{"id":213261,"date":"2022-08-05T17:36:54","date_gmt":"2022-08-05T12:06:54","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=213261"},"modified":"2022-08-05T17:36:54","modified_gmt":"2022-08-05T12:06:54","slug":"ibps-po-and-ibps-rrb-po-percentage-questions-pdf","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/ibps-po-and-ibps-rrb-po-percentage-questions-pdf\/","title":{"rendered":"IBPS PO and IBPS RRB PO Prelims Percentage Questions PDF"},"content":{"rendered":"

Percentage Questions for IBPS PO and IBPS RRB Prelims<\/h1>\n

Download Percentage Questions for IBPS PO and IBPS RRB Prelims<\/a><\/p>\n

Question 1:\u00a0<\/b>Suresh gave 17.39% of his monthly income to his wife and spent 31.57% of the remaining amount for household expenses. Out of the remaining amount he gave 15.38% to the charity. Again from the remaining amount he gave 18.18% to his friend. Finally if Suresh is left with ___ then monthly income of Suresh is ___ .
\nWhich of the following values can fill in the blanks appropriately?
\ni) 10035, 25645
\nii) 8991, 22977
\niii) 16083, 41101
\niv) 14085, 35995<\/p>\n

a)\u00a0Only (ii) and (iv)<\/p>\n

b)\u00a0Only (i) and (iv)<\/p>\n

c)\u00a0All (i), (ii), (iii) and (iv)<\/p>\n

d)\u00a0Only (i), (ii) and (iv)<\/p>\n

e)\u00a0Only (ii), (iii) and (iv)<\/p>\n

1)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Solution:<\/b><\/p>\n

Suresh gave 17.39% of his monthly income to his wife.
\nLet the monthly income of Suresh = 23p
\nAmount given to his wife = $\\frac{4}{23}\\times$23p = 4p
\nAmount remaining = 23p – 4p = 19p<\/p>\n

Suresh spent 31.57% of the remaining amount for household expenses.
\nAmount spent for household expenses = $\\frac{6}{19}\\times$19p = 6p
\nAmount remaining = 19p – 6p = 13p<\/p>\n

Out of the remaining amount he gave 15.38% to charity.
\nAmount given charity = $\\frac{2}{13}\\times$13p = 2p
\nAmount remaining = 13p – 3p = 11p<\/p>\n

Again from the remaining amount he gave 18.18% to his friend.
\nAmount given to friend = $\\frac{2}{11}\\times$11p = 2p
\nFinal amount remaining = 11p – 2p = 9p<\/p>\n

Ratio of the final amount remaining with Suresh and his monthly income respectively = 9p : 23p
\n= 9 : 23
\n
\n<\/strong>i) 10035, 25645
\n<\/strong>Ratio of the final amount remaining with Suresh and his monthly income respectively = 10035 : 25645
\n= 9 : 23
\nGiven values satisfy the condition of the question.<\/p>\n

ii) 8991, 22977
\n<\/strong>Ratio of the final amount remaining with Suresh and his monthly income respectively = 8991 : 22977
\n= 9 : 23
\nGiven values satisfy the condition of the question.<\/p>\n

iii) 16083, 41101
\n<\/strong>Ratio of the final amount remaining with Suresh and his monthly income respectively = 16083 : 41101
\n= 9 : 23
\nGiven values satisfy the condition of the question.<\/p>\n

iii) 14085, 35995
\n<\/strong>Ratio of the final amount remaining with Suresh and his monthly income respectively = 14085 : 35995
\n= 9 : 23
\nGiven values satisfy the condition of the question.
\nHence, the correct answer is Option C<\/p>\n

Question 2:\u00a0<\/b>If $(x+5) \\text{ of } 11.11\\% = y \\text{ of } 12.5\\% -10$ and $(x-25) = 75\\% \\text{ of } (y-40)$, then find out the value of $40\\% of (y-x)$.<\/p>\n

a)\u00a039<\/p>\n

b)\u00a051<\/p>\n

c)\u00a028<\/p>\n

d)\u00a013<\/p>\n

e)\u00a0None of the above<\/p>\n

2)\u00a0Answer\u00a0(E)<\/strong><\/p>\n

Solution:<\/b><\/p>\n

$(x+5) \\text{ of } 11.11\\% = y \\text{ of } 12.5\\% – 10$
\n$(x+5)\\times\\frac{1}{9} = y\\times\\frac{1}{8} – 10$
\n$(x+5) = y\\times\\frac{9}{8} – 90$<\/p>\n

$x = y\\times\\frac{9}{8} – 90 -5$<\/p>\n

$x = y\\times\\frac{9}{8} – 95$ Eq.(i)<\/p>\n

$(x-25) = 75\\% \\text{ of } (y-40)$
\n$(x-25) = \\frac{3}{4} \\times (y-40)$
\nPut the value of \u2018x\u2019 in the above equation from Eq.(i).
\n$(y\\times \\frac{9}{8}-95-25)=\\frac{3}{4}\\times (y-40)$
\nAfter solving the above equation, y = 240.
\nPut the value of \u2018y\u2019 in Eq.(i).
\n$x = 240\\times\\frac{9}{8} – 95$
\nx = 270-95
\n= 175
\nvalue of $40\\% of (y-x)$ = $40\\% of (240-175)$
\n= 40% of 65<\/p>\n

= 26
\nHence, option e is the correct answer.<\/p>\n

Question 3:\u00a0<\/b>Ketan spent 41.67% of his monthly salary on house rent. Out of the remaining, he spent 20% on food. Out of the remaining, he spent 10% on education. After that the remaining amount was invested in FD and MF in the ratio of 7:5 respectively. If the amount spent on education by him is Rs. 4480, then find out the difference between the amount spent on house rent and the amount invested on FD from his monthly salary.<\/p>\n

a)\u00a0Rs. 15240<\/p>\n

b)\u00a0Rs. 18640<\/p>\n

c)\u00a0Rs. 16480<\/p>\n

d)\u00a0Rs. 12680<\/p>\n

e)\u00a0None of the above<\/p>\n

3)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Solution:<\/b><\/p>\n

Let\u2019s assume the monthly salary of Ketan is 12z.
\nKetan spent 41.67% of his monthly salary on house rent.
\nAmount spent on house rent = 12z of (5\/12) = 5z
\nOut of the remaining, he spent 20% on food.
\nAmount spent on food = (12z-5z) of 20%
\n= 7z of 20%
\n= 1.4z
\nOut of the remaining, he spent 10% on education.
\nAmount spent on education = (7z-1.4z) of 10%
\n= 5.6z of 10%
\n= 0.56z
\nIf the amount spent on education by him is Rs. 4480.
\n0.56z = 4480
\nz = 8000
\n<\/b>After that the remaining amount was invested in FD and MF in the ratio of 7:5 respectively.
\nAmount invested on FD = 5.04z of (7\/12)
\n= 2.94z
\nDifference between the amount spent on house rent and the amount invested on FD from his monthly salary = 5z – 2.94z
\n= 2.06z
\nPut the value of \u2018z\u2019 in the equation.
\n= $2.06\\times8000$
\n= Rs. 16480
\nHence, option c is the correct answer.<\/p>\n

Question 4:\u00a0<\/b>The monthly savings of A is 58.33% less than the monthly expenditure of B. The monthly income of A is 25% more than the monthly income of B. If the monthly savings of B is Rs. 760 and the sum of the monthly expenditure of A and B together is Rs. 2490, then find out the difference between the monthly income of A and B.<\/p>\n

a)\u00a0Rs. 500<\/p>\n

b)\u00a0Rs. 200<\/p>\n

c)\u00a0Rs. 300<\/p>\n

d)\u00a0Rs. 400<\/p>\n

e)\u00a0None of the above<\/p>\n

4)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Solution:<\/b><\/p>\n

The monthly savings of A is 58.33% less than the monthly expenditure of B.
\nLet\u2019s assume the monthly expenditure of B is 12y.
\nmonthly savings of A = (5\/12) of 12y = 5y
\nThe monthly income of A is 25% more than the monthly income of B.
\nLet\u2019s assume the monthly income of B is 4z.
\nmonthly income of A = 5z
\nmonthly expenditure of A = (5z-5y)
\nmonthly savings of B = (4z-12y)
\nThe monthly savings of B is Rs. 760.
\n(4z-12y) = 760
\nz-3y = 190
\nz = (190+3y) Eq.(i)
\nThe sum of the monthly expenditure of A and B together is Rs. 2490.
\n(5z-5y)+12y = 2490
\n(5z+7y) = 2490
\nPut Eq.(i) in the above equation.
\n$5\\times(190+3y)+7y = 2490$
\n950+15y+7y = 2490
\n15y+7y = 2490-950 = 1540
\n22y = 1540
\ny = 70
\nPut the value of \u2018y\u2019 in Eq.(i).
\nz = (190+210) = 400
\nDifference between the monthly income of A and B = (5z-4z) = 400
\nHence, option d is the correct answer.<\/p>\n

Question 5:\u00a0<\/b>The ratio of income of Rahul and Amit is 9:13 respectively. The ratio of savings and expenditure of Amit is 6:7 respectively. If the savings of Amit is 20% more than the savings of Rahul, then the expenditure of Amit is how much percent more or less than the expenditure of Rahul?<\/p>\n

a)\u00a075% less<\/p>\n

b)\u00a025% more<\/p>\n

c)\u00a025% less<\/p>\n

d)\u00a075% more<\/p>\n

e)\u00a0None of the above<\/p>\n

5)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Solution:<\/b><\/p>\n

The ratio of income of Rahul and Amit is 9:13 respectively.
\nLet the income of Rahul and Amit are 9p and 13p respectively.
\nThe ratio of savings and expenditure of Amit is 6:7.
\nLet the savings and expenditure of Amit are 6q and 7q respectively.
\nIncome of Amit = 13p
\n$\\Rightarrow$ 6q + 7q = 13p
\n$\\Rightarrow$ 13q = 13p
\n$\\Rightarrow$ q = p\u2026\u2026..(1)
\nThe savings of Amit is 20% more than the savings of Rahul.
\nLet the savings of Rahul = t
\nSavings of Amit = $\\frac{120}{100}$t
\n$\\Rightarrow$ 6q = $\\frac{6}{5}$t
\n$\\Rightarrow$ t = 5q
\n$\\Rightarrow$ t = 5p
\nSavings of Rahul = t = 5p
\nExpenditure of Rahul = Income of Rahul – Savings of Rahul
\n= 9p – 5p
\n= 4p
\nExpenditure of Amit = 7q = 7p
\nRequired percentage = $\\frac{7p-4p}{4p}\\times$100
\n= $\\frac{3p}{4p}\\times$100
\n= 75% more
\nHence, the correct answer is Option D<\/p>\n

Question 6:\u00a0<\/b>A man spent 20% of his monthly income on house rent. Out of the remaining amount he spent 22% for shopping. Out of the remaining amount one fourth was spent on food and the remaining amount was saved. If the amount spent on shopping was \u20b99504, then what was the amount saved by the man?<\/p>\n

a)\u00a0\u20b926732<\/p>\n

b)\u00a0\u20b927892<\/p>\n

c)\u00a0\u20b924382<\/p>\n

d)\u00a0\u20b925272<\/p>\n

e)\u00a0None of the above<\/p>\n

6)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Solution:<\/b><\/p>\n

Let the monthly income of man = p
\nMan spent 20% of his monthly income on house rent.
\nRemaining amount after spending on house rent = 80% of p
\n= $\\frac{80}{100}$p
\nAmount spent on shopping was \u20b99504.
\n22% of $\\frac{80}{100}$p = 9504
\n$\\frac{22}{100}\\times\\frac{80}{100}$p = 9504
\np = \u20b954000
\nAmount saved by the man = 54000 of (100-20)% of (100-22)% of (3\/4)
\n= 54000 of 80% of 78% of (3\/4)
\n= 54000$\\times\\frac{80}{100}\\times\\frac{78}{100}\\times\\frac{3}{4}$
\n= \u20b925272
\nHence, the correct answer is Option D<\/p>\n

Question 7:\u00a0<\/b>A is 25% less than B 14.28% more than C. If the sum of A and C is 195, then find out the value of B.<\/p>\n

a)\u00a0180<\/p>\n

b)\u00a0120<\/p>\n

c)\u00a0150<\/p>\n

d)\u00a090<\/p>\n

e)\u00a0Cannot be determined<\/p>\n

7)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Solution:<\/b><\/p>\n

Let\u2019s assume the value of C is 7y.
\nA is 25% less than B 14.28% more than C.
\nValue of B = (8\/7) of 7y = 8y
\nValue of A = 8y of 75% = 6y
\nIf the sum of A and C is 195.
\n6y+7y = 195
\n13y = 195
\ny = 15
\nvalue of B = 8y = 120
\nHence, option b is the correct answer.<\/p>\n

Question 8:\u00a0<\/b>In 2010, the number of bears in the zoo was increased by 35% and next year these were decreased by 16.67%. Now the number of bears in the zoo is 405, then find out the 20% of the number of bears in the zoo two years ago.<\/p>\n

a)\u00a066<\/p>\n

b)\u00a054<\/p>\n

c)\u00a060<\/p>\n

d)\u00a078<\/p>\n

e)\u00a0None of the above<\/p>\n

8)\u00a0Answer\u00a0(E)<\/strong><\/p>\n

Solution:<\/b><\/p>\n

Let\u2019s assume the number of bears in the zoo two years ago is \u2018y\u2019.
\ny of (100+35)% of (100-16.67)% = 405
\n$y\\times1.35\\times\\frac{5}{6} = 405$
\n6.75y = 2430
\ny = 360
\n20% of the number of bears in the zoo two years ago = 20% of 360
\n= 72
\nHence, option e is the correct answer.<\/p>\n

Question 9:\u00a0<\/b>The price of icecream has increased by 40%. Lekha has decided to spend only 4% more than what he initially did on buying icecream. What is the percentage decrease in Lekha’s rice consumption?<\/p>\n

a)\u00a019%<\/p>\n

b)\u00a060%<\/p>\n

c)\u00a015%<\/p>\n

d)\u00a030%<\/p>\n

e)\u00a025%<\/p>\n

9)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Solution:<\/b><\/p>\n

Let the initial price of icecream be Rs. 100 per unit and Lekha’s consumption be 10 units.<\/p>\n

\u2234 Initial amount spent = 100 \u00d7 10 = Rs. 1,000<\/p>\n

New price of icecream = 140% of 100 = Rs. 140 and new total amount spent = 104% of 1000 = Rs. 1,040
\ntherefore , the new consumption will be\u00a0$\\ \\frac{\\ 1040}{150}$ = 6.93 (let us take approximate value as 7)<\/p>\n

Decrease in consumption =\u00a03 units<\/p>\n

% decrease\u00a0\u00a0=$\\ \\frac{\\ 3}{10}\\times\\ 100$ = 30%<\/p>\n

Hence answer is option d<\/p>\n

Question 10:\u00a0<\/b>Three students has birthday on same day they received\u00a0\u00a0126, 786 and 986 gifts\u00a0respectively from their friends\u00a0\u00a0What percentage of the total gifts\u00a0 did the person with more gifts\u00a0get?<\/p>\n

a)\u00a052%<\/p>\n

b)\u00a055%<\/p>\n

c)\u00a075%<\/p>\n

d)\u00a090%<\/p>\n

e)\u00a080%<\/p>\n

10)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Solution:<\/b><\/p>\n

Total number of gifts = (126+786+986) = 1898<\/p>\n

Required percentage =\u00a0\u00a0$\\ \\frac{\\ 986}{1898}\\times\\ 100$<\/p>\n

=> 51.95% which is approximately 52%<\/p>\n

hence answer is option a<\/p>\n

Question 11:\u00a0<\/b>If 35% of a number P is 82 less than the 45% of a number Q and the sum of numbers P & Q is 1320, then find out the sum of the 55% of P and 25% of Q.<\/p>\n

a)\u00a0546<\/p>\n

b)\u00a0568<\/p>\n

c)\u00a0584<\/p>\n

d)\u00a0522<\/p>\n

e)\u00a0None of the above<\/p>\n

11)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Solution:<\/b><\/p>\n

35% of P = 45% of Q – 82
\n0.35P = 0.45Q – 82 Eq.(i)
\nSum of numbers P & Q is 1320.
\nP+Q = 1320
\nQ = 1320-P Eq.(ii)
\nPut Eq.(ii) in Eq.(i).
\n0.35P = 0.45(1320-P) – 82
\n0.35P = 594-0.45P – 82
\n0.35P+0.45P = 594 – 82
\n0.8P = 512
\nP = 640
\nPut the value of P in Eq.(ii).
\nQ = 1320-640 = 680
\nSum of the 55% of P and 25% of Q = 55% of 640 + 25% of 680
\n= 352+170
\n= 522
\nHence, option d is the correct answer.<\/p>\n

Question 12:\u00a0<\/b>The present population of a village P is 19683. The population of the village P increases by 11.11% every year. After 4 years, out of the total population of village P, 67.3% are adults and the rest are children. Out of the total number of adults, 30% are female while out of the total number of children, 60% are female. Find the total number of male(children+adults) after 4 years.<\/p>\n

a)\u00a016486<\/p>\n

b)\u00a017156<\/p>\n

c)\u00a018057<\/p>\n

d)\u00a016874<\/p>\n

e)\u00a0None of these<\/p>\n

12)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Solution:<\/b><\/p>\n

Present population of the village P = 19683.
\n11.11% = $\\dfrac{1}{9}$<\/p>\n

Population of P after 4 years = $19683\\times\\dfrac{10}{9}\\times\\dfrac{10}{9}\\times\\dfrac{10}{9}\\times\\dfrac{10}{9}$<\/p>\n

$=30000$<\/p>\n

Total number of adults = 67.3% of 30000 = 20190.
\nTotal number of children = 30000-20190 = 9810.<\/p>\n

Number of male adults = (100-30)% of 20190 = 70% of 20190 = 14133.
\nNumber of male children = (100-60)% of 9810 = 40% of 9810 = 3924.<\/p>\n

Total number of male children and adults together = 14133+3924 = 18057.<\/p>\n

Question 13:\u00a0<\/b>The population of a village M increases by 12.5% every year. After 4 years, the population of village\u00a0M will be 465831. Out of the present population of village M, 25% are females and the remaining are males. Out of the female population, 43.75% are children while out of the male population, 58.33% are children. Find the total number of adults in the village M at present.<\/p>\n

a)\u00a0124786<\/p>\n

b)\u00a0131776<\/p>\n

c)\u00a0134786<\/p>\n

d)\u00a0142784<\/p>\n

e)\u00a0None of these<\/p>\n

13)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Solution:<\/b><\/p>\n

After 4 years, the population of M = 465831.
\nPresent population of M = $465831\\times\\dfrac{9}{8}\\times\\dfrac{9}{8}\\times\\dfrac{9}{8}\\times\\dfrac{9}{8}$<\/p>\n

$=290816$<\/p>\n

Number of females = 25% of 290816.
\nNumber of adult females = (100-43.75)% of 25% of 290816 = $\\dfrac{9}{16}\\times\\dfrac{1}{4}\\times290816 = 40896$.<\/p>\n

Number of males = 75% of 290816.
\nNumber of adult males = (100-58.33)% of 75% of 290816 = $\\dfrac{5}{12}\\times\\dfrac{3}{4}\\times290816 = 90880$.<\/p>\n

Total number of adults = 40896+90880 = 131776.<\/p>\n

Question 14:\u00a0<\/b>Four natural numbers P, Q, R, and S are given such that their total sum is equal to 7700. If Q is increased by 36.36% then it will become 30\/11 times of the sum of P and S. If Q is decreased by 8.33% it will become 11 times the difference between P and\u00a0S (Considering P>S). Find the value of S if S is 100% more of R?<\/p>\n

a)\u00a0990<\/p>\n

b)\u00a01000<\/p>\n

c)\u00a0880<\/p>\n

d)\u00a02000<\/p>\n

e)\u00a0Can\u2019t be determined<\/p>\n

14)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Solution:<\/b><\/p>\n

ATQ,
\nP+Q+R+S = 7700 —————(i)
\nIf Q is increased by 36.36% then it will become 30\/11 times of the sum of P and S i.e 36.36% = 4\/11, so, if it is increased by 36.36% i.e. 1+ 4\/11 = 15\/11.
\n15\/11Q= 30\/11(P+S)
\nQ=2(P+S) ———(ii)
\nIf Q is decreased by 8.33% it will become 11 times the difference of P, and S i.e. 8.33% = 1\/12
\n11\/12 Q = 11 (P-S)
\nQ = 12(P-S) ————(iii)
\nFrom eq (i) and (ii), we get
\n2(P+S) = 12(P-S) ——–(iiib)
\nNow using eq (iii) in the above eq.,we get,
\n5P= 7S —(iv)
\nAgain using eq (ii) in the above eqn, we get,
\nQ = 2(7S\/5+S)
\nQ = 24S\/5
\nQ = 4.8S ——(v)
\nS is 100% more of R
\nS= 2R —-(vi)
\nSo, from eq (i), we get,
\nP+Q+R+S = 2000
\n7S\/5+24S\/5+S\/2+S = 7700
\nFrom eq (iiib), we get
\nS = 1000.<\/p>\n

Question 15:\u00a0<\/b>In an essay writing class a boy writes a 6 page long essay with 25 lines in each page and 21 characters in each line. If he writes the same content in a different notebook with 20 lines in each page and 15 characters in each line, then the required numbers of pages to write the same essay will be how much percent more or less than the previous notebook?<\/p>\n

a)\u00a011%<\/p>\n

b)\u00a0111%<\/p>\n

c)\u00a083.33%<\/p>\n

d)\u00a066.67%<\/p>\n

e)\u00a0None of the above<\/p>\n

15)\u00a0Answer\u00a0(E)<\/strong><\/p>\n

Solution:<\/b><\/p>\n

According to the question,
\n6 x 25 x 21 = 20 x 15 x number of pages, solving this we get,
\nNumber of pages = 10.5
\nSo number of pages required = 10.5 pages
\nDifference = 10.5 – 6 = 4.5
\nPercentage increase = $\\frac{4.5}{6} \\times 100$ = 75% more.<\/p>\n

Hence (E)<\/p>\n

Question 16:\u00a0<\/b>A person spends 12.5% of his monthly income on a house loan. Out of his remaining monthly salary, he spends 16.67% on clothes. He distributes the remaining salary to his wife and his son in the ratio 5:2 respectively. His wife spends 20% of the amount obtained by her and saves the rest. His son invests 10% of the amount obtained by him in mutual funds and saves the rest. If the difference between the amount saved by his wife and his son is Rs.4543, then find the amount spent by him on clothes.<\/p>\n

a)\u00a0Rs.2171<\/p>\n

b)\u00a0Rs.2469<\/p>\n

c)\u00a0Rs.2631<\/p>\n

d)\u00a0Rs.2891<\/p>\n

e)\u00a0None of these<\/p>\n

16)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Solution:<\/b><\/p>\n

Let the monthly salary of the person be Rs.48x.
\nAmount spent on house loan = 12.5% of 48x = Rs.6x.
\nRemaining salary = 48x-6x = Rs.42x.
\nAmount spent on clothes = 16.67% of 42x = $\\dfrac{1}{6}\\times42x = Rs.7x$.
\nRemaining salary = Rs.42x-7x = Rs.35x.
\nAmount obtained by his wife = $\\dfrac{5}{7}\\times35x = Rs.25x$.
\nAmount spent by his wife = 20% of Rs.25x = Rs.5x.
\nAmount saved by his wife = Rs.25x – Rs.5x = Rs.20x.<\/p>\n

Amount obtained by his son = $\\dfrac{2}{7}\\times35x = Rs.10x$
\nAmount invested in mutual funds = 10% of Rs.10x = Rs.x.
\nAmount saved = Rs.10x-x = Rs.9x.<\/p>\n

Given, 20x – 9x = 4543
\n11x = 4543
\nx = 413.<\/p>\n

Hence, The amount spent on clothes = Rs.7x = Rs.2891.<\/p>\n

Question 17:\u00a0<\/b>If number A is 37.5% of B and B is 50% of C.Then A will be how much percent of C?<\/p>\n

a)\u00a00.625%<\/p>\n

b)\u00a06.25%<\/p>\n

c)\u00a062.5%<\/p>\n

d)\u00a018.75%<\/p>\n

e)\u00a0None of the above<\/p>\n

17)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Solution:<\/b><\/p>\n

ATQ,
\nA = 37.5\/100 B
\nA = 3\/8\u00a0 B —-(a)
\nB = 50\/100 C
\nOr
\nB = \u00bd C —–(b)
\nPutting the value of B in eq (a)
\nA = 3\/8 x (\u00bd C)
\nA = 3\/16 C
\nSo, in percentage
\n$A = (\\dfrac{3}{16} \\times 100) of C$
\nA = 18.75% of C.<\/p>\n

Question 18:\u00a0<\/b>The population of village A in 2010 is 16384. In 2011, the population of the village A decreased by 12.5% and in 2012, it increased by 12.5% as compared to 2011. In 2013, it again decreased by 12.5% and in 2014, it again increased by 12.5%. The population of another village B in 2010 is 43923. In 2011, the population of the village B increased by 9.09% and in 2012, it decreased by 9.09%. In 2013, it again increased by 9.09% and in 2014, it again decreased by 9.09%. Find the difference between the population of villages A and B in 2014.<\/p>\n

a)\u00a024384<\/p>\n

b)\u00a017364<\/p>\n

c)\u00a027324<\/p>\n

d)\u00a021464<\/p>\n

e)\u00a0None of these<\/p>\n

18)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Solution:<\/b><\/p>\n

Population of village A in 2010 = 16384.
\nPopulation of village A in 2014 = (100-12.5)% of (100+12.5)% of (100-12.5)% of (100+12.5)% of 16384.<\/p>\n

$=\\dfrac{7}{8}\\times\\dfrac{9}{8}\\times\\dfrac{7}{8}\\times\\dfrac{9}{8}\\times16384 = 15876$.<\/p>\n

Population of village B in 2010 = 43923.
\nPopulation of village B in 2014 = (100+9.09)% of (100-9.09)% of (100+9.09)% of (100-9.09)% of 43923.<\/p>\n

$=\\dfrac{12}{11}\\times\\dfrac{10}{11}\\times\\dfrac{12}{11}\\times\\dfrac{10}{11}\\times43923 = 43200$.<\/p>\n

Hence, Difference = 43200 – 15876 = 27324.<\/p>\n

Question 19:\u00a0<\/b>The ratio between the first and third numbers is 3:1 respectively and the second number is 44.44% more than the first number. The sum of the second and third numbers is 1216. Find out the fourth number which is 83.33% of the first number.<\/p>\n

a)\u00a0660<\/p>\n

b)\u00a0540<\/p>\n

c)\u00a0630<\/p>\n

d)\u00a0570<\/p>\n

e)\u00a0None of the above<\/p>\n

19)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Solution:<\/b><\/p>\n

The ratio between the first and third numbers is 3:1 respectively.
\nLet\u2019s assume the first and third numbers are 9y and 3y respectively.
\nThe second number is 44.44% more than the first number.
\nSecond number = (13\/9) of 9y = 13y
\nThe sum of the second and third numbers is 1216.
\n13y+3y = 1216
\n16y = 1216
\ny = 76
\nFirst number = 9y = $9\\times76$ = 684
\nFourth number = 83.33% of 684
\n= \u215a of 684
\n= 570
\nHence, option d is the correct answer.<\/p>\n

Question 20:\u00a0<\/b>A person spends 20% of his monthly salary on house rent. Out of the remaining, he spends 15% on food. Out of the remaining salary, he spends 25% on travel. He spends 33.33% of the remaining salary on clothes and distributes the remaining salary to his two sons equally. If each son got Rs.1581, then find the amount spent on house rent.<\/p>\n

a)\u00a0Rs.1860<\/p>\n

b)\u00a0Rs.1720<\/p>\n

c)\u00a0Rs.1240<\/p>\n

d)\u00a0Rs.1450<\/p>\n

e)\u00a0None of these<\/p>\n

20)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Solution:<\/b><\/p>\n

Let his monthly salary be Rs.100x.
\nAmount spent on house rent = 20% of 100x = Rs.20x.
\nRemaining salary = 100x-20x = Rs.80x.
\nAmount spent on food = 15% of 80x = Rs.12x.
\nRemaining salary = 80x-12x = Rs.68x.
\nAmount spent on travel = 25% of 68x = Rs.17x.
\nRemaining salary = 68x-17x = Rs.51x.
\nAmount spent on clothes = 33.33% of 51x = Rs.17x.
\nRemaining salary = 51x-17x = Rs.34x.
\nAmount obtained by each son = Rs.17x.<\/p>\n

Given, 17x = 1581 \u21d2 x = 93.
\nAmount spent on house rent = $20\\% of 100\\times93 = 20\\% of 9300 = Rs.1860$.<\/p>\n","protected":false},"excerpt":{"rendered":"

Percentage Questions for IBPS PO and IBPS RRB Prelims Question 1:\u00a0Suresh gave 17.39% of his monthly income to his wife and spent 31.57% of the remaining amount for household expenses. Out of the remaining amount he gave 15.38% to the charity. Again from the remaining amount he gave 18.18% to his friend. Finally if Suresh […]<\/p>\n","protected":false},"author":32,"featured_media":213273,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_mi_skip_tracking":false,"footnotes":""},"categories":[8,1127,2069],"tags":[171,48,5814,5818,312,5816],"class_list":{"0":"post-213261","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-banking","8":"category-ibps-rrb","9":"category-ibps-rrb-po","10":"tag-banking","11":"tag-ibps-po","12":"tag-ibps-po-and-ibps-rrb-prelims","13":"tag-ibps-po-prelims","14":"tag-ibps-rrb-po","15":"tag-ibps-rrb-po-prelims"},"better_featured_image":{"id":213273,"alt_text":"IBPS PO & IBPS RRB PO","caption":"IBPS PO & IBPS RRB PO ","description":"IBPS PO & IBPS RRB PO 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