{"id":212084,"date":"2022-06-10T15:29:14","date_gmt":"2022-06-10T09:59:14","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=212084"},"modified":"2022-06-10T15:29:14","modified_gmt":"2022-06-10T09:59:14","slug":"coding-decoding-questions-pdf-for-mah-cet","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/coding-decoding-questions-pdf-for-mah-cet\/","title":{"rendered":"Coding Decoding Questions PDF for MAH-CET"},"content":{"rendered":"

Here you can download a free Coding-Decoding questions PDF with answers for MAH MBA CET 2022 by Cracku. These are some tricky questions in the MAH MBA CET 2022 exam that you need to find Coding-Decoding answers for the given questions. These questions will help you to make practice and solve the Coding and Decoding<\/strong>\u00a0questions in the MAH MBA CET exam. Utilize this best PDF practice set<\/strong> which is included answers in detail. Click on the below link to download the Coding-Decoding MCQ<\/strong> PDF for MBA-CET 2022 for free.<\/p>\n

Download Coding Decoding Questions for MAH-CET<\/a><\/p>\n

Enroll to MAH-CET 2022 Crash Course<\/a><\/p>\n

Instructions<\/b><\/p>\n

Study the following information and answer the questions given below:<\/p>\n

In a certain code, the symbol for 0 (zero) is @ and for 1 is $. There are no other symbols for all other numbers greater than one. The numbers greater than 1 are to be written only by using the two symbols given above. The value of the symbol for 1, doubles itself every time it shifts one place to the left. Study the following example
\n\u20180\u2019 is written as @
\n\u20181\u2019 is written as $
\n\u20182\u2019 is written as $@
\n\u20183\u2019 is written as $
\n\u20184\u2019 is written as $@@ and so on<\/p>\n

Question 1:\u00a0<\/b>Which of the following numbers will be represented by $@@@$ ?<\/p>\n

a)\u00a022<\/p>\n

b)\u00a031<\/p>\n

c)\u00a014<\/p>\n

d)\u00a017<\/p>\n

e)\u00a0None of these<\/p>\n

1)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Solution:<\/b><\/p>\n

The pattern followed is that the numbers are given in binary form. Eg\u00a0:- 2 is written as ’10’ and 3 as ’11’ and so on.<\/p>\n

$@@@$ represents = 10001 which is binary code for :<\/p>\n

= $2^0+2^4=(1+16)=$\u00a017<\/strong><\/p>\n

=> Ans – (D)<\/p>\n

Question 2:\u00a0<\/b>Which of the following will represent the value of the product 3 \u00d7 3 + 1 ?<\/p>\n

a)\u00a0$@$<\/p>\n

b)\u00a0$@$@<\/p>\n

c)\u00a0$@@$<\/p>\n

d)\u00a0$$<\/p>\n

e)\u00a0None of these<\/p>\n

2)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Solution:<\/b><\/p>\n

The pattern followed is that the numbers are given in binary form. Eg\u00a0:- 2 is written as ’10’ and 3 as ’11’ and so on.<\/p>\n

Value of = $3\\times3+1=9+1=10$<\/p>\n

Thus,\u00a0binary code for 10 = ‘1010’ represented as = $@$@<\/strong><\/p>\n

=> Ans – (B)<\/p>\n

Question 3:\u00a0<\/b>Which of the following numbers will be represented by $@$ ?<\/p>\n

a)\u00a08<\/p>\n

b)\u00a011<\/p>\n

c)\u00a013<\/p>\n

d)\u00a012<\/p>\n

e)\u00a0None of these<\/p>\n

3)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Solution:<\/b><\/p>\n

The pattern followed is that the numbers are given in binary form. Eg\u00a0:- 2 is written as ’10’ and 3 as ’11’ and so on.<\/p>\n

$@$ represents = 1101 which is binary code for :<\/p>\n

= $2^0+2^2+2^3=(1+4+8)=$\u00a013<\/strong><\/p>\n

=> Ans – (C)<\/p>\n

Question 4:\u00a0<\/b>Which of the following will represent 8 ?<\/p>\n

a)\u00a0$@@<\/p>\n

b)\u00a0@$@<\/p>\n

c)\u00a0$@$@<\/p>\n

d)\u00a0@@$<\/p>\n

e)\u00a0None of these<\/p>\n

4)\u00a0Answer\u00a0(E)<\/strong><\/p>\n

Solution:<\/b><\/p>\n

The pattern followed is that the numbers are given in binary form. Eg\u00a0:- 2 is written as ’10’ and 3 as ’11’ and so on.<\/p>\n

Thus, binary code for 8 = ‘1000’ represented as = $@@@<\/strong><\/p>\n

=> Ans – (E)<\/p>\n

Question 5:\u00a0<\/b>Which of the following will represent 11 ?<\/p>\n

a)\u00a0$@$<\/p>\n

b)\u00a0@$@<\/p>\n

c)\u00a0$@@<\/p>\n

d)\u00a0$@$@@<\/p>\n

e)\u00a0None of these<\/p>\n

5)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Solution:<\/b><\/p>\n

The pattern followed is that the numbers are given in binary form. Eg\u00a0:- 2 is written as ’10’ and 3 as ’11’ and so on.<\/p>\n

Thus, binary code for 11 = ‘1011’ represented as =\u00a0$@$<\/strong><\/p>\n

=> Ans – (A)<\/p>\n

Instructions<\/b><\/p>\n

Ravi ,Suresh ,And asif are in control of the following number -letter-symbol series respectively.
\nRavi : 2 & S * 9 P T B \u20a4 8 Q \u0394 6
\nSuresh: \u29bb 1 \u2751 F @ V 4 $ \u00a9 M T D \u21d4
\nAsif: G 3 H # K N \u26ab 5 R = 7 W Y<\/p>\n

Take Free MAH-CET mock tests here<\/a><\/p>\n

Question 6:\u00a0<\/b>Which of the following is true?<\/p>\n

a)\u00a0The total number of symbols immediately preceded by numbers in Ravi\u2019s series are equal to the total number of letters immediately preceded by numbers in Suresh’s series<\/p>\n

b)\u00a0The total number of symbols immediately followed by numbers in Asif\u2019s series are less than the total number of letters immediately preceded by numbers in Ravi\u2019s series.<\/p>\n

c)\u00a0The total number of letters immediately following symbol in Ravi\u2019s series are more than the total number of symbols immediately preceded by fix numbers in Suresh\u2019s series.<\/p>\n

d)\u00a0The total number of symbols immediately preceding letter in Ravi\u2019s series are less than the total number of symbols immediately followed by numbers in Asif\u2019s series.<\/p>\n

e)\u00a0The total number of symbols in Ravi\u2019s series is more than the total number of symbols in Suresh\u2018s series.<\/p>\n

6)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Solution:<\/b><\/p>\n

(A) : (number) (symbol) in Ravi’s series = 1<\/p>\n

(number) (letter) in Suresh’s series = 0<\/p>\n

(B) : (symbol) (number) in Asif’s series = 2<\/p>\n

(number) (letter) in Ravi’s series = 2<\/p>\n

(C) : (symbol) (letter)\u00a0in Ravi’s series = 1<\/p>\n

(number) (symbol) in Suresh’s series = 2<\/p>\n

(D) : (symbol) (letter) in Ravi’s series = 1<\/p>\n

(symbol) (number)\u00a0in Asif\u2019s series = 2<\/p>\n

=> Ans – (D)<\/p>\n

Question 7:\u00a0<\/b>If all the numbers from Asif’s series, all the letters from Suresh’s series and all the symbols from Ravi’s series are respectively arranged in the same given order one after the other from the left end, which of the following will be the seventh to the right of the eleventh element from your right?<\/p>\n

a)\u00a0D<\/p>\n

b)\u00a0M<\/p>\n

c)\u00a0\u00a9<\/p>\n

d)\u00a0\u0394<\/p>\n

e)\u00a0None of these<\/p>\n

7)\u00a0Answer\u00a0(E)<\/strong><\/p>\n

Solution:<\/b><\/p>\n

If all the numbers from Asif’s series, all the letters from Suresh’s series and all the symbols from Ravi’s series are respectively arranged in the same given order one after the other from the left end, then\u00a0:<\/p>\n

Arrangement\u00a0: 3 5<\/strong> 7 \u00a0F V M T D \u00a0&<\/strong> * \u20a4 \u0394<\/p>\n

11th element from right end = 5<\/p>\n

7th to the right of 5 = &<\/p>\n

=> Ans – (E)<\/p>\n

Question 8:\u00a0<\/b>If each symbol which immediately preceded a number in Ravi’s series, each number which immediately follows a letter in Suresh’s series, and each letter which immediately precedes a symbol in Asif’s series are selected, what will be total number of these elements?<\/p>\n

a)\u00a07<\/p>\n

b)\u00a08<\/p>\n

c)\u00a06<\/p>\n

d)\u00a05<\/p>\n

e)\u00a0None of these<\/p>\n

8)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Solution:<\/b><\/p>\n

In Ravi’s series, we need to find\u00a0= (symbol) (number)<\/p>\n

Ravi : 2 & S * 9<\/strong> P T B \u20a4 8<\/strong> Q \u0394 6<\/strong><\/p>\n

In Suresh’s = (letter) (number)<\/p>\n

Suresh: \u29bb 1 \u2751 F @ V 4<\/strong> $ \u00a9 M T D \u21d4<\/p>\n

In Asif’s = (letter)\u00a0(symbol)<\/p>\n

Asif: G 3 H #<\/strong> K N \u26ab<\/strong> 5 R =<\/strong> 7 W Y<\/p>\n

Thus, there are 7 such elements.<\/p>\n

=> Ans – (A)<\/p>\n

Question 9:\u00a0<\/b>If from each series, amongst letters\/numbers\/symbols the one having highest members is sorted out and then arranged in the descending order on the basis of the number of elements they have, which of the following will indicate the correct descending order?<\/p>\n

a)\u00a0Asif-letters, Suresh-symbols, Ravi-symbols<\/p>\n

b)\u00a0Asif-letters, Suresh-symbols, Ravi-letters<\/p>\n

c)\u00a0Ravi-numbers, Suresh-letters, Asif-symbols<\/p>\n

d)\u00a0Ravi-letters, Suresh-symbols, Asif-letters<\/p>\n

e)\u00a0None of these<\/p>\n

9)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Solution:<\/b><\/p>\n

Elements in Ravi’s series are\u00a0:<\/p>\n

Numbers = 4 , Symbols = 4 , Letters = 5<\/strong><\/p>\n

Elements in Suresh’s series are\u00a0:<\/p>\n

Numbers = 2 , Symbols = 6<\/strong> , Letters =\u00a05<\/p>\n

Elements in Asif’s series are\u00a0:<\/p>\n

Numbers = 3 , Symbols = 3 , Letters =\u00a07<\/strong><\/p>\n

$\\therefore$ The correct descending order is :\u00a0Asif-letters, Suresh-symbols, Ravi-letters<\/p>\n

=> Ans – (B)<\/p>\n

Question 10:\u00a0<\/b>Starting from the left end & following the given order in each series, if a group of three elements is formed by taking symbol from Suresh\u2019s series, number from Ravi\u2019s series & letter from Asif\u2019s series taking each symbol, number and letter only once, which of the following will be the elements of the 4th such group formed?<\/p>\n

a)\u00a0$8T<\/p>\n

b)\u00a0\u00a96R<\/p>\n

c)\u00a0$6N<\/p>\n

d)\u00a0*1V<\/p>\n

e)\u00a0None of these<\/p>\n

10)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Solution:<\/b><\/p>\n

If a group of three elements is formed by taking symbol from Suresh\u2019s series, number from Ravi\u2019s series & letter from Asif\u2019s series, then\u00a0:<\/p>\n

<\/figure>\n

Thus, elements of 4th group =\u00a0$6N<\/strong><\/p>\n

=> Ans – (C)<\/p>\n

Take MAH-CET Mock Tests<\/a><\/p>\n

Enroll to CAT 2022 course<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"

Here you can download a free Coding-Decoding questions PDF with answers for MAH MBA CET 2022 by Cracku. These are some tricky questions in the MAH MBA CET 2022 exam that you need to find Coding-Decoding answers for the given questions. These questions will help you to make practice and solve the Coding and Decoding\u00a0questions […]<\/p>\n","protected":false},"author":32,"featured_media":212087,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_mi_skip_tracking":false,"footnotes":""},"categories":[169,3167,125,4409],"tags":[4253,5420],"class_list":{"0":"post-212084","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-downloads","8":"category-downloads-en","9":"category-featured","10":"category-mah-mba-cet","11":"tag-coding-decoding","12":"tag-mah-cet-2022"},"better_featured_image":{"id":212087,"alt_text":"Coding Decoding Questions","caption":"Coding Decoding Questions","description":"Coding Decoding 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