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Download Profit and Loss Discount Questions for SSC MTS<\/a><\/p>\n Enroll to 15 SSC MTS 2022 Mocks At Just Rs. 149<\/a><\/p>\n Question 1:\u00a0<\/b>An article was sold at a loss of 12%. If it was sold for \u20b9 630 more, then there would have been a gain of 6%. Find the cost price of the article.<\/p>\n a)\u00a0\u20b9 3,500<\/p>\n b)\u00a0\u20b9 2,800<\/p>\n c)\u00a0\u20b9 2,500<\/p>\n d)\u00a0\u20b9 3,000<\/p>\n 1)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Solution:<\/b><\/p>\n Let the cost price of the article = C<\/p>\n Selling price of the article at 12% loss =\u00a0$\\frac{88}{100}$C<\/p>\n Selling price of the article at 6% gain =\u00a0$\\frac{106}{100}$C<\/p>\n According to the problem,<\/p>\n $\\frac{88}{100}$C $+\u00a0 630 = \\frac{106}{100}$C<\/p>\n $\\Rightarrow$ \u00a0$\\frac{106}{100}$C $- \\frac{88}{100}$C $=630$<\/p>\n $\\Rightarrow$ \u00a0$\\frac{18}{100}$C $=630$<\/p>\n $\\Rightarrow$\u00a0 C = 3500<\/p>\n $\\therefore\\ $Cost price of the article =\u00a0\u20b9 3,500<\/p>\n Hence, the correct answer is Option A<\/p>\n Question 2:\u00a0<\/b>The printed price of a cooker is \u20b9 2,000, and discounts are 30%, 20% and 10%, respectively. Find the selling price of the cooker.<\/p>\n a)\u00a0\u20b9 1,002<\/p>\n b)\u00a0\u20b9 1,008<\/p>\n c)\u00a0\u20b9 1,004<\/p>\n d)\u00a0\u20b9 1,006<\/p>\n 2)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Solution:<\/b><\/p>\n Given, Marked price(Printed price) of the cooker =\u00a0\u20b9 2,000<\/p>\n Price of the cooker after 30% discount = $\\frac{70}{100}\\times2000$ =\u00a0\u20b9 1,400<\/p>\n Price of the cooker after 20% discount =\u00a0$\\frac{80}{100}\\times1400$ =\u00a0\u20b9\u00a01,120<\/p>\n Price of the cooker after 10% discount =\u00a0$\\frac{90}{100}\\times1120$ =\u00a0\u20b9 1,008<\/p>\n $\\therefore\\ $Selling price of the cooker after successive discounts =\u00a0\u20b9 1,008<\/p>\n Hence, the correct answer is Option B<\/p>\n Question 3:\u00a0<\/b>Anil bought some articles at 6 for \u20b9 8 and sold them at 10 for \u20b9 12. His percentage loss orgain is:<\/p>\n a)\u00a010% loss<\/p>\n b)\u00a010% gain<\/p>\n c)\u00a08% gain<\/p>\n d)\u00a08% loss<\/p>\n 3)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Solution:<\/b><\/p>\n Cost price of 6 articles =\u00a0\u20b9 8<\/p>\n $\\Rightarrow$\u00a0 Cost price of 1 article = $\\frac{8}{6}$ \u00a0= \u20b9 $\\frac{4}{3}$<\/p>\n Selling price of 10 articles =\u00a0\u20b9 12<\/p>\n $\\Rightarrow$\u00a0 Selling price of 1 article = $\\frac{12}{10}$ =\u00a0\u20b9 $\\frac{6}{5}$<\/p>\n Loss of 1 article =\u00a0$\\frac{4}{3}-\\frac{6}{5}=\\frac{20-18}{15}=$\u00a0 \u20b9 $\\frac{2}{15}$<\/p>\n Loss% $=\\frac{\\frac{2}{15}}{\\frac{4}{3}}\\times100=\\frac{2}{15}\\times\\frac{3}{4}\\times100=10\\%$<\/p>\n Hence, the correct answer is Option A<\/p>\n Question 4:\u00a0<\/b>Marked price of an article is 20% more than it\u2019s cost price. At what percent less should it be sold for no profit and no loss ?<\/p>\n a)\u00a0$16 \\frac{2}{3}$%<\/p>\n b)\u00a0$16 \\frac{1}{3}$%<\/p>\n c)\u00a0$14 \\frac{1}{3}$%<\/p>\n d)\u00a0$14 \\frac{2}{3}$%<\/p>\n 4)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Solution:<\/b><\/p>\n Let the cost price of the article = C<\/p>\n $\\Rightarrow$ Marked price of the article =\u00a0$\\frac{120}{100}$C =\u00a0$\\frac{6}{5}$C<\/p>\n For no profit and no loss, Selling price = Cost price = C<\/p>\n $\\therefore\\ $Required percentage = $\\frac{\\frac{6}{5}C-C}{\\frac{6}{5}C}\\times100$ = $\\frac{\\frac{1}{5}C}{\\frac{6}{5}C}\\times100$ = $16 \\frac{2}{3}$%<\/p>\n Hence, the correct answer is Option A<\/p>\n Question 5:\u00a0<\/b>Sohan purchased an old scooter, and sold it for \u20b928,000 thus gaining a 12% profit on the cost price. The cost price of the scooter is:<\/p>\n a)\u00a0\u20b927,000<\/p>\n b)\u00a0\u20b930,000<\/p>\n c)\u00a0\u20b925,000<\/p>\n d)\u00a0\u20b926,000<\/p>\n 5)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Solution:<\/b><\/p>\n Let the cost price of the scooter = C<\/p>\n Profit% = 12%<\/p>\n $\\Rightarrow$ Selling price of the scooter = $\\frac{112}{100}$C<\/p>\n Given, Selling price of the scooter = \u20b928,000<\/p>\n $\\Rightarrow$\u00a0$\\frac{112}{100}$C = 28000<\/p>\n $\\Rightarrow$\u00a0 C =\u00a0\u20b925,000<\/p>\n $\\therefore\\ $Cost price of the scooter =\u00a0\u20b925,000<\/p>\n Hence, the correct answer is Option C<\/p>\n Take a free SSC MTS Tier-1 mock test<\/a><\/p>\n Download SSC CGL Tier-1 Previous Papers PDF<\/a><\/p>\n Question 6:\u00a0<\/b>The marked price of a toy is \u20b9450. After a certain discount on the marked price, the selling price of the toy is \u20b9405. The rate of discount is:<\/p>\n a)\u00a08%<\/p>\n b)\u00a012%<\/p>\n c)\u00a015%<\/p>\n d)\u00a010%<\/p>\n 6)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Solution:<\/b><\/p>\n Marked price of the toy =\u00a0\u20b9450<\/p>\n Selling price of the toy =\u00a0\u20b9405<\/p>\n Discount = 450 – 405 = 45<\/p>\n $\\therefore\\ $Discount% =\u00a0$\\frac{45}{450}\\times100=10\\%$<\/p>\n Hence, the correct answer is Option D<\/p>\n Question 7:\u00a0<\/b>A trader marks his goods in such a way that even after allowing 15% discount on marked price he still gains 27.5%. If the cost price of the goods is \u20b9 200, then its marked price is:<\/p>\n a)\u00a0\u20b9 300<\/p>\n b)\u00a0\u20b9 250<\/p>\n c)\u00a0\u20b9 350<\/p>\n d)\u00a0\u20b9 400<\/p>\n 7)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Solution:<\/b><\/p>\n Given, cost price of the goods =\u00a0\u20b9 200<\/p>\n Gain% = 27.5%<\/p>\n $\\Rightarrow$\u00a0 Selling price of the goods = $\\frac{127.5}{100}\\times200=255$<\/p>\n Let the marked price of the goods = M<\/p>\n Discount = 15%<\/p>\n $\\Rightarrow$\u00a0 Selling price of the goods =\u00a0$\\frac{85}{100}$M<\/p>\n $\\Rightarrow$ \u00a0$\\frac{85}{100}$M = 255<\/p>\n $\\Rightarrow$\u00a0 M = 300<\/p>\n $\\therefore\\ $Marked price of the goods = \u20b9 300<\/p>\n Hence, the correct answer is Option A<\/p>\n Question 8:\u00a0<\/b>Amit sold an article for \u20b9 7,000 and incurred a loss. Had he sold it for \u20b9 8,750, his gain would have been three-fourth of the amount of loss that he incurred. At what price should he sell the article to get 10% profit?<\/p>\n a)\u00a0\u20b9 8,800<\/p>\n b)\u00a0\u20b9 8,400<\/p>\n c)\u00a0\u20b9 8,000<\/p>\n d)\u00a0\u20b9 7,800<\/p>\n 8)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Solution:<\/b><\/p>\n Let the cost price = C<\/p>\n Loss for selling price\u00a0\u20b9 7,000 = C – 7000<\/p>\n Profit for selling price\u00a0\u20b9 8,750 = 8750 – C<\/p>\n According to the problem,<\/p>\n $8750-\\text{C}=\\frac{3}{4}\\left(\\text{C}-7000\\right)$<\/p>\n $\\Rightarrow$ \u00a0$8750-\\text{C}=\\frac{3}{4}\\text{C}-5250$<\/p>\n $\\Rightarrow$ \u00a0$\\frac{7}{4}\\text{C}=14000$<\/p>\n $\\Rightarrow$\u00a0 C = 8000<\/p>\n $\\therefore\\ $Selling price =\u00a0$\\frac{110}{100}\\times8000$ = \u20b9 8,800<\/p>\n Hence, the correct answer is Option A<\/p>\n Question 9:\u00a0<\/b>The selling price of a book, including the sales tax, is \u20b9 956.34. The rate of sales tax is 10%. If the shopkeeper has made a profit of 15%, then the cost price of the book is:<\/p>\n a)\u00a0\u20b9 836<\/p>\n b)\u00a0\u20b9 797.34<\/p>\n c)\u00a0\u20b9 845.98<\/p>\n d)\u00a0\u20b9 756<\/p>\n 9)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Solution:<\/b><\/p>\n Let the cost price of the book = C<\/p>\n Sales tax = 10%<\/p>\n Price of the book with sales tax =\u00a0$\\frac{110}{100}C$<\/p>\n Profit = 15%<\/p>\n Selling price of the book =\u00a0\u20b9 956.34<\/p>\n $\\Rightarrow$ \u00a0$\\frac{115}{100}\\times\\frac{110}{100}C$ = 956.34<\/p>\n $\\Rightarrow$ \u00a0$C=\\frac{956340}{115\\times11}$<\/p>\n $\\Rightarrow$ \u00a0$C=\\frac{86940}{115}$<\/p>\n $\\Rightarrow$ \u00a0$C=\\frac{3780}{5}$<\/p>\n $\\Rightarrow$ \u00a0$C=756$<\/p>\n $\\therefore\\ $Cost price of the book =\u00a0\u20b9 756<\/p>\n Hence, the correct answer is Option D<\/p>\n Question 10:\u00a0<\/b>A dozen pairs of gloves worth \u20b9 600 are available at a discount of 10%. Find out how many pairs of gloves can be bought for \u20b9 270.<\/p>\n a)\u00a0Seven<\/p>\n b)\u00a0Four<\/p>\n c)\u00a0Six<\/p>\n d)\u00a0Five<\/p>\n 10)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Solution:<\/b><\/p>\n Marked price of dozen pair of gloves =\u00a0\u20b9 600<\/p>\n Discount = 10%<\/p>\n Selling price of the dozen pair of gloves by shopkeeper =\u00a0$\\frac{90}{100}\\times600$ = \u20b9 540<\/p>\n 12 pair of gloves can be bought for\u00a0\u20b9 540<\/p>\n $\\therefore\\ $6 pair of gloves can be bought for\u00a0\u20b9 270<\/p>\n Hence, the correct answer is Option C<\/p>\n Question 11:\u00a0<\/b>A person purchased 40 items at some price. He sold some items at a profit of 30% by selling them at a price equal to the cost price of 26 items. The remaining items are sold at 18% profit. The total profit percentage is:<\/p>\n a)\u00a027%<\/p>\n b)\u00a028%<\/p>\n c)\u00a024%<\/p>\n d)\u00a025%<\/p>\n 11)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Solution:<\/b><\/p>\n Let the cost price = 40C<\/p>\n Number of items sold at 30% profit = a<\/p>\n Cost price of ‘a’ items = aC<\/p>\n Selling price of ‘a’ items =\u00a0$\\frac{130}{100}aC$<\/p>\n According to the problem,<\/p>\n Selling price of ‘a’ items = Cost price of 26 items<\/p>\n $=$> \u00a0$\\frac{130}{100}aC=26C$<\/p>\n $=$> \u00a0$a=20$<\/p>\n $=$> \u00a0Number of items sold at 30% profit = a = 20<\/p>\n Remaining items sold at 18% profit = 40 – 20 = 20<\/p>\n Selling price of items sold at 30% profit =\u00a0$\\frac{130}{100}\\times20C$ =\u00a0$26C$<\/p>\n Selling price of items sold at 18% profit = $\\frac{118}{100}\\times20C$ = $23.6C$<\/p>\n $\\therefore\\ $Total profit percentage =\u00a0$\\frac{26C+23.6C-40C}{40C}\\times100=\\frac{9.6}{40}\\times100=24\\%$<\/p>\n Hence, the correct answer is Option C<\/p>\n Question 12:\u00a0<\/b>By selling an article for $\u20b9 600$, a shopkeeper makes a profit of 20%. At what price should he sell the article to incur a loss of 20% ?<\/p>\n a)\u00a0$\u20b9 500$<\/p>\n b)\u00a0$\u20b9 400$<\/p>\n c)\u00a0$\u20b9 300$<\/p>\n d)\u00a0$\u20b9 600$<\/p>\n 12)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Solution:<\/b><\/p>\n Let the cost price = C.P<\/p>\n Given,<\/p>\n Profit% = 20%<\/p>\n Selling price = $\u20b9 600$<\/p>\n $=$> \u00a0$\\frac{120}{100}\\text{C.P}=600$<\/p>\n $=$> \u00a0$\\text{C.P}=500$<\/p>\n $\\therefore\\ $Selling price when loss is 20% = $\\frac{80}{100}\\text{C.P}=\\frac{80}{100}\\times500=\u20b9 400$<\/p>\n Hence, the correct answer is Option B<\/p>\n Question 13:\u00a0<\/b>A product, whose MRP is $\u20b9$ 978, is sold for $\u20b9$ 925 by a wholesale shop owner. What is the percentage of discount given by him?<\/p>\n a)\u00a09.2%<\/p>\n b)\u00a06.5%<\/p>\n c)\u00a05.4%<\/p>\n d)\u00a07.8%<\/p>\n 13)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Solution:<\/b><\/p>\n Given,<\/p>\n MRP of the product =\u00a0$\u20b9$ 978<\/p>\n Selling Price of the product = $\u20b9$ 925<\/p>\n Discount = 978 – 925 =\u00a0$\u20b9$ 53<\/p>\n Discount% =\u00a0$\\frac{\\text{Discount}}{\\text{MRP}}\\times100$<\/p>\n $=\\frac{53}{978}\\times100$<\/p>\n $=0.054\\times100$<\/p>\n $=5.4$%<\/p>\n Hence, the correct answer is Option C<\/p>\n Question 14:\u00a0<\/b>A shopkeeper purchased pens in bulk for $\u20b9 28$ each. He sold each for $\u20b9 40$. What was his profit percentage?<\/p>\n a)\u00a048.12%<\/p>\n b)\u00a028.40%<\/p>\n c)\u00a042.85%<\/p>\n d)\u00a038.75%<\/p>\n 14)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Solution:<\/b><\/p>\n Let the number of pens purchased by shopkeeper = n<\/p>\n Cost price of each pen =\u00a0$\u20b9 28$<\/p>\n $=$>\u00a0 Cost price of total pens = 28n<\/p>\n Selling price of each pen = $\u20b9 40$<\/p>\n $=$>\u00a0 Selling price of total pens =\u00a040n<\/p>\n $\\therefore\\ $Profit percentage =\u00a0$\\frac{40n-28n}{28n}\\times100$ =\u00a0$\\frac{12n}{28n}\\times100$ = 42.85%<\/p>\n Hence, the correct answer is Option C<\/p>\n Question 15:\u00a0<\/b>A chair was purchased for $\u20b9 785$ and sold at a profit of 22%. What was the selling price?<\/p>\n a)\u00a0$\u20b9 857.9$<\/p>\n b)\u00a0$\u20b9 957.7$<\/p>\n c)\u00a0$\u20b9 987.4$<\/p>\n d)\u00a0$\u20b9 768.3$<\/p>\n 15)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Solution:<\/b><\/p>\n Given,<\/p>\n Cost Price of the chair =\u00a0$\u20b9 785$<\/p>\n Profit% = 22%<\/p>\n $=$>\u00a0 Profit =\u00a0$\\frac{22}{100}\\times785$<\/p>\n $\\therefore\\ $Selling Price = Cost Price + Profit =\u00a0$785+\\frac{22}{100}\\times785$ =\u00a0$\\frac{122}{100}\\times785$ =\u00a0$\u20b9 957.7$<\/p>\n Hence, the correct answer is Option B<\/p>\n Question 16:\u00a0<\/b>If the cost price of 25 articles is equal to the selling price of 35 articles find the profit\/loss percentage.<\/p>\n a)\u00a0Loss \u2014 28.57%<\/p>\n b)\u00a0Profit \u2014 28.57%<\/p>\n c)\u00a0Profit \u2014 18.93%<\/p>\n d)\u00a0Loss \u2014 18.93%<\/p>\n 16)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Solution:<\/b><\/p>\n Given,\u00a0cost price of 25 articles is equal to the selling price of 35 articles<\/p>\n Let the cost price of 25 articles = C<\/p>\n $=$>\u00a0 Cost price of 1 article =\u00a0$\\frac{C}{25}$<\/p>\n Selling price of 35 articles = C<\/p>\n $=$>\u00a0 Selling price of 1 article = $\\frac{C}{35}$<\/p>\n Loss = Cost price – Selling price = $\\frac{C}{25}-\\frac{C}{35}$ = $\\frac{10C}{25\\times35}$ = $\\frac{2C}{175}$<\/p>\n $\\therefore\\ $Loss% = $\\frac{\\frac{2C}{175}}{\\frac{C}{25}}\\times100$ = $\\frac{2\\times25}{175}\\times100$ = $28.57\\%$<\/p>\n Hence, the correct answer is Option A<\/p>\n Question 17:\u00a0<\/b>Sohan sold a plot for $\u20b9 2,55,000$ at a 15% loss. At what price should he sell the plot to gain a 10% profit?<\/p>\n a)\u00a0$\u20b9 3,00,000$<\/p>\n b)\u00a0$\u20b9 3,33,000$<\/p>\n c)\u00a0$\u20b9 3,30,000$<\/p>\n d)\u00a0$\u20b9 3,33,300$<\/p>\n 17)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Solution:<\/b><\/p>\n Let the cost price of the plot =\u00a0CP<\/p>\n Given, loss% = 15%<\/p>\n Selling price of the plot =\u00a0$\u20b9 2,55,000$<\/p>\n $=$> \u00a0$\\frac{85}{100}\\text{CP}=255000$<\/p>\n $=$> \u00a0$\\text{CP}=255000\\times\\frac{100}{85}$<\/p>\n $=$> \u00a0$\\text{CP}=\u20b9 300000$<\/p>\n When gain is 10%,<\/p>\n Selling price of the article =\u00a0$\\frac{110}{100}\\times300000=\u20b9 330000$<\/p>\n Hence, the correct answer is Option C<\/p>\n Question 18:\u00a0<\/b>A dealer marks his goods at 30% above the cost price. Then he allows 35% discount on it. What would be his loss percentage?<\/p>\n a)\u00a015.5%<\/p>\n b)\u00a016.5%<\/p>\n c)\u00a017.5%<\/p>\n d)\u00a018.5%<\/p>\n 18)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Solution:<\/b><\/p>\n Let the Cost Price = C.P<\/p>\n Given, dealer marked his goods at 30% above cost price<\/p>\n $=$>\u00a0 Marked Price (M.P) =\u00a0$\\frac{130}{100}$C.P =\u00a0$\\frac{13}{10}$C.P<\/p>\n Discount = 35%<\/p>\n $=$>\u00a0 Selling Price (S.P) =\u00a0$\\frac{65}{100}$M.P =\u00a0$\\frac{65}{100}\\times\\frac{13}{10}$C.P =\u00a0$\\frac{845}{1000}$C.P<\/p>\n $\\therefore\\ $Loss % = $\\frac{\\text{C.P}-\\text{S.P}}{\\text{C.P}}\\times100\\ $<\/p>\n $=\\frac{ \\text{C.P}-\\frac{845}{1000}\\ \\text{C.P}}{\\text{C.P}}\\times100\\ $<\/p>\n $=\\frac{155}{1000}\\times100\\ $<\/p>\n $=15.5$%<\/p>\n Hence, the correct answer is Option A<\/p>\n Question 19:\u00a0<\/b>The cost price of 33 books is the same as the selling price of \u2018x\u2019 books. If the profit is 10%, then the value of \u2018x\u2019 is :<\/p>\n a)\u00a030<\/p>\n b)\u00a020<\/p>\n c)\u00a040<\/p>\n d)\u00a010<\/p>\n 19)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Solution:<\/b><\/p>\n Let the cost price of 33 books = C<\/p>\n Cost price of 1 book = $\\frac{C}{33}$<\/p>\n Profit% = 10%<\/p>\n $=$>\u00a0 Selling price of 1 book =\u00a0$\\frac{110}{100}\\times\\frac{C}{33}=\\frac{C}{30}$<\/p>\n According to the problem,<\/p>\n Selling price of ‘$x$’ books = C<\/p>\n Selling price of 1 book =\u00a0$\\frac{C}{x}$<\/p>\n $=$> \u00a0$\\frac{C}{x}=\\frac{C}{30}$<\/p>\n $=$> \u00a0$x=30$<\/p>\n Hence, the correct answer is Option A<\/p>\n Question 20:\u00a0<\/b>In a 15% discount sale, the cost of a book is $\u20b9 2,150.$ What was the original price of the book? (Correct to two decimal places)<\/p>\n a)\u00a0$\u20b9 1,527.00$<\/p>\n b)\u00a0$\u20b9 2,500.00$<\/p>\n c)\u00a0$\u20b9 2,529.41$<\/p>\n d)\u00a0$\u20b9 2,250.50$<\/p>\n 20)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Solution:<\/b><\/p>\n Given,<\/p>\n Cost Price of the book =\u00a0$\u20b9 2,150$<\/p>\n Disount% = 15%<\/p>\n Let the Marked Price = MP<\/p>\n $=$> \u00a0$\\frac{85}{100}\\times \\text{MP}=2150$<\/p>\n $=$> \u00a0$\\text{MP}=\u20b9 2,529.41$<\/p>\n $\\therefore\\ $Original Price of the book = $\u20b9 2,529.41$<\/p>\n Hence, the correct answer is Option C<\/p>\n Question 21:\u00a0<\/b>If the gain is one-fifth of the selling price, then the gain percentage is:<\/p>\n a)\u00a016%<\/p>\n b)\u00a020%<\/p>\n c)\u00a080%<\/p>\n d)\u00a025%<\/p>\n 21)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Solution:<\/b><\/p>\n Let the Cost Price = CP<\/p>\n Selling Price = SP<\/p>\n Given, gain is one-fifth of the selling price<\/p>\n $=$>\u00a0 Gain = $\\frac{\\text{SP}}{5}$<\/p>\n $=$> \u00a0$\\text{SP}-\\text{CP}=\\frac{\\text{SP}}{5}$<\/p>\n $=$> \u00a0$\\text{CP}=\\text{SP}-\\frac{\\text{SP}}{5}$<\/p>\n $=$> \u00a0$\\text{CP}=\\frac{4\\text{SP}}{5}$<\/p>\n $\\therefore\\ $Gain% =\u00a0$\\frac{\\text{Gain}}{\\text{CP}}\\times100$<\/p>\n $=\\frac{\\frac{\\text{SP}}{5}}{\\frac{4\\text{SP}}{5}}\\times100$<\/p>\n $=\\frac{1}{4}\\times100$<\/p>\n $=25\\%$<\/p>\n Hence, the correct answer is Option D<\/p>\n Question 22:\u00a0<\/b>A shopkeeper allows a discount of 20% on an article and still makes a profit of 25%. What does he pay for an article whose marked price is $\u20b9800$?<\/p>\n a)\u00a0$\u20b9 492$<\/p>\n b)\u00a0$\u20b9 800$<\/p>\n c)\u00a0$\u20b9 512$<\/p>\n d)\u00a0$\u20b9 640$<\/p>\n 22)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Solution:<\/b><\/p>\n Given, Marked Price (MP) =\u00a0$\u20b9800$<\/p>\n Discount% = 20%<\/p>\n $=$> \u00a0Selling Price (SP) =\u00a0$\\frac{80}{100}\\times800=\u20b9640$<\/p>\n Profi% = 25%<\/p>\n Let cost paid by the shopkeeper to purchase the article (Cost Price) = CP<\/p>\n $=$> \u00a0$\\frac{125}{100}\\text{CP}=640$<\/p>\n $=$> \u00a0$\\text{CP}=\u20b9512$<\/p>\n Hence, the correct answer is Option C<\/p>\n Question 23:\u00a0<\/b>Salma buys an article and then sells it for $\u20b9 810.$ If she loses 10%, then at what price should she sell it to gain 4%?<\/p>\n a)\u00a0$\u20b9 900$<\/p>\n b)\u00a0$\u20b9 936$<\/p>\n c)\u00a0$\u20b9 864$<\/p>\n d)\u00a0$\u20b9 729$<\/p>\n 23)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Solution:<\/b><\/p>\n Given,<\/p>\n Selling Price of the article = $\u20b9 810$<\/p>\n Loss% = 10%<\/p>\n Let the Cost Price of the article = C.P<\/p>\n $=$>\u00a0\u00a0$\\frac{90}{100}\\text{C.P}$ = $810$<\/p>\n $=$> \u00a0$\\text{C.P}=\u20b9 900$<\/p>\n When gain is 4% then<\/p>\n Selling Price of the article =\u00a0$\\frac{104}{100}\\text{C.P}=\\frac{104}{100}\\times900=\u20b9 936$<\/p>\n Hence, the correct answer is Option B<\/p>\n Question 24:\u00a0<\/b>A mobile phone was sold for \u20b931,500 after giving two successive discounts of 30% and 10%, respectively. What was the marked price of the mobile?<\/p>\n a)\u00a0\u20b955,000<\/p>\n b)\u00a0\u20b950,000<\/p>\n c)\u00a0\u20b935,000<\/p>\n d)\u00a0\u20b952,500<\/p>\n 24)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Solution:<\/b><\/p>\n Given,<\/p>\n Selling Price of the mobile phone = $\u20b931,500$<\/p>\n Let the Marked Price of the mobile phone = $\\text{M.P}$<\/p>\n Price after 30% discount =\u00a0$\\frac{70}{100}\\times \\text{M.P}$<\/p>\n Selling Price after 10% discount =\u00a0$\\frac{90}{100}\\times\\frac{70}{100}\\times \\text{M.P}$<\/p>\n $=$> \u00a0$\\frac{90}{100}\\times\\frac{70}{100}\\times \\text{M.P}=31500$<\/p>\n $=$> \u00a0$\\text{M.P}=\u20b950000$<\/p>\n $\\therefore\\ $Marked Price of the mobile phone = $\u20b950,000$<\/p>\n Hence, the correct answer is Option B<\/p>\n Question 25:\u00a0<\/b>If the marked price of a television set is $\u20b9 24,500,$ then its selling price after a 12% discount on it is:<\/p>\n a)\u00a0$\u20b9 21,460$<\/p>\n b)\u00a0$\u20b9 21,640$<\/p>\n c)\u00a0$\u20b9 21,650$<\/p>\n d)\u00a0$\u20b9 21,560$<\/p>\n 25)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Solution:<\/b><\/p>\n Given,<\/p>\n Marked Price of the television set = $\u20b9 24,500$<\/p>\n Discount% = 12%<\/p>\n $=$> Discount =\u00a0$\\frac{12}{100}\\times24500=2940$<\/p>\n $\\therefore\\ $Selling Price = 24,500 – 2940 =\u00a0$\u20b9 21,560$<\/p>\n Hence, the correct answer is Option D<\/p>\n