The only trick to cracking this section is just practising the different types of chart questions. Use this Data Interpretation chart questions with solution PDF for practising. MBA CET is a speed-based exam<\/strong> so increase your speed of solving the question in this section by practising the question in given below PDF.<\/p>\n Click on the below link to download the data interpretation chart questions PDF\u00a0<\/strong><\/p>\n Download Data Interpretation Chart Questions for MAH-CET PDF<\/a><\/p>\n Enroll to MAH-CET Crash Course<\/a><\/p>\n Instructions<\/b><\/p>\n Read the information given below and answer the 3 associated questions. The following, however, are known: ii) China has the highest agriculture sector GDP, valued at US $1 trillion, followed respectively by the USA and India Question 1:\u00a0<\/b>Which of the following information, when considered in addition to the given information, does not allow us to completely identify the nine nations in the graph?<\/p>\n a)\u00a0Germany\u2019s industry GDP is US $1.2 trillion<\/p>\n b)\u00a0The nation ranked fourth in terms of agriculture GDP has its agriculture GDP valued at US $150 billion<\/p>\n c)\u00a0In terms of percentage contribution to the respective nations\u2019 GDP, France and Japan\u2019s agriculture sectors contribute the same<\/p>\n d)\u00a0Japan\u2019s industry GDP is US $1.25 trillion<\/p>\n e)\u00a0Both Japan\u2019s and Germany\u2019s industry GDPs are more than US $1 trillion<\/p>\n 1)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Solution:<\/b><\/p>\n FRom ii, China is F.<\/p>\n FRom iv and v, India must be A, Brazil must be G and Russia must be B.<\/p>\n India’s GDP due to agriculture = 17% of 2 trillion =0.34 trillion.<\/p>\n FRom i, USA GDP due to agriculture> 0.34 trillion and <1 trillion i.e. it’s percentage must be >2% and less than 5.8%<\/p>\n So, USA can be C\/E\/H.<\/p>\n From point 3, UK must be D and France must be H=> U.S.A\u00a0 must be C\/E.<\/p>\n Now, Germany and Japan can be C or I.<\/p>\n Option A:\u00a0If Germany is C, then its GDP will be 1 but given its gdp is 1.2 So, C is not Germany. If Germany is I, then its GDP will be 1.2trillion. Hence, Germany is I => Japan is C\/E and USA is C\/E. If USA is C then its GDP due to agriculture is not 3rd highest. So, USA is E and Japan is C.<\/p>\n Option A is correct.<\/p>\n Question 2:\u00a0<\/b>Based on the given information, which of the following CANNOT be ruled out?<\/p>\n a)\u00a0US is Nation I<\/p>\n b)\u00a0Russia is Nation G<\/p>\n c)\u00a0China is Nation C<\/p>\n d)\u00a0Japan is Nation E<\/p>\n e)\u00a0India is Nation B<\/p>\n 2)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Solution:<\/b><\/p>\n FRom ii, China is F.<\/p>\n FRom iv and v, India must be A, Brazil must be G and Russia must be B.<\/p>\n India’s GDP due to agriculture = 17% of 2 trillion =0.34 trillion.<\/p>\n FRom i, USA GDP due to agriculture> 0.34 trillion and <1 trillion i.e. it’s percentage must be >2% and less than 5.8%<\/p>\n So, USA can be C\/E\/H.<\/p>\n From point 3, UK must be D and France must be H=> U.S.A must be C\/E.<\/p>\n Now, Germany and Japan can be C or I or E.<\/p>\n .’. Everything except option D can be ruled out.<\/p>\n Question 3:\u00a0<\/b>Based on the given information, how many nations can be uniquely identified?<\/p>\n a)\u00a06<\/p>\n b)\u00a09<\/p>\n c)\u00a03<\/p>\n d)\u00a02<\/p>\n e)\u00a07<\/p>\n 3)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Solution:<\/b><\/p>\n FRom ii, China<\/strong> is F.<\/p>\n FRom iv and v, India<\/strong> must be A, Brazil<\/strong> must be G and Russia<\/strong> must be B.<\/p>\n India’s GDP due to agriculture = 17% of 2 trillion =0.34 trillion.<\/p>\n FRom i, USA GDP due to agriculture> 0.34 trillion and <1 trillion i.e. it’s percentage must be >2% and less than 5.8%<\/p>\n So, USA can be C\/E\/H.<\/p>\n From point 3, UK<\/strong> must be D and France<\/strong> must be H=> U.S.A must be C\/E.<\/p>\n Now, Germany and Japan can be C or I.<\/p>\n 6\u00a0nations can be uniquely identified.<\/p>\n Instructions<\/b><\/p>\n The Ministry of Home Affairs is analysing crimes committed by foreigners in different states and union territories (UT) of India. All cases refer to the ones registered against foreigners in 2016.<\/p>\n The number of cases – classified into three categories: IPC crimes, SLL crimes and other crimes – for nine states\/UTs are shown in the figure below. These nine belong to the top ten states\/UTs in terms of the total number of cases registered. The remaining state (among top ten) is West Bengal, where all the 520 cases registered were SLL crimes.<\/p>\n The table below shows the ranks of the ten states\/UTs mentioned above among ALL states\/UTs of India in terms of the number of cases registered in each of the three category of crimes. A state\/UT is given rank r for a category of crimes if there are (r\u20101) states\/UTs having a larger number of cases registered in that category of crimes. For example, if two states have the same number of cases in a category, and exactly three other states\/UTs have larger numbers of cases registered in the same category, then both the states are given rank 4 in that category. Missing ranks in the table are denoted by *.<\/p>\n Question 4:\u00a0<\/b>What is the sum of the ranks of Delhi in the three categories of crimes?<\/p>\n 4)\u00a0Answer:\u00a05<\/b><\/p>\n View Video Solution<\/a><\/p>\n Solution:<\/b><\/p>\n The data can be tabulated as follows(approximately):<\/p>\n The data can be tabulated as follows(approximately):<\/p>\n The rank of Delhi in IPC crimes should be 1 because the states which are not in table cannot crime more than that of Telangana which is 24-25.<\/p>\n Similarly Delhi Rank in Other crimes will be 1.<\/p>\n Now in SLL crimes clearly West Bengal has rank 1. It is given that Karnataka has rank 2. The rank 3 can go to either Goa, Delhi and Maharashtra but Goa and Maharashtra already have rank 4. So Delhi will have rank 3. Also no state outside of the table can be ranked 3 in SLL crimes as maximum number of crime should be less than that of Telangana(24-25). Here the number of\u00a0SLL crimes is 35-36.<\/p>\n Hence the sum of the ranks = 1+3+1=5<\/p>\n Question 5:\u00a0<\/b>Which of the following is DEFINITELY true about the ranks of states\/UT in the \u2018other crimes\u2019 category? a)\u00a0both i) and ii)<\/p>\n b)\u00a0only ii)<\/p>\n c)\u00a0neither i) , nor ii)<\/p>\n d)\u00a0only i)<\/p>\n 5)\u00a0Answer\u00a0(A)<\/strong><\/p>\n View Video Solution<\/a><\/p>\n Solution:<\/b><\/p>\n The data can be tabulated as follows(approximately):<\/p>\n From the table, the rank of Tamilnadu in other crimes is 2. The states which are not in the table will have crimes less than Telangana(i.e 24-25)<\/p>\n From the table the rank of Pudducherry in other crimes\u00a0is 3.<\/p>\n Question 6:\u00a0<\/b>In the two states where the highest total number of cases are registered, the ratio of the total number of cases in IPC crimes to the total number in SLL crimes is closest to<\/p>\n a)\u00a03 : 2<\/p>\n b)\u00a019 : 20<\/p>\n c)\u00a011 : 10<\/p>\n d)\u00a01 : 9<\/p>\n 6)\u00a0Answer\u00a0(D)<\/strong><\/p>\n View Video Solution<\/a><\/p>\n Solution:<\/b><\/p>\n The data can be tabulated as follows(approximately):<\/p>\n The highest cases are registered in West Bengal and Delhi.<\/p>\n The total number of IPC crimes = 63-64<\/p>\n The total number of SLL crimes = 520+35-36 = 555-556<\/p>\n Hence the ratio = (63-64)\/(555-556)\u00a0 = 0.11\u00a0 (Approximately)\u00a0 \u00a0= 1:9<\/p>\n Question 7:\u00a0<\/b>What is the rank of Kerala in the \u2018IPC crimes\u2019 category?<\/p>\n 7)\u00a0Answer:\u00a05<\/b><\/p>\n View Video Solution<\/a><\/p>\n Solution:<\/b><\/p>\n The data can be tabulated as follows(approximately):<\/p>\n Rank of Delhi in IPC crimes category = 1, The rank of Karnataka and Maharashtra is 3(from table), then the rank of Goa can only be 2.<\/p>\n The rank of Telangana is 6 which has less |IPC crimes than Kerala, which means the rank of Kerala can be less than or equal to 5.<\/p>\n Now, there are two states with 3 ranks, so there will be no rank 4, there can only be rank 5 which is Kerala.<\/p>\n Instructions<\/b><\/p>\n Answer the questions with the given information and the data.<\/p>\n The figures given below show the amount of work distribution (in operational hours) for a toy manufacturing company having manufacturing plants in Chennai and Kanpur. Each plant carries out six activities. Planned operational cost per hour of Chennai and Kanpur plants are\u00a0\u20b9 250 and %\u20b9300 respectively. However, the actual operational cost per hour is\u00a0\u20b9 270 in Chennai and\u00a0\u20b9 315 in Kanpur.<\/p>\n Cost Difference (in %)=Absolute ((Actual Cost \u2014- Planned Cost) \/ Planned Cost) x 100<\/p>\n Question 8:\u00a0<\/b>Whichof following activities has maximum cost difference in Kanpur Plant ?<\/p>\n a)\u00a0Activity 1<\/p>\n b)\u00a0Activity 3<\/p>\n c)\u00a0Activity 4<\/p>\n d)\u00a0Activity 5<\/p>\n 8)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Solution:<\/b><\/p>\n ACtivity 1 : 50\/100 * 100 = 50%<\/p>\n Activity 3 : 100\/150 *100= 66.6%<\/p>\n Activity 4 : 50\/100 *100 = 50%<\/p>\n Activity 5 = 50\/250 * 100 = 20%<\/p>\n Activity 3 is the correct answer.<\/p>\n Question 9:\u00a0<\/b>In how many activities plant in Chennai could meet at least 50% shortfall in the actual operational hours compared to planned operational hours of plant in Kanpur ?<\/p>\n a)\u00a01<\/p>\n b)\u00a02<\/p>\n c)\u00a03<\/p>\n d)\u00a04<\/p>\n 9)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Solution:<\/b><\/p>\n In Activity 1, 50% shortfall of planned and actual in Kanpur is 25. Excess in chennai is 25. Hence this activity is counted.<\/p>\n In Activity 2 there is no shortfall<\/p>\n In Activity 3, the 50% shortfall is 50. Excess in chennai is 28. Hence this is incorrect<\/p>\n In Activity 4 and 5 there is no shortfall<\/p>\n In Activity 6 the 50% shortfall is 25. Excess in Chennai is 78. Hence, this activity is counted.<\/p>\n Question 10:\u00a0<\/b>Overall Cost difference in Chennai plant is approximately :<\/p>\n a)\u00a039%<\/p>\n b)\u00a041%<\/p>\n c)\u00a065%<\/p>\n d)\u00a070%<\/p>\n 10)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Solution:<\/b><\/p>\n Planned cost in chennai = 1032 * 250=258000<\/p>\n Actual cost in chennai = 1350 * 270 = 364500<\/p>\n Cost difference = (106500\/258000)*100 = 41%<\/p>\n Take Free MAH-CET mock tests here<\/a><\/p>\n Question 11:\u00a0<\/b>In how manyactivities plant in Chennai has higher planned operational hours as compared to plant in Kanpur ?<\/p>\n a)\u00a01<\/p>\n b)\u00a02<\/p>\n c)\u00a03<\/p>\n d)\u00a04<\/p>\n 11)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Solution:<\/b><\/p>\n Chennai has more planned operational hours in Activity 2 and 6.<\/p>\n Instructions<\/b><\/p>\n Answer the questions with the given information and the graph. Question 12:\u00a0<\/b>In which year, highest annual percentage change in StyleSpend is recorded ?<\/p>\n a)\u00a02015<\/p>\n b)\u00a02014<\/p>\n c)\u00a02013<\/p>\n d)\u00a02011<\/p>\n 12)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Solution:<\/b><\/p>\n 2015 =\u00a0(450-300)\/300 = 0.5<\/p>\n 2014 = (650-300)\/650 =0.54<\/p>\n 2013 = (620-350)\/350 = 0.77<\/p>\n 2011 =\u00a0 (350-300)\/350= 0.14<\/p>\n The highest percentage change is in the year 2013<\/p>\n Question 13:\u00a0<\/b>In which year, ratio of percentage annual change in Style_Spend to percentage annual change in Sentiment_Index is highest ?<\/p>\n a)\u00a02011<\/p>\n b)\u00a02012<\/p>\n c)\u00a02014<\/p>\n d)\u00a02017<\/p>\n 13)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Solution:<\/b><\/p>\n 2015 = (450-300)\/300 = 0.5<\/p>\n 2014 = (650-300)\/650 =0.54<\/p>\n 2013 = (620-350)\/350 = 0.77<\/p>\n 2011 Style spend = (350-300)\/350= 0.14 2012 Style spend = 50\/300 = 1\/6 2014 Style spend =\u00a0(650-300)\/650 =0.54 2017 style spend = 100\/450 Option C is the correct answer.<\/p>\n Question 14:\u00a0<\/b>From the years mentioned below, in which year Food_Spend as a proportion of Style_Spend is lowest ?<\/p>\n a)\u00a02012<\/p>\n b)\u00a02013<\/p>\n c)\u00a02015<\/p>\n d)\u00a02016<\/p>\n 14)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Solution:<\/b><\/p>\n 2012 :\u00a0520\/350 = 1.49<\/p>\n 2013 : 700\/650 = 1.07<\/p>\n 2015 : 520\/450 = 1.15<\/p>\n 2016 :\u00a0520 \/ 450= 1.15<\/p>\n 2013 is the lowest and hence it is the correct answer.<\/p>\n Question 15:\u00a0<\/b>From the years mentioned below, in which year total of Food_Spend and StyleSpend as a proportion of Sentiment_Index is lowest ?<\/p>\n a)\u00a02011<\/p>\n b)\u00a02013<\/p>\n c)\u00a02016<\/p>\n d)\u00a02017<\/p>\n 15)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Solution:<\/b><\/p>\n 2011 :\u00a0910\/390= 2.33<\/p>\n 2013: 1330\/750= 1.77<\/p>\n 2016: 970\/550 = 1.75<\/p>\n 2017: 960\/370 = 2.6<\/p>\n Option C , 2016 is the correct answer.<\/p>\n Instructions<\/b><\/p>\n The break-up of the students in a university by subject major is given in the polar pie-chart. The bar chart shows the number of students who major in physics by geographic location.<\/p>\n Question 16:\u00a0<\/b>If the proportion of physics majors who are from Delhi is the same as the proportion of engineering majors who are from Delhi, how many engineering majors are from Delhi?<\/p>\n a)\u00a022<\/p>\n b)\u00a026<\/p>\n c)\u00a018<\/p>\n d)\u00a020<\/p>\n e)\u00a024<\/p>\n 16)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Solution:<\/b><\/p>\n Total number of Physics major from all locations = 225<\/p>\n $\\therefore $\u00a0Total number of students =\u00a0$\\frac{225}{0.18}$ = 1250<\/p>\n Number of engineering students = 20% * 1250 = 250<\/p>\n So, basis the given condition we have<\/p>\n $\\frac{18}{225}$=$\\frac{x}{250}$<\/p>\n => x = 20<\/p>\n Hence, option D<\/p>\n (Note: This question has been presented as was in the actual paper and has been solved by the aid of visual inference)<\/p>\n Question 17:\u00a0<\/b>How many students major in chemistry?<\/p>\n a)\u00a0200<\/p>\n b)\u00a0175<\/p>\n c)\u00a0170<\/p>\n d)\u00a0190<\/p>\n e)\u00a0180<\/p>\n 17)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Solution:<\/b><\/p>\n Total number of Physics major from all locations = 225<\/p>\n $\\therefore $\u00a0Total number of students =\u00a0$\\frac{225}{0.18}$ = 1250<\/p>\n Number of students majoring in chemistry = 14 % * 1250 = 175<\/p>\n Hence, option B.<\/p>\n Question 18:\u00a0<\/b>12% of all students are from Chennai. What is the largest possible percentage of economics students that can be from Chennai, rounded o\ufb00 to the nearest integer?<\/p>\n a)\u00a073%<\/p>\n b)\u00a077%<\/p>\n c)\u00a075%<\/p>\n d)\u00a071%<\/p>\n e)\u00a069%<\/p>\n 18)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Solution:<\/b><\/p>\n Total number of Physics major from all locations = 225<\/p>\n $\\therefore $\u00a0Total number of students =\u00a0$\\frac{225}{0.18}$ = 1250<\/p>\n Students from Chennai = 12% * 1250 = 150<\/p>\n Given, number of Physics majors from chennai = 40<\/p>\n $\\therefore $ maximum possible number of economic students from chennai = 150 – 40 = 110<\/p>\n Maximum percentage of students =\u00a0$\\frac{110}{150}$ * 100 % = 73.33 %<\/p>\n Hence, option A.<\/p>\n Instructions<\/b><\/p>\n The multi-layered pie-chart below shows the sales of LED television sets for a big retail electronics outlet during 2016 and 2017. The outer layer shows the monthly sales during this period, with each label showing the month followed by sales figure of that month. For some months, the sales figures are not given in the chart. The middle-layer shows quarterwise aggregate sales figures (in some cases, aggregate quarter-wise sales numbers are not given next to the quarter). The innermost layer shows annual sales. It is known that the sales figures during the three months of the second quarter (April, May, June) of 2016 form an arithmetic progression, as do the three monthly sales figures in the fourth quarter (October, November, December) of that year.<\/p>\n <\/p>\n <\/p>\n Question 19:\u00a0<\/b>During which month was the percentage increase in sales from the previous month\u2019s sales the highest?<\/p>\n a)\u00a0March of 2017<\/p>\n b)\u00a0October of 2017<\/p>\n c)\u00a0March of 2016<\/p>\n d)\u00a0October of 2016<\/p>\n 19)\u00a0Answer\u00a0(B)<\/strong><\/p>\n View Video Solution<\/a><\/p>\n Solution:<\/b><\/p>\n We have been given details about the quarterly sales figures. Also, we have been given details about the sales figures every month. Some of the data are missing and some additional conditions have been given in the question. Let us try to complete the pie chart as much as possible with the data available to us.<\/p>\n It is known that the sales figures during the three months of the second quarter (April, May, June) of 2016 form an arithmetic progression.<\/p>\n We know that the sales in April is 40.<\/p>\n Let the sales in May be 40+x and the sales in June be 40+2x.<\/p>\n We know that the total sales in Q2 is 150.<\/p>\n => 40 + 40 + x + 40 + 2x = 150 Therefore, sales in May 2016 = 40 + 10 = 50<\/p>\n Sales in June 2016 = 40 + 20 = 60<\/p>\n Similarly, it has been given that the sales in October, November, and December 2016 form an arithmetic progression.<\/p>\n Sales in October = 100<\/p>\n Sales in Q4 = 360<\/p>\n Let the sales in November be 100+y and the sales in December be 100+2y. 300 + 3y = 360<\/p>\n => y = 20<\/p>\n Sales in November 2016 = 120 and Sales in December 2016 = 140<\/p>\n Sales in Q1 of 2016 = Sum of the sales in the months of January, February, and March 2016 Sales in Q3 of 2016 = Sum of the sales in the months of July, August, and September 2016<\/p>\n = 75 + 120 + 55<\/p>\n = 250<\/p>\n Sales in Q1 of 2017 = 120 + 100 + 160 = 380 We know that sales in Q3 of 2017 = 220<\/p>\n Let the sales in August of 2017 be \u2018a\u2019. => a = 90<\/p>\n Sales in August 2017 = 90<\/p>\n We know that sales in Q4 of 2017 = 500 150 + 170 + d = 500<\/p>\n => d = 180<\/p>\n Sales in December 2017 = 180<\/p>\n March of 2017: October of 2017: March of 2016: October of 2016: As we can see, the percentage increase in sale as compared to the previous month was highest in October of 2017 among the given options. Therefore, option\u00a0B is the right answer.<\/p>\n Question 20:\u00a0<\/b>During which quarter was the percentage decrease in sales from the previous quarter\u2019s sales the highest?<\/p>\n a)\u00a0Q2 of 2017<\/p>\n b)\u00a0Q4 of 2017<\/p>\n c)\u00a0Q2 of 2016<\/p>\n d)\u00a0Q1 of 2017<\/p>\n 20)\u00a0Answer\u00a0(A)<\/strong><\/p>\n View Video Solution<\/a><\/p>\n Solution:<\/b><\/p>\n We have been given details about the quarterly sales figures. Also, we have been given details about the sales figures every month. Some of the data are missing and some additional conditions have been given in the question. Let us try to complete the pie chart as much as possible with the data available to us.<\/p>\n It is known that the sales figures during the three months of the second quarter (April, May, June) of 2016 form an arithmetic progression.<\/p>\n We know that the sales in April is 40.<\/p>\n Let the sales in May be 40+x and the sales in June be 40+2x.<\/p>\n We know that the total sales in Q2 is 150.<\/p>\n => 40 + 40 + x + 40 + 2x = 150 Therefore, sales in May 2016 = 40 + 10 = 50<\/p>\n Sales in June 2016 = 40 + 20 = 60<\/p>\n Similarly, it has been given that the sales in October, November, and December 2016 form an arithmetic progression.<\/p>\n Sales in October = 100<\/p>\n Sales in Q4 = 360<\/p>\n Let the sales in November be 100+y and the sales in December be 100+2y. 300 + 3y = 360<\/p>\n => y = 20<\/p>\n Sales in November 2016 = 120 and Sales in December 2016 = 140<\/p>\n Sales in Q1 of 2016 = Sum of the sales in the months of January, February, and March 2016 Sales in Q3 of 2016 = Sum of the sales in the months of July, August, and September 2016<\/p>\n = 75 + 120 + 55<\/p>\n = 250<\/p>\n Sales in Q1 of 2017 = 120 + 100 + 160 = 380 We know that sales in Q3 of 2017 = 220<\/p>\n Let the sales in August of 2017 be \u2018a\u2019. => a = 90<\/p>\n Sales in August 2017 = 90<\/p>\n We know that sales in Q4 of 2017 = 500 150 + 170 + d = 500<\/p>\n => d = 180<\/p>\n Sales in December 2017 = 180<\/p>\n Q2 of 2017:<\/p>\n Sales in Q2 of 2017 = 200 Q4 of 2017: Q2 of 2016: Q1 of 2017: 180\/380 is very close to 50%. 90\/240 is closer to 33.33%. Therefore, option\u00a0A is the right answer.<\/p>\n Question 21:\u00a0<\/b>In which quarter of 2017 was the percentage increase in sales from the same quarter of 2016 the highest?<\/p>\n a)\u00a0Q2<\/p>\n b)\u00a0Q1<\/p>\n c)\u00a0Q4<\/p>\n d)\u00a0Q3<\/p>\n 21)\u00a0Answer\u00a0(B)<\/strong><\/p>\n View Video Solution<\/a><\/p>\n Solution:<\/b><\/p>\n We have been given details about the quarterly sales figures. Also, we have been given details about the sales figures every month. Some of the data are missing and some additional conditions have been given in the question. Let us try to complete the pie chart as much as possible with the data available to us.<\/p>\n It is known that the sales figures during the three months of the second quarter (April, May, June) of 2016 form an arithmetic progression.<\/p>\n We know that the sales in April is 40.<\/p>\n Let the sales in May be 40+x and the sales in June be 40+2x.<\/p>\n We know that the total sales in Q2 is 150.<\/p>\n => 40 + 40 + x + 40 + 2x = 150 Therefore, sales in May 2016 = 40 + 10 = 50<\/p>\n Sales in June 2016 = 40 + 20 = 60<\/p>\n Similarly, it has been given that the sales in October, November, and December 2016 form an arithmetic progression.<\/p>\n Sales in October = 100<\/p>\n Sales in Q4 = 360<\/p>\n Let the sales in November be 100+y and the sales in December be 100+2y. 300 + 3y = 360<\/p>\n => y = 20<\/p>\n Sales in November 2016 = 120 and Sales in December 2016 = 140<\/p>\n Sales in Q1 of 2016 = Sum of the sales in the months of January, February, and March 2016 Sales in Q3 of 2016 = Sum of the sales in the months of July, August, and September 2016<\/p>\n = 75 + 120 + 55<\/p>\n = 250<\/p>\n Sales in Q1 of 2017 = 120 + 100 + 160 = 380 We know that sales in Q3 of 2017 = 220<\/p>\n Let the sales in August of 2017 be \u2018a\u2019. => a = 90<\/p>\n Sales in August 2017 = 90<\/p>\n We know that sales in Q4 of 2017 = 500 150 + 170 + d = 500<\/p>\n => d = 180<\/p>\n Sales in December 2017 = 180<\/p>\n Among the given 4 options, we have to find the quarter in which the increase in sale from the previous quarter was the highest. Q1: Q3: Q4: We can eliminate Q3 since the sales has decreased. Growth in Q1 sales = (380-240)\/240 = 140\/240 = 58.33%<\/p>\n Growth in Q4 sales = (500-360)\/360 = 140\/360<\/p>\n 140\/240 > 140\/360<\/p>\n Therefore, Q1 has recorded the highest growth in sales and hence, option B is the right answer.<\/p>\n Question 22:\u00a0<\/b>What is the percentage increase in sales in December 2017 as compared to the sales in December 2016?<\/p>\n a)\u00a038.46<\/p>\n b)\u00a022.22<\/p>\n c)\u00a028.57<\/p>\n d)\u00a050.00<\/p>\n 22)\u00a0Answer\u00a0(C)<\/strong><\/p>\n View Video Solution<\/a><\/p>\n Solution:<\/b><\/p>\n We have been given details about the quarterly sales figures. Also, we have been given details about the sales figures every month. Some of the data are missing and some additional conditions have been given in the question. Let us try to complete the pie chart as much as possible with the data available to us.<\/p>\n It is known that the sales figures during the three months of the second quarter (April, May, June) of 2016 form an arithmetic progression.<\/p>\n We know that the sales in April is 40.<\/p>\n Let the sales in May be 40+x and the sales in June be 40+2x.<\/p>\n We know that the total sales in Q2 is 150.<\/p>\n => 40 + 40 + x + 40 + 2x = 150 Therefore, sales in May 2016 = 40 + 10 = 50<\/p>\n Sales in June 2016 = 40 + 20 = 60<\/p>\n Similarly, it has been given that the sales in October, November, and December 2016 form an arithmetic progression.<\/p>\n Sales in October = 100<\/p>\n Sales in Q4 = 360<\/p>\n Let the sales in November be 100+y and the sales in December be 100+2y. 300 + 3y = 360<\/p>\n => y = 20<\/p>\n Sales in November 2016 = 120 and Sales in December 2016 = 140<\/p>\n Sales in Q1 of 2016 = Sum of the sales in the months of January, February, and March 2016 Sales in Q3 of 2016 = Sum of the sales in the months of July, August, and September 2016<\/p>\n = 75 + 120 + 55<\/p>\n = 250<\/p>\n Sales in Q1 of 2017 = 120 + 100 + 160 = 380 We know that sales in Q3 of 2017 = 220<\/p>\n Let the sales in August of 2017 be \u2018a\u2019. => a = 90<\/p>\n Sales in August 2017 = 90<\/p>\n We know that sales in Q4 of 2017 = 500 150 + 170 + d = 500<\/p>\n => d = 180<\/p>\n Sales in December 2017 = 180<\/p>\n Sales in\u00a0December 2016 = 140 Percentage change = (180-140)\/140 = 40\/140 = 28.57%<\/p>\n Therefore, option\u00a0C is the right answer.<\/p>\n Instructions<\/b><\/p>\n The graph below represent the performance of four professors, across years. measured on four variables: Percentage of time spent on research, teaching, feedback on (a scale of 10. right-hand side) and number of publications (right-hand side). Assume that the cumulative time spent per year on research and teaching activities are sane for all four professors and each of them taught only one course of 90 classroom hours.<\/p>\n Question 23:\u00a0<\/b>Research efficiency is the ratio of cumulative number of publication for a period of 3 years to the cumulative number of hours spent on research activity in those 3 years. Which of the following professors is the least efficient researcher for the period 2015 to 2017?<\/p>\n a)\u00a0Professor Artihmetic<\/p>\n b)\u00a0Professor Algebra<\/p>\n c)\u00a0Professor Geometry<\/p>\n d)\u00a0Professor Calculus<\/p>\n e)\u00a0Cannot be determined as research is expressed in percentage<\/p>\n 23)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Solution:<\/b><\/p>\n Research efficiency = (total number of publications)\/(total time spent in research)<\/p>\n Prof. Arithmetic: RE = (8) \/ [90*(0.7 + 0.5 + 0.6)] = 8 \/ (18 * 9)<\/p>\n Prof. Algebra: RE = (8) \/ [90*(0.3 + 0.4 + 0.25)] = 8 \/ (9.5 * 9)<\/p>\n Prof. Geometry: RE = (8) \/ [90*(0.75 + 0.25 + 2)] = 8 \/ (12 * 9)<\/p>\n Prof. Calculus: RE = (8) \/ [90*(0.55 + 0.55 + 0.4)] = 8 \/ (15 * 9)<\/p>\n Thus, we can observe that Prof. Arithmetic has the lowest efficiency.<\/p>\n Hence, option A is the answer.<\/p>\n Question 24:\u00a0<\/b>Count the number of instances in which “annual decreasing efforts in research” is accompanied with “annual increase in feedback”?<\/p>\n a)\u00a05<\/p>\n b)\u00a07<\/p>\n c)\u00a09<\/p>\n d)\u00a011<\/p>\n e)\u00a0None of the above<\/p>\n 24)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Solution:<\/b><\/p>\n Prof. Arithmetic: There are two such instances, during 2013-14 and 2015-16<\/p>\n Prof. Algebra: There are three such instances, during 2011-12, 2014-15 and 2015-16<\/p>\n Prof. Geometry: There are two such instances, during 2010-11 and 2013-14<\/p>\n Prof. Calculus: There are two such instances, during 2010-11 and 2014-15<\/p>\n Thus, there are 2+3+2+2 = 9 such instances.<\/p>\n Hence, option C is the answer.<\/p>\n Question 25:\u00a0<\/b>Which of the following, shows the maximum year to year percentage growth in feedback?<\/p>\n a)\u00a0Professor Artihmetic during 2013-2014<\/p>\n b)\u00a0Professor Algebra during 2015-2016<\/p>\n c)\u00a0Professor Calculus during 2012-2013<\/p>\n d)\u00a0Professor Calculus during 2014-2015<\/p>\n e)\u00a0None of the above<\/p>\n 25)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Solution:<\/b><\/p>\n Let the required percentage be P.<\/p>\n Option A: PA<\/sub> = (6.5 – 4) * 100\/ 4 = 62.5%<\/p>\n Option B: PB<\/sub> = (8 – 5) * 100\/ 5 = 60%<\/p>\n Option C: PC<\/sub> = (7 – 4) * 100\/ 4 = 75%<\/p>\n Option D: PD<\/sub> = (9 – 5.5) * 100\/ 5.5 = 63.63%<\/p>\n Thus, option C shows the maximum year-on-year growth and is the answer.<\/p>\n Instructions<\/b><\/p>\n Simple Happiness index (SHI) of a country is computed on the basis of three, parameters: social support (S),freedom to life choices (F) and corruption perception (C). Each of these three parameters is measured on a scale of 0 to 8 (integers only). A country is then categorised based on the total score obtained by summing the scores of all the three parameters, as shown in the following table:<\/p>\n <\/p>\n Following diagram depicts the frequency distribution of the scores in S, F and C of 10 countries – Amda, Benga, Calla, Delma, Eppa, Varsa, Wanna, Xanda,Yanga and Zooma:<\/p>\n <\/p>\n Further, the following are known. <\/p>\n Question 26:\u00a0<\/b>If Benga scores 16 and Delma scores 15, then what is the maximum number of countries with a score of 13?<\/p>\n a)\u00a00<\/p>\n b)\u00a01<\/p>\n c)\u00a02<\/p>\n d)\u00a03<\/p>\n 26)\u00a0Answer\u00a0(B)<\/strong><\/p>\n View Video Solution<\/a><\/p>\n Solution:<\/b><\/p>\n S:\u00a0 F:\u00a0 C: 1,2,2,2, Given that Benga scores 16, and Delma scores 15.<\/p>\n The possibility is Benga: 5,5,6 and Delma: 7,5,3<\/p>\n If Benga’s distribution is 7,3,6 then Delma can’t score 15.<\/p>\n Strike off those numbers.<\/p>\n S:\u00a0 F:\u00a0 C: 1,2,2,2, We have to maximum number of countries with score 13. This score does not comes under the category of happy. So to score 13, the distribution can be 5,5,3. Hence, maximum 1 country is possible.<\/p>\n Question 27:\u00a0<\/b>Benga and Delma, two countries categorized as happy, are tied with the same total score. What is the a)\u00a014<\/p>\n b)\u00a015<\/p>\n c)\u00a016<\/p>\n d)\u00a017<\/p>\n 27)\u00a0Answer\u00a0(B)<\/strong><\/p>\n View Video Solution<\/a><\/p>\n Solution:<\/b><\/p>\n S:\u00a0 F:\u00a0 C: 1,2,2,2, Benga and Delma, two countries categorized as happy, are tied with the same total score.<\/p>\n The best numbers remaining are 7,5,6 which adds upto 18, If Benga scores 18, then Delma can’t score 18.<\/p>\n Similarly both can’t score 17 and 16. Both can score 15 and their distribution will be:<\/p>\n Benga: 7,5,3<\/p>\n Delma: 4,5,6 or 5,4,6<\/p>\n Question 28:\u00a0<\/b>What is Zooma’s score in S?<\/p>\n 28)\u00a0Answer:\u00a06<\/b><\/p>\n View Video Solution<\/a><\/p>\n Solution:<\/b><\/p>\n The frequency distribution is:<\/p>\n
\nThe following graph depicts sector-wise percentage contributions to the gross domestic product (GDP) of nine nations, labelled \u201cNation A\u201d, \u201cNation B\u201d and so on. It is known that these nations are Brazil, China, France, Germany,India, Japan, Russia, the UK and the USA, but not necessarily in the same order.<\/p>\n![](\"https:\/\/cracku.in\/media\/uploads\/Quant-Q26-28.png\")
<\/figure>\n
\ni) The GDPs of the nine nations (in US $ trillion) are:<\/p>\n![](\"https:\/\/cracku.in\/media\/uploads\/Quant-Q26.png\")
<\/figure>\n
\niii) In terms of percentage contribution to the respective nations\u2019 GDPs by their service sectors, the UK and France are respectively the first and the second
\niv) Nation A, Nation B and Nation G have the same GDP
\nv) The GDPofIndia\u2019s industry sector is lower than the GDP of Russia\u2019s industry sector. However,it is larger than that of Brazil’s industry sector<\/p>\n![](\"https:\/\/cracku.in\/media\/uploads\/Screenshot_19_9XatBpD.png\")
<\/figure>\n![](\"https:\/\/cracku.in\/media\/uploads\/Screenshot_20_jr2urRD.png\")
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\ni) Tamil Nadu: 2
\nii) Puducherry: 3<\/p>\n<\/figure>\n<\/figure>\n<\/figure>\n<\/figure>\n<\/figure>\n<\/figure>\n![](\"https:\/\/cracku.in\/media\/uploads\/DILR%20Q9%20(1).png\")
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\nThe analyst at a retail giant has modelled the consumer spending and consumer sentiment to prepare a strategy on product offers in the upcoming festive season. The data given in the figure are from last 10 years on 3 parameters namely, food spending (Food_Spend), style spending (Style_Spend), and sentiment index (Sentiment_Index). Study the figure below and answer the following questions :<\/p>\n![](\"https:\/\/cracku.in\/media\/uploads\/Screenshot_1_0IVy9TD.png\")
<\/figure>\n
\n2011 sentiment index = 140\/250 = 0.56
\n2011 ratio = 1\/4.<\/p>\n
\n2012 sentiment index = 140\/390
\nRatio 2012 =\u00a00.06<\/p>\n
\n2014 sentiment index =360\/750=0.48
\nRatio =\u00a01.1<\/p>\n
\n2017 sentiment Index = 160\/550
\nRatio = 0.75<\/p>\n![](\"https:\/\/cracku.in\/media\/uploads\/Screenshot%20from%202019-12-19%2015%3A42%3A16.png\")
<\/figure>\n![](\"https:\/\/cracku.in\/media\/uploads\/rep2.png\")
<\/figure>\n![](\"https:\/\/cracku.in\/media\/uploads\/q_lPmBVjf.png\")
<\/figure>\n
\n3x = 30
\nx = 10<\/p>\n
\n100 + 100 + y + 100 + 2y = 360<\/p>\n
\n= 80 + 60 + 100
\n= 240<\/p>\n
\nSales in Q2 of 2017 = 65 + 75 + 60 = 200<\/p>\n
\n60 + 70 + a = 220<\/p>\n
\nLet the sales in December of 2017 be \u2018d\u2019.<\/p>\n![](\"https:\/\/cracku.in\/media\/uploads\/pi2.JPG\")
<\/figure>\n
\nSales in March of 2017 = 160
\nSales in February of 2017 = 100
\n% increase = 60\/100 = 60%<\/p>\n
\nSales in October of 2017 = 150
\nSales in September of 2017 = 70
\nAs we can see, the sales has increased by more than 100%.<\/p>\n
\nSales in March of 2016 = 100
\nSales in February of 2016 = 60
\n% increase in sales is less than 100%.<\/p>\n
\nSales in October of 2016 = 100
\nSales in September of 2016 = 55
\n% increase is less than 100%<\/p>\n
\n3x = 30
\nx = 10<\/p>\n
\n100 + 100 + y + 100 + 2y = 360<\/p>\n
\n= 80 + 60 + 100
\n= 240<\/p>\n
\nSales in Q2 of 2017 = 65 + 75 + 60 = 200<\/p>\n
\n60 + 70 + a = 220<\/p>\n
\nLet the sales in December of 2017 be \u2018d\u2019.<\/p>\n<\/figure>\n
\nSales in Q1 of 2017 = 380
\n% decrease = 180\/380<\/p>\n
\nWe can eliminate this option since the sales has increased in Q4 of 2017 as compared to the previous quarter.<\/p>\n
\nSales in Q2 of 2016 = 150
\nSales in Q1 of 2016 = 240
\n% decrease = 90\/240<\/p>\n
\nSales in Q1 of 2017 has increased as compared to sales in the previous quarter. We can eliminate this option\u00a0as well.<\/p>\n
\n3x = 30
\nx = 10<\/p>\n
\n100 + 100 + y + 100 + 2y = 360<\/p>\n
\n= 80 + 60 + 100
\n= 240<\/p>\n
\nSales in Q2 of 2017 = 65 + 75 + 60 = 200<\/p>\n
\n60 + 70 + a = 220<\/p>\n
\nLet the sales in December of 2017 be \u2018d\u2019.<\/p>\n<\/figure>\n
\nQ2:
\nSales in 2017 = 200
\nSales in 2016 = 150<\/p>\n
\nSales in 2017 = 380
\nSales in 2016 = 240<\/p>\n
\nSales in 2017 = 220
\nSales in 2016 = 250<\/p>\n
\nSales in 2017 = 500
\nSales in 2016 = 360<\/p>\n
\nGrowth in Q2 sales = 50\/150 = 1\/3 = 33.33%<\/p>\n
\n3x = 30
\nx = 10<\/p>\n
\n100 + 100 + y + 100 + 2y = 360<\/p>\n
\n= 80 + 60 + 100
\n= 240<\/p>\n
\nSales in Q2 of 2017 = 65 + 75 + 60 = 200<\/p>\n
\n60 + 70 + a = 220<\/p>\n
\nLet the sales in December of 2017 be \u2018d\u2019.<\/p>\n<\/figure>\n
\nSales in December 2017 = 180<\/p>\n![](\"https:\/\/cracku.in\/media\/uploads\/Screenshot_1_QjaPddm.png\")
\n![](\"https:\/\/cracku.in\/media\/uploads\/Screenshot_2_iiSXPmM.png\")
\n![](\"https:\/\/cracku.in\/media\/uploads\/Screenshot_3_AS7xOdx.png\")
\n![](\"https:\/\/cracku.in\/media\/uploads\/Screenshot_4_GFc92yr.png\")
<\/p>\n![](\"https:\/\/cracku.in\/media\/uploads\/bar%20graph_3v2WA4j.png\")
<\/figure>\n![](\"https:\/\/cracku.in\/media\/uploads\/dilr-freq.JPG\")
<\/figure>\n
\n1. Amda and Calla jointly have the lowest total score, 7, with identical scores in all the three parameters.
\n2. Zooma has a total score of 17.
\n3. All the 3 countries, which are categorised as happy, have the highest score ln exactly one parameter.<\/p>\n3,3<\/del>,3,4,4,4,5,5,6<\/del>,7<\/p>\n1,1<\/del>,2,3,3,4,5,5,5,7<\/del><\/p>\n3,3<\/del>,3,3,4<\/del>,6<\/p>\n3,3<\/del>,3,4,4,4,5,5,6,7<\/del><\/p>\n1,1<\/del>,2,3,3,4,5,5,5<\/del>,7<\/del><\/p>\n3,3<\/del>,3,3,4,6<\/del><\/p>\n
\nmaximum score they can have?<\/p>\n3,3<\/del>,3,4,4,4,5,5,6<\/del>,7<\/p>\n1,1<\/del>,2,3,3,4,5,5,5,7<\/del><\/p>\n3,3<\/del>,3,3,4<\/del>,6<\/p>\n
![](\"https:\/\/cracku.in\/media\/uploads\/95188%20-%201.png\")
<\/figure>\n![](\"https:\/\/cracku.in\/media\/uploads\/95188%20-%202.png\")
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