/p>\n b)\u00a0Rs.4218<\/p>\n c)\u00a0Rs.1786<\/p>\n d)\u00a0Rs.993<\/p>\n e)\u00a0None of these<\/p>\n 19)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Solution:<\/b><\/p>\n Let the amount obtained by P, Q and R be Rs.6x, Rs.4x and Rs.3x respectively.<\/p>\n Amount obtained by the elder son of P = $\\dfrac{7}{12}\\times6x = Rs.3.5x$<\/p>\n Amount obtained by the younger son of P = 6x – 3.5x = Rs.2.5x.<\/p>\n Given, 3.5x – 2.5x = 1786 Hence, The required difference = 4x – 3x = Rs.1786.<\/p>\n Question 20:\u00a0<\/b>In a jar P, (y-35) litres of mixture is available, where the quantity of water is 63.63% less than the quantity of juice. In another jar Q, \u2018y\u2019 litres of mixture is available, where the quantity of juice is $\\frac{3}{7}$ times more than the quantity of water. If the mixture of both the jars is mixed together, then the quantity of water will be 452 litres. Find out the value of \u2018y\u2019.<\/p>\n a)\u00a0520<\/p>\n b)\u00a0560<\/p>\n c)\u00a0640<\/p>\n d)\u00a0680<\/p>\n e)\u00a0None of the above<\/p>\n 20)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Solution:<\/b><\/p>\n In a jar P, (y-35) litres of mixture is available, where the quantity of water is 63.63% less than the quantity of juice. 68y-2380+105y = 115260 Question 21:\u00a0<\/b>In a \u2018y\u2019 liters of mixture, the quantity of milk is 37.5% more than the quantity of water. If 10 litres of water is added into the mixture, then the ratio between the quantity of milk to water will become 4:3. Find out the difference between the quantity of milk and water in the initial mixture.<\/p>\n a)\u00a0125 liters<\/p>\n b)\u00a0175 liters<\/p>\n c)\u00a0180 liters<\/p>\n d)\u00a0120 liters<\/p>\n e)\u00a0None of the above<\/p>\n 21)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Solution:<\/b><\/p>\n In a \u2018y\u2019 liters of mixture, the quantity of milk is 37.5% more than the quantity of water. $\\frac{11y}{8y + 190} = \\frac{4}{3}$<\/p>\n 33y = 32y + 760 = $\\frac{3}{19}\\times760$<\/p>\n = 120 liters
\nWhich of the following values can fill in the blanks appropriately?
\n(i) 60, 4
\n(ii) 95, 3
\n(iii) 140, 2<\/p>\n
\nFinal quantity of milk = Final quantity of water + $\\frac{4}{7}\\times$Final quantity of water
\nFinal quantity of milk = $\\frac{11}{7}\\times$Final quantity of water
\nRatio of the final quantity of milk and water is 11:7 respectively.<\/p>\n
\n<\/strong>60 litres of mixture is taken and 4 litres of milk is added from the tank.
\nRatio of initial quantity of milk and water = 120 : 80
\n= 3 : 2
\nFinal quantity of milk = 120 – $\\frac{3}{3+2}\\times$60 + 4 = 88 litres
\nFinal quantity of water = 80 – $\\frac{2}{3+2}\\times$60 = 56
\nRatio of final quantity of milk and water = 88 : 56
\n= 11:7
\nGiven values satisfy the conditions of the question.<\/p>\n
\n<\/strong>95 litres of mixture is taken and 3 litres of milk is added from the tank.
\nRatio of initial quantity of milk and water = 120 : 80
\n= 3 : 2
\nFinal quantity of milk = 120 – $\\frac{3}{3+2}\\times$95 + 3 = 66 litres
\nFinal quantity of water = 80 – $\\frac{2}{3+2}\\times$95 = 42
\nRatio of final quantity of milk and water = 66 : 42
\n= 11:7
\nGiven values satisfy the conditions of the question.<\/p>\n
\n<\/strong>140 litres of mixture is taken and 2 litres of milk is added from the tank.
\nRatio of initial quantity of milk and water = 120 : 80
\n= 3 : 2
\nFinal quantity of milk = 120 – $\\frac{3}{3+2}\\times$140 + 2 = 38 litres
\nFinal quantity of water = 80 – $\\frac{2}{3+2}\\times$140 = 24
\nRatio of final quantity of milk and water = 38 : 24
\n= 19:12
\nGiven values do not satisfy the conditions of the question.
\nHence, the correct answer is Option B<\/p>\n
\nIf the number of toffees obtained by C is 40.
\nnumber of toffees obtained by B = 40 of (9\/8) = 45
\nThe ratio between the number of toffees obtained by A and B is 4:3 respectively.
\nnumber of toffees obtained by A = 45 of (4\/3) = 60
\nThe number of toffees obtained by A is 20% less than the number of toffees obtained by D.
\n60 = 80% of the number of toffees obtained by D
\nthe number of toffees obtained by D = 75
\nSum of the number of toffees obtained by A, B and D = 60+45+75
\n= 180
\nHence, option c is the correct answer.<\/p>\n
\nLet the number of chocolates received by employee X = 9p
\nNumber of chocolates received by employee Y = $\\frac{7}{9}\\times$9p = 7p<\/p>\n
\nNumber of chocolates received by employee Z = $\\frac{8}{9}\\times$7p = $\\frac{56}{9}$p<\/p>\n
\n$\\Rightarrow$ $\\frac{9p+7p+\\frac{56}{9}p}{3}$ = 66$\\frac{2}{3}$
\n$\\Rightarrow$ $\\frac{81p+63p+56p}{9\\times3}$ = $\\frac{200}{3}$
\n$\\Rightarrow$ 200p = 200 x 9
\n$\\Rightarrow$ p = 9
\nNumber of chocolates received by employee Z = $\\frac{56}{9}$p
\n= $\\frac{56}{9}\\times$9
\n= 56
\nHence, the correct answer is Option D<\/p>\n
\nLet\u2019s assume the amount obtained by B and C is 13y and 14y respectively.
\nthe average of the amount obtained by C and D is Rs. 4900.
\n$\\frac{14y+\\text{amount obtained by D}}{2} = 4900$
\n14y+amount obtained by D = 9800
\namount obtained by D = (9800-14y)
\nthe amount obtained by A is 25% less than the amount obtained by B
\nthe amount obtained by A = 75% of 13y
\n= 9.75y
\nThe difference between the amount obtained by A and D is Rs. 300.
\n9.75y-(9800-14y) = 300
\n9.75y-9800+14y = 300
\n23.75y = 9800+300 = 10100
\ny = 425.263158 Eq.(i)
\nOr (9800-14y)-9.75y = 300
\n9800-14y-9.75y = 300
\n9800-300 = 23.75y
\n23.75y = 9500
\ny = 400 Eq.(ii)
\nAverage of the amount obtained by all the four people = $\\frac{9.75y+13y+14y+(9800-14y)}{4}$
\n= $\\frac{22.75y+9800}{4}$
\n= (5.6875y+2450) Eq.(iii)
\nPut the value of \u2018y\u2019 from Eq.(i) to the above given equation.
\n= (5.6875\\times425.263158+2450)
\nAfter solving this, we will get a fractional value which is not available in any of the options. So the value of \u2018y\u2019 which is given in Eq.(i) is not possible.
\nPut the value of \u2018y\u2019 from Eq.(ii) to the equation Eq.(iii).
\n= $(5.6875\\times400+2450)$
\n= 2275+2450
\n= 4725
\nHence, option c is the correct answer.<\/p>\n
\nThe amount obtained by Q is 11.11% less than the amount obtained by P.
\nAmount obtained by Q = $\\frac{8}{9}$ of the amount obtained by P
\n= $\\frac{8}{9}\\times$72p
\n= 64p
\nThe amount obtained by P is 14.28% more than the amount obtained by R.
\nAmount obtained by P = $\\frac{8}{7}$ of the amount obtained by R
\n72p = $\\frac{8}{7}\\times$Amount obtained by R
\nAmount obtained by R = 63p
\nTotal amount divided among them is \u20b91194
\n72p + 64p + 63p 1194
\n199p = 1194
\np = 6
\nAmount obtained by R = 63p
\n= 63(6)
\n= \u20b9378
\nHence, the correct answer is Option D<\/p>\n
\nLet the quantity of milk and water in tank A is 4p and p respectively.
\nRatio of milk and water in tank B is 3 : 1
\nLet the quantity of milk and water in tank B is 3q and q respectively.
\nThe total quantity of mixture is 60 litres when $\\frac{1}{5}$ of mixture from tank A and $\\frac{1}{4}$ of mixture from tank B are mixed.
\n$\\Rightarrow$ $\\frac{1}{5}$(4p+p) + $\\frac{1}{4}$(3q+q) = 60
\n$\\Rightarrow$ p + q = 60\u2026\u2026\u2026.(1)
\nThe quantity of milk in tank A is 40 litres more than quantity of water in tank B.
\n$\\Rightarrow$ 4p = q + 40\u2026….(2)
\nAdding (1) and (2),
\n5p + q = q + 100
\np = 20
\n$\\therefore$ Initial quantity of water in tank A = p = 20 litres
\nHence, the correct answer is Option A<\/p>\n
\nPrice of each ml = 20<\/p>\n
\nPrice of each ml = 20<\/p>\n
\nPrice of each ml = 20<\/p>\n
\nIf both the mixture of both of the drums are mixed together with \u2018y\u2019 litres of water, then the ratio of milk and water in the new mixture is 5:4 respectively.
\n5c = 800
\nc = 160
\n4c = 640
\nTotal mixture = 9c = 1440
\nIn a drum A, the ratio between the quantity of milk and water is 23:13 respectively.
\nLet\u2019s assume the quantity of milk and water in drum A is 23a and 13a respectively.
\nIn drum B, the quantity of milk is 28.57% more than the quantity of water.
\nLet\u2019s assume the quantity of water in drum B is 7b.
\nquantity of milk in drum B = 7b of (9\/7) = 9b
\n13a+7b+y = 640
\n23a+9b = 800
\nNow further, we cannot solve it. Because one equation has three variables and another one has two variables. So we cannot determine the answer from the given information.
\nHence, option e is the correct answer.<\/p>\n
\n<\/b>An amount was divided among three people such as the ratio between the amount obtained by Anu and Chotu is 3:2 respectively.
\nAnu : Chotu \u21d2 3:2 Eq.(i)
\nThe amount obtained by Bindu is 83.33% more than the amount obtained by Chotu.
\namount obtained by Bindu = (11\/6) amount obtained by Chotu
\nBindu : Chotu \u21d2 11:6 Eq.(ii)
\nFrom Eq.(i) and Eq.(ii).
\nAnu : Bindu : Chotu \u21d2 18:22:12
\n\u21d2 9:11:6
\nThe average of the amount obtained by Anu and Bindu is 12000.
\n9y+11y = $12000\\times2$ = 24000
\n20y = 24000
\ny = 1200
\nTotal amount = 9y+11y+6y = 26y = $26\\times1200$
\n= 31200
\nWhen divided between two people \u21d2 <\/b>
\nBindu + Anu = 31200 Eq.(iii)
\nIf the amount will be divided between two people Anu and Bindu such as that Anu got Rs. 2600 less than Bindu.
\nAnu = Bindu – 2600
\nBindu – Anu = 2600 Eq.(iv)
\nAdd Eq.(iii) and Eq.(iv).
\n2Bindu = 31200+2600 = 33800
\nBindu = 16900
\nPut the above value in Eq.(iv).
\n16900 – Anu = 2600
\nAnu = 16900-2600
\n= 14300
\nAmount obtained by Anu is more than the amount obtained by her earlier = 14300-$1200\\times9$
\n= 14300-10800
\n= Rs. 3500
\nHence, option b is the correct answer.<\/p>\n
\nMilkman sold 10 litres of this mixture
\nRemaining mixture = 40 litres
\nPercentage of water = 20%
\nQuantity of water in the remaining mixture = $\\dfrac{20}{100}\\times$40 = 8 litres
\nQuantity of milk in the remaining mixture = 40 – 8 = 32 litres
\nAfter adding 32 litres of milk and 24 litres of water in the remaining mixture,
\nQuantity of milk in the new mixture = 32 + 32 = 64 litres
\nQuantity of water in the new mixture = 8 + 24 = 32 litres
\n$\\therefore$ Percentage of water in the new mixture = $\\dfrac{32}{64+32}\\times$100
\n= $\\dfrac{32}{96}\\times$100
\n= 33$\\frac{1}{3}$%
\nHence, the correct answer is Option A<\/p>\n
\nLet\u2019s assume the amount obtained by Aman and Chandu is y and 2y respectively.
\nThe amount obtained by Bhanu is 25% less than the amount obtained by Aman.
\namount obtained by Bhanu = \u00be of y = 0.75y
\nAn amount of Rs. 4410 was divided among three people Aman, Bhanu and Chandu.
\ny+0.75y+2y = 4410
\n3.75y = 4410
\ny = 1176
\nSum of the amount obtained by Bhanu and Chandu = 0.75y+2y
\n= 2.75y
\n= $2.75\\times1176$
\n= Rs. 3234
\nHence, option b is the correct answer.<\/p>\n
\nquantity of water = 75% of quantity of juice
\nquantity of juice : quantity of water \u21d2 4:3
\nquantity of juice = 280 of (4\/7) = 160 litres
\nquantity of water = 280 of (3\/7) = 120 litres
\nIf 20 litres and \u2018y\u2019 litres of juice and water are added into the initial mixture, then the quantity of juice and water in the new mixture will be 9:8 respectively.
\n$\\frac{160+20}{120+y} = \\frac{9}{8}$<\/p>\n
\ny = 160-120 = 40
\nHence, option b is the correct answer.<\/p>\n
\nLet\u2019s assume the initial quantity of milk and water in the mixture is 4z and z respectively.
\nIf \u2018y\u2019 and (y-15) litres of milk and water are poured into the mixture respectively, then in the mixture the new ratio of milk and water will be 7:2 respectively.
\n$\\frac{4z+y}{z+(y-15)} = \\frac{7}{2}$
\n8z+2y = 7z+7y-105
\nz-5y = -105
\n5y-z = 105
\nz = 5y-105 Eq.(i)
\nIf 40 litres of mixture is taken out from the initial mixture and (y-3) and (y-7) itres of milk and water are poured into the mixture respectively, then in the mixture the new ratio of milk and water will be 49:15 respectively.
\n$\\frac{4z-32+(y-3)}{z-8+(y-7)} = \\frac{49}{15}$<\/p>\n
\n60z-525+15y = 49z-735+49y
\n11z-34y = -735+525
\n34y-11z = 210 Eq.(ii)
\nPut Eq.(i) in Eq.(ii).
\n34y-11(5y-105) = 210
\n34y-55y+1155 = 210
\n21y = 945
\ny = 45
\nHence, option b is the correct answer.<\/p>\n
\n$\\frac{4y+20}{3y} = \\frac{3}{2}$
\n8y+40 = 9y
\n9y-8y = 40
\ny = 40
\nInitial quantity of milk in bucket A = 4y = 160
\nQuantity of water in bucket A = 3y = 120
\nIn bucket B, the quantity of water is 30 litres less than the quantity of water in bucket A.
\nQuantity of water in bucket B = 120-30 = 90
\nIf the total initial quantity of mixture in both the buckets together is 520 litres.
\nInitial quantity of milk in bucket A + Quantity of water in bucket A + Quantity of milk in bucket B + Quantity of water in bucket B = 520
\n160+120+Quantity of milk in bucket B+90 = 520
\nQuantity of milk in bucket B+370 = 520
\nQuantity of milk in bucket B = 520-370 = 150 litres
\nHence, option e is the correct answer.<\/p>\n
\nInitial quantity of milk = $\\frac{5}{8}\\times2024$
\n= 1265
\nInitial quantity of water = $\\frac{3}{8}\\times2024$
\n= 759
\nIf (y+44) litres of milk and \u2018y\u2019 litres of water is poured into the mixture, then the ratio between the quantity of milk and water will be 27:16 respectively.<\/p>\n
\n27y-16y = 20944-20493
\n11y = 451
\ny = 41
\nvalue of (y+8) = 41+8 = 49
\nHence, option a is the correct answer.<\/p>\n
\nx = 1786.<\/p>\n
\nIn a jar P, the ratio between the quantities of juice and water is 11:4 respectively.
\nIn another jar Q, \u2018y\u2019 litres of mixture is available, where the quantity of juice is $\\frac{3}{7}$ times more than the quantity of water.
\nIn a jar Q, the ratio between the quantities of juice and water is 10:7 respectively.
\nIf the mixture of both the jars is mixed together, then the quantity of water will be 452 litres.
\n(4\/15) of (y-35) + (7\/17) of y = 452<\/p>\n
\n173y = 115260+2380 = 117640
\ny = 680
\nHence, option d is the correct answer.<\/p>\n
\nThe ratio between the initial quantity of milk and water is 11:8 respectively.
\nIf 10 litres of water is added into the mixture, then the ratio between the quantity of milk to water will become 4:3.
\n$\\frac{\\frac{11}{19}y}{\\frac{8}{19}y + 10} = \\frac{4}{3}$<\/p>\n
\ny = 760
\nDifference between the quantity of milk and water in the initial mixture = $\\frac{11}{19}y – \\frac{8}{19}y$
\n= $\\frac{3}{19}y$<\/p>\n
\nHence, option d is the correct answer.<\/p>\n