Coins and Weights is one of the key topics in the CAT LRDI section<\/strong>. If you’re weak in Coins and Weights, make sure you are at least aware of the basic concepts of solving and representing these sets. You can learn all the important concepts in Coins and Weights LRDI questions for CAT here<\/span><\/strong><\/a>. You can check out these CAT Coins and Weights questions from the CAT Previous year’s papers<\/strong><\/span><\/a>.\u00a0<\/span><\/p>\n Also, if you don’t have enough time, learn only the basics of Coins and Weights and practice a few easy sets from the topic. <\/span>This post will look at important Coins and Weights questions<\/strong> in the CAT LRDI section. These are a good source of practice for CAT preparation; If you want to practice these questions, you can download this CAT Coins and Weights<\/strong> Questions<\/strong> PDF <\/strong>along with the detailed solutions (and video solutions) below, which is completely Free.<\/p>\n Download LR Coins and Weights Questions for CAT<\/a><\/p>\n Enroll for CAT 2022 Crash Course<\/a><\/p>\n Instructions<\/b>DIRECTIONS for the following two questions: These questions are based on the situation given below: Question 1:\u00a0<\/b>If Q gets fewer coins than R, then which one of the following is not necessarily true?<\/p>\n a)\u00a0P and Q together get at least four coins.<\/p>\n b)\u00a0Q and S together get at least four coins.<\/p>\n c)\u00a0R and S together get at least five coins.<\/p>\n d)\u00a0P and R together get at least five coins.<\/p>\n 1)\u00a0Answer\u00a0(A)<\/strong><\/p>\n View Video Solution<\/a><\/p>\n Solution:<\/b><\/p>\n From the given passage, it is given that Q>P, R>S.<\/p>\n When R = 4 and S = 3, then Q = 2 and P = 1.<\/p>\n P+Q = 2+1 = 3 which contradicts statement 1.<\/p>\n Question 2:\u00a0<\/b>If R gets at least two more coins than S, then which one of the following is necessarily true?<\/p>\n a)\u00a0Q gets at least two more coins than S.<\/p>\n b)\u00a0Q gets more coins than P.<\/p>\n c)\u00a0P gets more coins than S.<\/p>\n d)\u00a0P and Q together get at least five coins.<\/p>\n 2)\u00a0Answer\u00a0(B)<\/strong><\/p>\n View Video Solution<\/a><\/p>\n Solution:<\/b><\/p>\n From the given passage, it is given that Q>P, R>S. Now it is given that R is greater than or equal to S+2. Option B will still remain true because it is given that Q>P.<\/p>\n Question 3:\u00a0<\/b>If the number of coins distributed to Q is twice the number distributed to P then which one of the following is necessarily true?<\/p>\n a)\u00a0R gets an even number of coins.<\/p>\n b)\u00a0R gets an odd number of coins.<\/p>\n c)\u00a0S gets an even number of coins.<\/p>\n d)\u00a0S gets an odd number of coins.<\/p>\n 3)\u00a0Answer\u00a0(D)<\/strong><\/p>\n View Video Solution<\/a><\/p>\n Solution:<\/b><\/p>\n From the given passage, it is given that Q>P, R>S.<\/p>\n According to the information Q = 2 when P = 1 or Q = 4 when P = 2.<\/p>\n In first case R = 4 and S = 3 and in the second case R = 3 and S = 1.<\/p>\n In both the instances S is odd.<\/p>\n Instructions<\/b>Direction for the following three questions: Answer the questions based on the following information. Question 4:\u00a0<\/b>If A collected 54 coins and B collected two more coins than twice the number of coins collected by C, then the number of coins collected by B could be<\/p>\n a)\u00a028<\/p>\n b)\u00a020<\/p>\n c)\u00a026<\/p>\n d)\u00a022<\/p>\n 4)\u00a0Answer\u00a0(D)<\/strong><\/p>\n View Video Solution<\/a><\/p>\n Solution:<\/b><\/p>\n Number of coins with A = 54<\/p>\n Number of coins with B = 2x+2<\/p>\n Number of coins with C = x<\/p>\n Number of coins with D = y<\/p>\n 54+3x+2+y = 100<\/p>\n 3x+y = 44<\/p>\n If 2x+2 = 28, then x = 13 and y = 5 which is not possible.<\/p>\n If 2x+2 = 20, then x = 9 which is not possible.<\/p>\n If 2x+2 = 26, then x = 12 and y = 8 which is not possible<\/p>\n If 2x+2 = 22, then x = 10 and y = 14 which is feasible<\/p>\n Question 5:\u00a0<\/b>If A collected 54 coins, then the difference in the number of coins between the one who collected maximum number of coins and the one who collected the second highest number of coins must be at least<\/p>\n a)\u00a012<\/p>\n b)\u00a024<\/p>\n c)\u00a030<\/p>\n d)\u00a0None of these<\/p>\n 5)\u00a0Answer\u00a0(C)<\/strong><\/p>\n View Video Solution<\/a><\/p>\n Solution:<\/b><\/p>\n If A collected 54 coins, remaining will be 46. Checkout: CAT Free Practice Questions and Videos<\/strong><\/a><\/em><\/p>\n Question 6:\u00a0<\/b>The maximum number of coins collected by any one of them cannot exceed<\/p>\n a)\u00a064<\/p>\n b)\u00a036<\/p>\n c)\u00a054<\/p>\n d)\u00a0None of these<\/p>\n 6)\u00a0Answer\u00a0(A)<\/strong><\/p>\n View Video Solution<\/a><\/p>\n Solution:<\/b><\/p>\n As least number of coin, one can have is 10 Instructions<\/b>In a game played by two people there were initially N match sticks kept on the table. A move in the game consists of a player removing either one or two matchsticks from the table. The one who takes the last matchstick loses. Players make moves alternately. The player who will make the first move is A. The other player is B.<\/p>\n Question 7:\u00a0<\/b>The largest of N (less than 50) that ensures a win for B is<\/p>\n a)\u00a046<\/p>\n b)\u00a047<\/p>\n c)\u00a048<\/p>\n d)\u00a049<\/p>\n 7)\u00a0Answer\u00a0(D)<\/strong><\/p>\n View Video Solution<\/a><\/p>\n Solution:<\/b><\/p>\n When total matchstick is 1, B will surely win as A is the one who is picking up matchstick first.<\/p>\n When total matchstick is 2, A will surely win as A will pick one matchstick then B has to pick last one.<\/p>\n When total matchstick is 3, A will surely win as he takes up a strategy so that B will have last matchstick to pick up. So A will pick 2 matchstick.<\/p>\n When total matchstick is 4, B will surely win as if A picks up one matchstick, remaining matchsticks will be 3 and we know that when total 3 matchsticks are there then the one, who is picking up matchstick first, is winning surely.<\/p>\n When total matchstick is 5, A will surely win as he takes up a strategy so that B will have last matchstick to pick up. So A will pick 1 matchstick first, then 4 matchsticks will be there and we know that the one, who picks up matchstick second now, will win. Hence A will win.<\/p>\n When total matchstick is 6, A will surely win either he takes up a strategy so that B will have last matchstick to pick up. So A will pick 2 matchstick first, then 4 matchsticks will be there and we know that the one, who picks up matchstick second now, will win. Hence A will win.<\/p>\n Hence it is making a pattern when number of matchsticks are 1,4,7,10……N then B is winning the game.<\/p>\n So largest value of N (less than 50) where B will win, is 49.<\/p>\n Question 8:\u00a0<\/b>The smallest value of N (greater than 5) that ensures a win for B is<\/p>\n a)\u00a07<\/p>\n b)\u00a06<\/p>\n c)\u00a010<\/p>\n d)\u00a08<\/p>\n
\nTen coins are distributed among four people P, Q, R, S such that one of them gets one coin, another gets two coins, the third gets three coins and the fourth gets four coins. It is known that Q gets more coins than P, and S gets fewer coins than R.<\/p>\n
\nA, B, C and D collected one-rupee coins following the given pattern.
\nTogether they collected 100 coins.
\nEach one of them collected even number of coins.
\nEach one of them collected at least 10 coins.
\nNo two of them collected the same number of coins.<\/p>\n
\nNow B,C,D must have atleast 10,12,14 coins
\nSo remaining coins will be 10
\nSo difference between maximum and second maximum should be least when second highest will be as maximum as possible.
\nI.e. difference = 54- (14+10) = 30<\/p>\n
\nAnd no two of them possess same number of coins, hence for having maximum number of coins to one person, the distribution of coins will be = 10,12,14,64
\nmaximum no. of coins = 64<\/p>\n