Here you can download a free Mixture and Alligations questions PDF with answers for IBPS PO and IBPS RRB PO 2022 by Cracku. These are some tricky questions in the IBPS PO and IBPS RRB PO 2022 exam that you need to find the Mixture and Alligations for the given questions. These questions will help you to do practice and solve the Mixture and Alligations questions in the IBPS PO and IBPS RRB PO exams. Utilize this best PDF practice set<\/strong> which is included answers in detail. Click on the below link to download the Mixture and Alligations MCQ<\/strong> PDF for IBPS PO and IBPS RRB PO 2022 for free.<\/p>\n Download Mixture and Alligations Questions for IBPS RRB and PO Prelims<\/a><\/p>\n Download IBPS PO Previous Papers<\/a><\/p>\n Question 1:\u00a0<\/b>In a mixture, the quantity of water is 20% less than the quantity of juice. When 90 liters of mixture is taken out and 70 liters of water is added into it, then the quantity of juice will be 11.11% more than the quantity of water. Find out the initial quantity of water in the mixture.<\/p>\n a)\u00a0750 liters<\/p>\n b)\u00a0600 liters<\/p>\n c)\u00a0500 liters<\/p>\n d)\u00a0800 liters<\/p>\n e)\u00a0450 liters<\/p>\n 1)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Solution:<\/b><\/p>\n In a mixture, the quantity of water is 20% less than the quantity of juice. Question 2:\u00a0<\/b>A tank contains 120 litres of milk and 80 litres of water. If __ litres of mixture is taken out from the tank and __ litres of milk is added to the tank then the final quantity of milk is 57.14% more than the final quantity of water. a)\u00a0Only (ii) and (iii)<\/p>\n b)\u00a0Only (i) and (ii)<\/p>\n c)\u00a0All (i), (ii) and (iii)<\/p>\n d)\u00a0Only (iii)<\/p>\n e)\u00a0Only (i) and (iii)<\/p>\n 2)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Solution:<\/b><\/p>\n The final quantity of milk is 57.14% more than the final quantity of water. (i) 60, 4 (ii) 95, 3 (iii) 140, 2 Question 3:\u00a0<\/b>There are two tanks A and B which contain a mixture of milk and water. Tank A contains milk and water in the ratio of 4 : 1 and tank B contains milk and water in the ratio of 3 : 1. The total quantity of mixture is 60 litres when $\\frac{1}{5}$ of mixture from tank A and $\\frac{1}{4}$ of mixture from tank B are mixed. The initial quantity of milk in tank A is 40 litres more than the initial\u00a0quantity of water in tank B. What is the initial quantity of water in tank A?<\/p>\n a)\u00a020 litres<\/p>\n b)\u00a024 litres<\/p>\n c)\u00a016 litres<\/p>\n d)\u00a012 litres<\/p>\n e)\u00a0None of the above<\/p>\n 3)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Solution:<\/b><\/p>\n Ratio of milk and water in tank A is 4 : 1 Question 4:\u00a0<\/b>In a 50 litres mixture of milk and water, percentage of water is 20%. The milkman sold 10 litres of this mixture and added 32 litres of milk and 24 litres of water in the remaining mixture. What is the percentage of water in the new mixture?<\/p>\n a)\u00a033$\\frac{1}{3}$%<\/p>\n b)\u00a031$\\frac{1}{3}$%<\/p>\n c)\u00a031$\\frac{2}{3}$%<\/p>\n d)\u00a033$\\frac{2}{3}$%<\/p>\n e)\u00a0None of the above<\/p>\n 4)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Solution:<\/b><\/p>\n Total initial mixture = 50 litres Question 5:\u00a0<\/b>In a mixture of 280 litres, the quantity of water is 25% less than the quantity of juice. If 20 litres and \u2018y\u2019 litres of juice and water are added into the initial mixture, then the quantity of juice and water in the new mixture will be 9:8 respectively. Find out the value of \u2018y\u2019.<\/p>\n a)\u00a025<\/p>\n b)\u00a040<\/p>\n c)\u00a050<\/p>\n d)\u00a035<\/p>\n e)\u00a0None of the above<\/p>\n 5)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Solution:<\/b><\/p>\n In a mixture of 280 litres, the quantity of water is 25% less than the quantity of juice. $\\frac{180}{120+y} = \\frac{9}{8}$<\/p>\n $\\frac{20}{120+y} = \\frac{1}{8}$<\/p>\n 160 = 120+y Question 6:\u00a0<\/b>A tank contains a mixture of milk and water in the ratio of 9 : 7 respectively. 32 litres of mixture is taken out and the tank is filled with 90 litres of milk, the ratio between milk and water becomes 2 : 1 respectively. What is the initial quantity of water in the tank?<\/p>\n a)\u00a0210 litres<\/p>\n b)\u00a0180 litres<\/p>\n c)\u00a0280 litres<\/p>\n d)\u00a0140 litres<\/p>\n e)\u00a0150 litres<\/p>\n 6)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Solution:<\/b><\/p>\n Initial ratio of milk and water = 9 : 7<\/p>\n Let the initial quantity of milk and water is 9p and 7p<\/p>\n 32 litres of mixture is taken out. The quantity of milk and water taken out will be in the same ratio 9 : 7.<\/p>\n Quantity of milk taken out = $\\frac{9}{9+7}\\times32$ = 18 litres<\/p>\n Remaining quantity of milk = 9p – 18<\/p>\n Quantity of water taken out = $\\frac{7}{9+7}\\times32$ = 14 litres<\/p>\n Remaining quantity of water = 7p – 14<\/p>\n According to the problem,<\/p>\n $\\frac{9p-18+90}{7p-14}=\\frac{2}{1}$<\/p>\n $9p+72=14p-28$<\/p>\n $5p=100$<\/p>\n $p=20$<\/p>\n $\\therefore$ Initial quantity of water = 7p = 7 x 20 = 140<\/p>\n Hence, the correct answer is Option D<\/p>\n Question 7:\u00a0<\/b>In a mixture, the initial quantity of milk and water is 4:1 respectively. If ‘y\u2019 and (y-15) litres of milk and water are poured into the mixture respectively, then in the mixture the new ratio of milk and water will be 7:2 respectively. If 40 litres of mixture is taken out from the initial mixture and (y-3) and (y-7) litres of milk and water are poured into the mixture respectively, then in the mixture, the new ratio of milk and water will be 49:15 respectively. Find out the value of \u2018y\u2019.<\/p>\n a)\u00a050<\/p>\n b)\u00a045<\/p>\n c)\u00a030<\/p>\n d)\u00a040<\/p>\n e)\u00a0Cannot be determined<\/p>\n 7)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Solution:<\/b><\/p>\n In a mixture, the initial quantity of milk and water is 4:1 respectively. $\\frac{4z-35+y}{z-15+y} = \\frac{49}{15}$ Question 8:\u00a0<\/b>In 2024 litres of the mixture, the ratio between the quantity of milk and water is 5:3 respectively. If (y+44) litres of milk and \u2018y\u2019 litres of water is poured into the mixture, then the ratio between the quantity of milk and water will be 27:16 respectively. Find out the value of (y+8).<\/p>\n a)\u00a049<\/p>\n b)\u00a041<\/p>\n c)\u00a045<\/p>\n d)\u00a047<\/p>\n e)\u00a0None of the above<\/p>\n 8)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Solution:<\/b><\/p>\n In 2024 litres of the mixture, the ratio between the quantity of milk and water is 5:3 respectively. $\\frac{1265+(y+44)}{759+y} = \\frac{27}{16}$<\/p>\n $\\frac{1309+y}{759+y} = \\frac{27}{16}$<\/p>\n 20944+16y = 20493+27y Question 9:\u00a0<\/b>In a jar P, (y-35) litres of mixture is available, where the quantity of water is 63.63% less than the quantity of juice. In another jar Q, \u2018y\u2019 litres of mixture is available, where the quantity of juice is $\\frac{3}{7}$ times more than the quantity of water. If the mixture of both the jars is mixed together, then the quantity of water will be 452 litres. Find out the value of \u2018y\u2019.<\/p>\n a)\u00a0520<\/p>\n b)\u00a0560<\/p>\n c)\u00a0640<\/p>\n d)\u00a0680<\/p>\n e)\u00a0None of the above<\/p>\n 9)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Solution:<\/b><\/p>\n In a jar P, (y-35) litres of mixture is available, where the quantity of water is 63.63% less than the quantity of juice. 68y-2380+105y = 115260 Question 10:\u00a0<\/b>In a mixture, the ratio between the quantities of milk and water is 5:7 respectively. If 22 litres of water is poured into the mixture, then the ratio between the quantities of milk and water will be 2:3 respectively. Find out the initial quantity of mixture.<\/p>\n a)\u00a0652 litres<\/p>\n b)\u00a0504 litres<\/p>\n c)\u00a0528 litres<\/p>\n d)\u00a0616 litres<\/p>\n e)\u00a0None of the above<\/p>\n 10)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Solution:<\/b><\/p>\n In a mixture, the ratio between the quantities of milk and water is 5:7 respectively. 15y = 14y+44 Take Free IBPS PO Mock Tests<\/a><\/p>\n Question 11:\u00a0<\/b>In a \u2018y\u2019 liters of mixture, the quantity of milk is 37.5% more than the quantity of water. If 10 litres of water is added into the mixture, then the ratio between the quantity of milk to water will become 4:3. Find out the difference between the quantity of milk and water in the initial mixture.<\/p>\n a)\u00a0125 liters<\/p>\n b)\u00a0175 liters<\/p>\n c)\u00a0180 liters<\/p>\n d)\u00a0120 liters<\/p>\n e)\u00a0None of the above<\/p>\n 11)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Solution:<\/b><\/p>\n In a \u2018y\u2019 liters of mixture, the quantity of milk is 37.5% more than the quantity of water. $\\frac{11y}{8y + 190} = \\frac{4}{3}$<\/p>\n 33y = 32y + 760 = $\\frac{3}{19}\\times760$<\/p>\n = 120 liters Question 12:\u00a0<\/b>In a \u2018y\u2019 litres of mixture, the ratio between the quantities of milk and water is 11:7 respectively. If 17 litres and 49 litres of milk and water is poured into the mixture, then the ratio between the quantities of milk and water will be 7:5 respectively. Find out the value of \u2018y\u2019.<\/p>\n a)\u00a0792<\/p>\n b)\u00a0774<\/p>\n c)\u00a0756<\/p>\n d)\u00a0738<\/p>\n e)\u00a0None of the above<\/p>\n 12)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Solution:<\/b><\/p>\n $\\frac{\\frac{11}{18}y + 17}{\\frac{7}{18}y + 49} = \\frac{7}{5}$<\/p>\n $\\frac{11y + 306}{7y + 882} = \\frac{7}{5}$<\/p>\n 55y + 1530 = 49y + 6174 Question 13:\u00a0<\/b>There are two drums A and B having (y-75) litres and \u2018y\u2019 litres of mixture respectively. The quantity of juice in drum A is 12.5% less than the quantity of water in the same drum. In drum B, the ratio between the quantity of juice and water is 11:7 respectively. If the difference between the quantity of water in both the drums is 64 litres, then find out the quality of juice in drum A.<\/p>\n a)\u00a0316 litres<\/p>\n b)\u00a0256 litres<\/p>\n c)\u00a0331 litres<\/p>\n d)\u00a0301 litres<\/p>\n e)\u00a0None of the above<\/p>\n 13)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Solution:<\/b><\/p>\n The quantity of juice in drum A is 12.5% less than the quantity of water in the same drum. $\\frac{8y}{15} – \\frac{7y}{18} = 64+40 = 104$<\/p>\n $\\frac{48y}{90} – \\frac{35y}{90} = 104$<\/p>\n $\\frac{13y}{90} = 104$<\/p>\n y = 720 litres Question 14:\u00a0<\/b>In a mixture of milk and water, the quantity of water is $\\frac{4}{35}$ times less than the quantity of milk. If \u2018y\u2019 litres of milk and (y+10) litres of water is poured into the mixture, then the quantity of milk will be 11.11% more than the quantity of water. If the initial quantity of water is 775 litres, then find out the value of \u2018y\u2019.<\/p>\n a)\u00a015<\/p>\n b)\u00a025<\/p>\n c)\u00a010<\/p>\n d)\u00a020<\/p>\n e)\u00a0None of the above<\/p>\n 14)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Solution:<\/b><\/p>\n In a mixture of milk and water, the quantity of water is $\\frac{4}{35}$ times less than the quantity of milk. $\\frac{875 + y}{785 + y} = \\frac{10}{9}$<\/p>\n 7875 + 9y = 7850 + 10y Question 15:\u00a0<\/b>In a drum P, \u2018z\u2019 litres of mixture is available where the quantity of juice and water is 3:5 respectively. In another drum Q, (z-240) litres of mixture is available where the quantity of juice and water is 7:4 respectively. If the total quantity of juice from both the drums together is 980 litres, then find out the value of \u2018z\u2019.<\/p>\n a)\u00a01250<\/p>\n b)\u00a01040<\/p>\n c)\u00a01160<\/p>\n d)\u00a01080<\/p>\n e)\u00a01120<\/p>\n 15)\u00a0Answer\u00a0(E)<\/strong><\/p>\n Solution:<\/b><\/p>\n $\\frac{3}{8} \\times z+ \\frac{7}{11} \\times (z-240) = 980$<\/p>\n $\\frac{3z}{8} + \\frac{7z}{11} – \\frac{1680}{11} = 980$<\/p>\n $\\frac{33z}{88} + \\frac{56z}{88} = 980 + \\frac{1680}{11}$<\/p>\n $\\frac{89z}{88} = \\frac{1680 + 10780}{11}$<\/p>\n $\\frac{89z}{88} = \\frac{12460}{11}$<\/p>\n $\\frac{89z}{8} = \\frac{12460}{1}$<\/p>\n $z = 140\\times8 = 1120$ Question 16:\u00a0<\/b>In 820 litres of a mixture, the ratio between the quantities of milk and water is 4:1 respectively. If 40 litres of mixture is taken out and some quantity of water is added into the mixture, then the ratio between the quantities of milk and water will be 3:1 respectively. Find out the quantity of water which was added in the mixture.<\/p>\n a)\u00a050 litres<\/p>\n b)\u00a056 litres<\/p>\n c)\u00a044 litres<\/p>\n d)\u00a048 litres<\/p>\n e)\u00a052 litres<\/p>\n 16)\u00a0Answer\u00a0(E)<\/strong><\/p>\n Solution:<\/b><\/p>\n In a 820 litres of mixture, the ratio between the quantities of milk and water is 4:1 respectively. $\\frac{624}{156+y} = \\frac{3}{1}$<\/p>\n 156+y = 208 Question 17:\u00a0<\/b>In a bucket P, 847 litres of mixture is available, where the ratio between the quantities of juice and water is 5:2 respectively. Another bucket Q is having 195 litres of juice and the remaining quantity is water. If the mixture of both buckets is poured into a big bucket R, then the total quantity of water in this bucket will be 31.25% of the total quantity of juice in this bucket. Find out the initial quantity of water in the bucket Q.<\/p>\n a)\u00a024 litres<\/p>\n b)\u00a06 litres<\/p>\n c)\u00a018 litres<\/p>\n d)\u00a012 litres<\/p>\n e)\u00a08 litres<\/p>\n 17)\u00a0Answer\u00a0(E)<\/strong><\/p>\n Solution:<\/b><\/p>\n In a bucket P, 847 litres of mixture is available, where the ratio between the quantities of juice and water is 5:2 respectively. $\\frac{800}{242+y} = \\frac{16}{5}$<\/p>\n $\\frac{50}{242+y} = \\frac{1}{5}$<\/p>\n 250 = 242+y Question 18:\u00a0<\/b>In a 765 litres of mixture, the quantity of milk is 20% less than the quantity of water. If \u2018y\u2019 litres of milk is poured into the mixture, the ratio between quantity of milk and water will be 16:17 respectively, then find out the value \u2018y\u2019.<\/p>\n a)\u00a045<\/p>\n b)\u00a060<\/p>\n c)\u00a090<\/p>\n d)\u00a075<\/p>\n e)\u00a0None of the above<\/p>\n 18)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Solution:<\/b><\/p>\n In a 765 litres of mixture, the quantity of milk is 20% less than the quantity of water. Initial quantity of water = $\\frac{5}{9}\\times765$ = 425 litres $\\frac{340+y}{25} = 16$<\/p>\n 340+y = 400 Question 19:\u00a0<\/b>In a mixture, the quantity of juice and water are in the ratio of 5:7 respectively. If 18 litres of juice is poured into the mixture, then the quantity of juice in the new mixture will be 25% less than the quantity of water in the new mixture. Find out the quantity of water in the mixture.<\/p>\n a)\u00a0637 litres<\/p>\n b)\u00a0560 litres<\/p>\n c)\u00a0504 litres<\/p>\n d)\u00a0651 litres<\/p>\n e)\u00a0None of the above<\/p>\n 19)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Solution:<\/b><\/p>\n In a mixture, the quantity of juice and water are in the ratio of 5:7 respectively. 20y+72 = 21y Question 20:\u00a0<\/b>In a drum, 1260 litres of pure milk is available. \u2018Y\u2019 litres of milk is taken out from the mixture and replaced with the water. This process is repeated once again after that the pure milk available in the drum is $1142\\frac{6}{7}$ litres. Find out the value of \u2018y\u2019.<\/p>\n a)\u00a045<\/p>\n b)\u00a060<\/p>\n c)\u00a075<\/p>\n d)\u00a072<\/p>\n e)\u00a0None of the above<\/p>\n 20)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Solution:<\/b><\/p>\n $1142\\frac{6}{7} = 1260 (1-\\frac{y}{1260})^{2} $<\/p>\n $\\frac{8000}{7} = 1260 (1-\\frac{y}{1260})^{2} $<\/p>\n $\\frac{8000}{7\\times1260} = (1-\\frac{y}{1260})^{2} $<\/p>\n $\\frac{8000}{8820} = (1-\\frac{y}{1260})^{2} $<\/p>\n $\\frac{400}{441} = (1-\\frac{y}{1260})^{2} $<\/p>\n $1-\\frac{y}{1260} = \\frac{20}{21}$<\/p>\n $\\frac{1}{21} = \\frac{y}{1260}$<\/p>\n y = 60
\nLet\u2019s assume the initial quantity of juice is 5y.
\nInitial quantity of water = 5y of (100-20)%
\n= 5y of 80%
\n= 4y
\nWhen 90 litres of mixture is taken out and 70 liters of water is added into it, then the quantity of juice will be 11.11% more than the quantity of water.
\n$\\frac{5y-50}{4y-40+70} = \\frac{10}{9}$
\n$\\frac{5y-50}{4y+30} = \\frac{10}{9}$
\n$\\frac{y-10}{4y+30} = \\frac{2}{9}$
\n9y-90 = 8y+60
\n9y-8y = 60+90
\ny = 150
\nInitial quantity of water in the mixture = 4y
\n= $4\\times150$
\n= 600 liters
\nHence, option b is the correct answer.<\/p>\n
\nWhich of the following values can fill in the blanks appropriately?
\n(i) 60, 4
\n(ii) 95, 3
\n(iii) 140, 2<\/p>\n
\nFinal quantity of milk = Final quantity of water + $\\frac{4}{7}\\times$Final quantity of water
\nFinal quantity of milk = $\\frac{11}{7}\\times$Final quantity of water
\nRatio of the final quantity of milk and water is 11:7 respectively.<\/p>\n
\n<\/strong>60 litres of mixture is taken and 4 litres of milk is added from the tank.
\nRatio of initial quantity of milk and water = 120 : 80
\n= 3 : 2
\nFinal quantity of milk = 120 – $\\frac{3}{3+2}\\times$60 + 4 = 88 litres
\nFinal quantity of water = 80 – $\\frac{2}{3+2}\\times$60 = 56
\nRatio of final quantity of milk and water = 88 : 56
\n= 11:7
\nGiven values satisfy the conditions of the question.<\/p>\n
\n<\/strong>95 litres of mixture is taken and 3 litres of milk is added from the tank.
\nRatio of initial quantity of milk and water = 120 : 80
\n= 3 : 2
\nFinal quantity of milk = 120 – $\\frac{3}{3+2}\\times$95 + 3 = 66 litres
\nFinal quantity of water = 80 – $\\frac{2}{3+2}\\times$95 = 42
\nRatio of final quantity of milk and water = 66 : 42
\n= 11:7
\nGiven values satisfy the conditions of the question.<\/p>\n
\n<\/strong>140 litres of mixture is taken and 2 litres of milk is added from the tank.
\nRatio of initial quantity of milk and water = 120 : 80
\n= 3 : 2
\nFinal quantity of milk = 120 – $\\frac{3}{3+2}\\times$140 + 2 = 38 litres
\nFinal quantity of water = 80 – $\\frac{2}{3+2}\\times$140 = 24
\nRatio of final quantity of milk and water = 38 : 24
\n= 19:12
\nGiven values do not satisfy the conditions of the question.
\nHence, the correct answer is Option B<\/p>\n
\nLet the quantity of milk and water in tank A is 4p and p respectively.
\nRatio of milk and water in tank B is 3 : 1
\nLet the quantity of milk and water in tank B is 3q and q respectively.
\nThe total quantity of mixture is 60 litres when $\\frac{1}{5}$ of mixture from tank A and $\\frac{1}{4}$ of mixture from tank B are mixed.
\n$\\Rightarrow$ $\\frac{1}{5}$(4p+p) + $\\frac{1}{4}$(3q+q) = 60
\n$\\Rightarrow$ p + q = 60\u2026\u2026\u2026.(1)
\nThe quantity of milk in tank A is 40 litres more than quantity of water in tank B.
\n$\\Rightarrow$ 4p = q + 40\u2026….(2)
\nAdding (1) and (2),
\n5p + q = q + 100
\np = 20
\n$\\therefore$ Initial quantity of water in tank A = p = 20 litres
\nHence, the correct answer is Option A<\/p>\n
\nMilkman sold 10 litres of this mixture
\nRemaining mixture = 40 litres
\nPercentage of water = 20%
\nQuantity of water in the remaining mixture = $\\dfrac{20}{100}\\times$40 = 8 litres
\nQuantity of milk in the remaining mixture = 40 – 8 = 32 litres
\nAfter adding 32 litres of milk and 24 litres of water in the remaining mixture,
\nQuantity of milk in the new mixture = 32 + 32 = 64 litres
\nQuantity of water in the new mixture = 8 + 24 = 32 litres
\n$\\therefore$ Percentage of water in the new mixture = $\\dfrac{32}{64+32}\\times$100
\n= $\\dfrac{32}{96}\\times$100
\n= 33$\\frac{1}{3}$%
\nHence, the correct answer is Option A<\/p>\n
\nquantity of water = 75% of quantity of juice
\nquantity of juice : quantity of water \u21d2 4:3
\nquantity of juice = 280 of (4\/7) = 160 litres
\nquantity of water = 280 of (3\/7) = 120 litres
\nIf 20 litres and \u2018y\u2019 litres of juice and water are added into the initial mixture, then the quantity of juice and water in the new mixture will be 9:8 respectively.
\n$\\frac{160+20}{120+y} = \\frac{9}{8}$<\/p>\n
\ny = 160-120 = 40
\nHence, option b is the correct answer.<\/p>\n
\nLet\u2019s assume the initial quantity of milk and water in the mixture is 4z and z respectively.
\nIf \u2018y\u2019 and (y-15) litres of milk and water are poured into the mixture respectively, then in the mixture the new ratio of milk and water will be 7:2 respectively.
\n$\\frac{4z+y}{z+(y-15)} = \\frac{7}{2}$
\n8z+2y = 7z+7y-105
\nz-5y = -105
\n5y-z = 105
\nz = 5y-105 Eq.(i)
\nIf 40 litres of mixture is taken out from the initial mixture and (y-3) and (y-7) itres of milk and water are poured into the mixture respectively, then in the mixture the new ratio of milk and water will be 49:15 respectively.
\n$\\frac{4z-32+(y-3)}{z-8+(y-7)} = \\frac{49}{15}$<\/p>\n
\n60z-525+15y = 49z-735+49y
\n11z-34y = -735+525
\n34y-11z = 210 Eq.(ii)
\nPut Eq.(i) in Eq.(ii).
\n34y-11(5y-105) = 210
\n34y-55y+1155 = 210
\n21y = 945
\ny = 45
\nHence, option b is the correct answer.<\/p>\n
\nInitial quantity of milk = $\\frac{5}{8}\\times2024$
\n= 1265
\nInitial quantity of water = $\\frac{3}{8}\\times2024$
\n= 759
\nIf (y+44) litres of milk and \u2018y\u2019 litres of water is poured into the mixture, then the ratio between the quantity of milk and water will be 27:16 respectively.<\/p>\n
\n27y-16y = 20944-20493
\n11y = 451
\ny = 41
\nvalue of (y+8) = 41+8 = 49
\nHence, option a is the correct answer.<\/p>\n
\nIn a jar P, the ratio between the quantities of juice and water is 11:4 respectively.
\nIn another jar Q, \u2018y\u2019 litres of mixture is available, where the quantity of juice is $\\frac{3}{7}$ times more than the quantity of water.
\nIn a jar Q, the ratio between the quantities of juice and water is 10:7 respectively.
\nIf the mixture of both the jars is mixed together, then the quantity of water will be 452 litres.
\n(4\/15) of (y-35) + (7\/17) of y = 452<\/p>\n
\n173y = 115260+2380 = 117640
\ny = 680
\nHence, option d is the correct answer.<\/p>\n
\nLet\u2019s assume the ratio between the quantities of milk and water is 5y and 7y respectively.
\nIf 22 litres of water is poured into the mixture, then the ratio between the quantities of milk and water will be 2:3 respectively.
\n$\\frac{5y}{7y+22} = \\frac{2}{3}$<\/p>\n
\ny = 44
\nInitial quantity of mixture = 5y+7y = 12y = $12\\times44$
\n= 528 litres
\nHence, option c is the correct answer.<\/p>\n
\nThe ratio between the initial quantity of milk and water is 11:8 respectively.
\nIf 10 litres of water is added into the mixture, then the ratio between the quantity of milk to water will become 4:3.
\n$\\frac{\\frac{11}{19}y}{\\frac{8}{19}y + 10} = \\frac{4}{3}$<\/p>\n
\ny = 760
\nDifference between the quantity of milk and water in the initial mixture = $\\frac{11}{19}y – \\frac{8}{19}y$
\n= $\\frac{3}{19}y$<\/p>\n
\nHence, option d is the correct answer.<\/p>\n
\n55y – 49y = 6174-1530
\n6y = 4644
\ny = 774
\nHence, option b is the correct answer.<\/p>\n
\nThe quantity of juice in drum A = \u215e of the quantity of water in the same drum
\nSo in drum A, the ratio between the quantity of juice and water is 7:8 respectively.
\nIf the difference between the quantity of water in both the drums is 64 litres.
\n(y-75) of (8\/15) – y of (7\/18) = 64
\n$\\frac{8y}{15} – 40 – \\frac{7y}{18} = 64$<\/p>\n
\nTotal quantity of mixture in drum A = (y-75) = 720-75 = 645 litres
\nQuality of juice in drum A = 645 of (7\/15)
\n= 301 litres
\nHence, option d is the correct answer.<\/p>\n
\nIf the initial quantity of water is 775 litres.
\nInitial quantity of milk = $\\frac{35}{31}\\times 775$ = 875 litres.
\nIf \u2018y\u2019 litres of milk and (y+10) litres of water is poured into the mixture, then the quantity of milk will be 11.11% more than the quantity of water.
\n$\\frac{875 + y}{775 + (y+10)} = \\frac{10}{9}$<\/p>\n
\ny = 7875-7850 = 25
\nHence, option b is the correct answer.<\/p>\n
\nHence, option e is the correct answer.<\/p>\n
\nInitial quantity of milk = $\\frac{4}{5}\\times820$
\n= 656
\nInitial quantity of water = $\\frac{1}{5}\\times820$
\n= 164
\nIf 40 liters of mixture is taken out and some quantity of water is added into the mixture, then the ratio between the quantities of milk and water will be 3:1 respectively.
\nLet\u2019s assume the quantity of water is added into the mixture is y.
\n$\\frac{656-32}{164+y-8} = \\frac{3}{1}$<\/p>\n
\ny = 208-156 = 52 litres
\nHence, option e is the correct answer.<\/p>\n
\nQuantity of juice in bucket P = $\\frac{5}{7}\\times847$ = 605 litres
\nQuantity of water in bucket P = $\\frac{2}{7}\\times847$ = 242 litres
\nAnother bucket Q is having 195 litres of juice and the remaining quantity is water.
\nQuantity of juice in bucket Q = 195 litres
\nLet\u2019s assume the quantity of water in bucket Q is y.
\nIf the mixture of both buckets is poured into a big bucket R, then the total quantity of water in this bucket will be 31.25% of the total quantity of juice in this bucket.
\n$\\frac{605+195}{242+y} = \\frac{16}{5}$<\/p>\n
\nInitial quantity of water in the bucket Q = y = 250-242 = 8 litres
\nHence, option e is the correct answer.<\/p>\n
\nSo the ratio of the initial quantity of milk and water will be 4:5 respectively.
\nInitial quantity of milk = $\\frac{4}{9}\\times765$ = 340 litres<\/p>\n
\nIf \u2018y\u2019 litres of milk is poured into the mixture, the ratio between quantity of milk and water will be 16:17 respectively.
\n$\\frac{340+y}{425} = \\frac{16}{17}$<\/p>\n
\ny = 400-340 = 60
\nHence, option b is the correct answer.<\/p>\n
\nLet\u2019s assume the quantity of juice and water in the mixture are 5y and 7y respectively.
\nIf 18 litres of juice is poured into the mixture, then the quantity of juice in the new mixture will be 25% less than the quantity of water in the new mixture.
\n$\\frac{5y+18}{7y} = \\frac{3}{4}$<\/p>\n
\n21y-20y = y = 72
\nQuantity of water in the mixture = 7y = $7\\times72$
\n= 504 litres
\nHence, option c is the correct answer.<\/p>\n
\nHence, option b is the correct answer.<\/p>\n