Here you can download the important MAH – CET Number Series Questions PDF by Cracku. Very Important MAH – CET 2022 and These questions will help your MAH – CET preparation. So kindly download the PDF for reference and do more practice.<\/p>\n
Download Number Series Questions for MAH-CET PDF<\/a><\/p>\n Enroll to MAH-CET Crash Course<\/a><\/p>\n Instructions<\/b><\/p>\n In each of the following questions a number series is given.After the series , a number is given followed by a (a),(b),(c),(d) and (e).You are required to complete the series starting with the number given following the sequences of the given series?<\/p>\n Question 1:\u00a0<\/b>12 \u00a024 \u00a096 \u00a0576 \u00a04608 a)\u00a01080<\/p>\n b)\u00a0676<\/p>\n c)\u00a03608<\/p>\n d)\u00a03456<\/p>\n e)\u00a0None of these<\/p>\n 1)\u00a0Answer\u00a0(E)<\/strong><\/p>\n Solution:<\/b><\/p>\n The pattern followed is that all the even natural numbers are multiplied.<\/p>\n 12 $\\times 2$ = 24<\/p>\n 24 $\\times 4$ = 96<\/p>\n 96 $\\times 6$ =\u00a0576<\/p>\n 576 $\\times 8$ =\u00a04608<\/p>\n Similarly,<\/p>\n 5\u00a0$\\times 2$ = 10<\/p>\n 10\u00a0$\\times 4$ =\u00a040<\/p>\n 40\u00a0$\\times 6$ =\u00a0240<\/strong><\/p>\n => Ans – (E)<\/p>\n Question 2:\u00a0<\/b>150 \u00a0 299 \u00a0 \u00a0601 \u00a01197 2401 \u00a0 4793 a)\u00a01917.2<\/p>\n b)\u00a01913<\/p>\n c)\u00a01922<\/p>\n d)\u00a0861<\/p>\n e)\u00a0None of these<\/p>\n 2)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Solution:<\/b><\/p>\n The pattern followed is :<\/p>\n 150 $\\times 2 – 1$ = 299<\/p>\n 299\u00a0$\\times 2 + 3$ =\u00a0601<\/p>\n 601\u00a0$\\times 2 – 5$ =\u00a01197<\/p>\n 1197\u00a0$\\times 2 + 7$ =\u00a02401<\/p>\n 2401\u00a0$\\times 2 – 9$ =\u00a04793<\/p>\n Similarly,<\/p>\n 60\u00a0$\\times 2 – 1$ =\u00a0119<\/p>\n 119 $\\times 2 + 3$ =\u00a0241<\/p>\n 241 $\\times 2 – 5$ =\u00a0477<\/p>\n 477 $\\times 2 + 7$ =\u00a0961<\/p>\n 961 $\\times 2 – 9$ =\u00a01913<\/strong><\/p>\n => Ans – (B)<\/p>\n Question 3:\u00a0<\/b>3 \u00a0 \u00a0 9 \u00a0 \u00a0 \u00a081 \u00a0 \u00a06561 a)\u00a0656<\/p>\n b)\u00a04374<\/p>\n c)\u00a01024<\/p>\n d)\u00a065536<\/p>\n e)\u00a0None of these<\/p>\n 3)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Solution:<\/b><\/p>\n The pattern followed is that each number is squared<\/p>\n $3^2$ = 9<\/p>\n $9^2$ =\u00a081<\/p>\n $81^2$ =\u00a06561<\/p>\n Similarly,<\/p>\n $2^2$ = 4<\/p>\n $4^2$ =\u00a016<\/p>\n $16^2$ =\u00a0256<\/p>\n $256^2$ =\u00a065536<\/strong><\/p>\n => Ans – (D)<\/p>\n Question 4:\u00a0<\/b>3 \u00a0 \u00a07 \u00a0 \u00a0 \u00a024 \u00a0 \u00a0101 \u00a0 512 a)\u00a055<\/p>\n b)\u00a0149<\/p>\n c)\u00a0168<\/p>\n d)\u00a0752<\/p>\n e)\u00a0None of these<\/p>\n 4)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Solution:<\/b><\/p>\n The pattern followed is\u00a0:<\/p>\n 3 $\\times 2+1$ = 7<\/p>\n 7\u00a0$\\times 3+3$ =\u00a024<\/p>\n 24\u00a0$\\times 4+5$ =\u00a0101<\/p>\n 101\u00a0$\\times 5+7$ =\u00a0512<\/p>\n Similarly,<\/p>\n 5 $\\times 2+1$ = 11<\/p>\n 11 $\\times 3+3$ =\u00a036<\/p>\n 36 $\\times 4+5$ =\u00a0149<\/strong><\/p>\n => Ans – (B)<\/p>\n Question 5:\u00a0<\/b>What will come in the place of question mark (?) in the following series ? a)\u00a096<\/p>\n b)\u00a0106<\/p>\n c)\u00a0126<\/p>\n d)\u00a0130<\/p>\n e)\u00a0None of these<\/p>\n 5)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Solution:<\/b><\/p>\n Each number is of the form $(n^3+1)$ where $n$ is a natural number<\/p>\n $1^3+1$ = 2<\/p>\n $2^3+1$ =\u00a09<\/p>\n $3^3+1$ =\u00a028<\/p>\n $4^3+1$ =\u00a065<\/p>\n $5^3+1$ =\u00a0126<\/strong><\/p>\n => Ans – (C)<\/p>\n Take Free MAH-CET mock tests here<\/a><\/p>\n Instructions<\/b><\/p>\n What will come in place of the question mark (?) in each of the following number series.<\/p>\n Question 6:\u00a0<\/b>8, 5.5, 8.5, 23, 89.5, ?<\/p>\n a)\u00a0455<\/p>\n b)\u00a0420.5<\/p>\n c)\u00a0445<\/p>\n d)\u00a0415.5<\/p>\n e)\u00a0433<\/p>\n 6)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Solution:<\/b><\/p>\n The pattern followed is\u00a0:<\/p>\n 8 $\\times 1 – 2.5$ = 5.5<\/p>\n 5.5\u00a0$\\times 2 – 2.5$ =\u00a08.5<\/p>\n 8.5\u00a0$\\times 3 – 2.5$ =\u00a023<\/p>\n 23\u00a0$\\times 4 – 2.5$ =\u00a089.5<\/p>\n 89.5\u00a0$\\times 5 – 2.5$ =\u00a0445<\/strong><\/p>\n Question 7:\u00a0<\/b>31, 15, 21, 50, ?, 767.25<\/p>\n a)\u00a0160.5<\/p>\n b)\u00a0171.5<\/p>\n c)\u00a0156.5<\/p>\n d)\u00a0122.5<\/p>\n e)\u00a0143.5<\/p>\n 7)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Solution:<\/b><\/p>\n The pattern followed is\u00a0:<\/p>\n 31 $\\times 0.5 – 0.5$ = 15<\/p>\n 15\u00a0$\\times 1.5 – 1.5$ =\u00a021<\/p>\n 21\u00a0$\\times 2.5 – 2.5$ =\u00a050<\/p>\n 50\u00a0$\\times 3.5 – 3.5$ =\u00a0171.5<\/strong><\/p>\n 171.5\u00a0$\\times 4.5 – 4.5$ =\u00a0767.25<\/p>\n Question 8:\u00a0<\/b>402, 400, 388, 358, 302, ?<\/p>\n a)\u00a0212<\/p>\n b)\u00a0236<\/p>\n c)\u00a0190<\/p>\n d)\u00a0182<\/p>\n e)\u00a0210<\/p>\n 8)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Solution:<\/b><\/p>\n The pattern followed is\u00a0:<\/p>\n 402 $- (1 \\times 2)$ = 400<\/p>\n 400\u00a0$- (3 \\times 4)$ =\u00a0388<\/p>\n 388\u00a0$- (5 \\times 6)$ =\u00a0358<\/p>\n 358\u00a0$- (7 \\times 8)$ =\u00a0302<\/p>\n 302\u00a0$- (9 \\times 10)$ =\u00a0212<\/strong><\/p>\n Question 9:\u00a0<\/b>16, 19, 24, 33, 50, ?<\/p>\n a)\u00a083<\/p>\n b)\u00a066<\/p>\n c)\u00a099<\/p>\n d)\u00a074<\/p>\n e)\u00a0102<\/p>\n 9)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Solution:<\/b><\/p>\n The pattern is\u00a0:<\/p>\n 16 + 3 = 19<\/p>\n 19 + 5 (= 3 + 2) = 24<\/p>\n 24 + 9\u00a0(= 5 + 4) =\u00a033<\/p>\n 33 + 17\u00a0(= 9 + 8) =\u00a050<\/p>\n 50 + 33\u00a0(= 17 + 16) =\u00a083<\/strong><\/p>\n Question 10:\u00a0<\/b>158, 78, 38, 18, 8, ?<\/p>\n a)\u00a03<\/p>\n b)\u00a05<\/p>\n c)\u00a02<\/p>\n d)\u00a07<\/p>\n e)\u00a06<\/p>\n 10)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Solution:<\/b><\/p>\n Each number is divided by 2 and then 1 is subtracted.<\/p>\n 158 $\\div 2 – 1$ = 78<\/p>\n 78\u00a0$\\div 2 – 1$ =\u00a038<\/p>\n 38\u00a0$\\div 2 – 1$ =\u00a018<\/p>\n 18\u00a0$\\div 2 – 1$ =\u00a08<\/p>\n 8\u00a0$\\div 2 – 1$ =\u00a03<\/strong><\/p>\n Question 11:\u00a0<\/b>What will come in place of the question mark (?) in the following number series? a)\u00a01589<\/p>\n b)\u00a01598<\/p>\n c)\u00a01958<\/p>\n d)\u00a01985<\/p>\n e)\u00a01835<\/p>\n 11)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Solution:<\/b><\/p>\n The pattern followed is\u00a0:<\/p>\n 9 $\\times 1 + 1^2$ = 10<\/p>\n 10\u00a0$\\times 3 + 3^2$ =\u00a039<\/p>\n 39\u00a0$\\times 5 + 5^2$ =\u00a0220<\/p>\n 220\u00a0$\\times 7 + 7^2$ =\u00a01589<\/strong><\/p>\n 1589\u00a0$\\times 9 + 9^2$ =\u00a014382<\/p>\n Question 12:\u00a0<\/b>What will come in place of thequestion mark (?) in the following number series? a)\u00a01008<\/p>\n b)\u00a0948<\/p>\n c)\u00a0944<\/p>\n d)\u00a0940<\/p>\n e)\u00a01005<\/p>\n 12)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Solution:<\/b><\/p>\n Each number is multiplied by 2 and then 4 is subtracted from it.<\/p>\n 121 $\\times 2 – 4$ = 238<\/p>\n 238\u00a0$\\times 2 – 4$ =\u00a0472<\/p>\n 472\u00a0$\\times 2 – 4$ =\u00a0940<\/strong><\/p>\n 940\u00a0$\\times 2 – 4$ =\u00a01876<\/p>\n 1876\u00a0$\\times 2 – 4$ =\u00a03748<\/p>\n Question 13:\u00a0<\/b>What will come in place of thequestion mark (?) in the following number series? a)\u00a044<\/p>\n b)\u00a055<\/p>\n c)\u00a066<\/p>\n d)\u00a033<\/p>\n e)\u00a035<\/p>\n 13)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Solution:<\/b><\/p>\n Each number is multiplied by $\\frac{3}{2}$<\/p>\n 44 $\\times \\frac{3}{2}$ =\u00a066<\/strong><\/p>\n 66\u00a0$\\times \\frac{3}{2}$ =\u00a099<\/p>\n 99\u00a0$\\times \\frac{3}{2}$ =\u00a0148.5<\/p>\n 148.5\u00a0$\\times \\frac{3}{2}$ =\u00a0222.75<\/p>\n 222.75\u00a0$\\times \\frac{3}{2}$ =\u00a0334.125<\/p>\n Question 14:\u00a0<\/b>What will come in place of thequestion mark (?) in the following number series? a)\u00a018.5<\/p>\n b)\u00a016.5<\/p>\n c)\u00a08.5<\/p>\n d)\u00a08.25<\/p>\n e)\u00a0None of these<\/p>\n 14)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Solution:<\/b><\/p>\n The pattern followed is\u00a0:<\/p>\n 33 $\\times \\frac{1}{2}$ = 16.5<\/p>\n 16.5\u00a0$\\times \\frac{2}{2}$ =\u00a016.5<\/strong><\/p>\n 16.5\u00a0$\\times \\frac{3}{2}$ =\u00a024.75<\/p>\n 24.75\u00a0$\\times \\frac{4}{2}$ =\u00a049.5<\/p>\n 49.5\u00a0$\\times \\frac{5}{2}$ =\u00a0123.75<\/p>\n Question 15:\u00a0<\/b>What will come in place of the question mark (?) in the following number series? a)\u00a095<\/p>\n b)\u00a090<\/p>\n c)\u00a0100<\/p>\n d)\u00a0105<\/p>\n e)\u00a096<\/p>\n 15)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Solution:<\/b><\/p>\n Numbers of the form $n^2 – (n-1)$ are added, where $n$ is an integer starting from 2<\/p>\n 23 $+ 2^2 – 1$ = 23<\/p>\n 23\u00a0$+ 3^2 – 2$ =\u00a030<\/p>\n 30\u00a0$+ 4^2 – 3$ =\u00a043<\/p>\n 43\u00a0$+ 5^2 – 4$ =\u00a064<\/p>\n 64\u00a0$+ 6^2 – 5$ =\u00a095<\/strong><\/p>\n Question 16:\u00a0<\/b>What should come in place of the question mark (?) in the following number series ? a)\u00a01168<\/p>\n b)\u00a01254<\/p>\n c)\u00a01457<\/p>\n d)\u00a01372<\/p>\n e)\u00a0None of these<\/p>\n 16)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Solution:<\/b><\/p>\n The pattern here followed is\u00a0:<\/p>\n 1 * 3 + 2 = 5<\/p>\n 5\u00a0* 3 + 2 =\u00a017<\/p>\n 17\u00a0* 3 + 2 =\u00a053<\/p>\n 53\u00a0* 3 + 2 =\u00a0161<\/p>\n 161\u00a0* 3 + 2 =\u00a0485<\/p>\n 485\u00a0* 3 + 2 =\u00a01457<\/strong><\/p>\n Question 17:\u00a0<\/b>What approximate value should come in place of the question mark (?) in the following question? a)\u00a084<\/p>\n b)\u00a048<\/p>\n c)\u00a0118<\/p>\n d)\u00a058<\/p>\n e)\u00a024<\/p>\n 17)\u00a0Answer\u00a0(E)<\/strong><\/p>\n Solution:<\/b><\/p>\n Expression\u00a0: $54.786 \\div 10.121 \\times 4.454 = ?$<\/p>\n = $\\frac{55}{10} \\times 4.5$<\/p>\n = $24.75 \\approx 24$<\/p>\n Question 18:\u00a0<\/b>What should come in place of the question mark (?) in the following number series? a)\u00a0168<\/p>\n b)\u00a0154<\/p>\n c)\u00a0191<\/p>\n d)\u00a0172<\/p>\n e)\u00a0None of these<\/p>\n 18)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Solution:<\/b><\/p>\n The pattern here followed is\u00a0:<\/p>\n 2 * 2 + 1 = 5<\/p>\n 5 *\u00a02 + 1 =\u00a0\u00a011<\/p>\n 11 *\u00a02 + 1 =\u00a023<\/p>\n 23 *\u00a02 + 1 =\u00a047<\/p>\n 47 *\u00a02 + 1 =\u00a095<\/p>\n 95 *\u00a02 + 1 =\u00a0191<\/strong><\/p>\n Question 19:\u00a0<\/b>What should come in place of the question mark (?) in the following number series? a)\u00a01268<\/p>\n b)\u00a01234<\/p>\n c)\u00a01272<\/p>\n d)\u00a01216<\/p>\n e)\u00a0None of these<\/p>\n 19)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Solution:<\/b><\/p>\n The pattern here followed is\u00a0:<\/p>\n 1\u00a0* 3 +\u00a01 = 4<\/p>\n 4\u00a0* 3 +\u00a02 = 14<\/p>\n 14\u00a0* 3 + 3 = 45<\/p>\n 45\u00a0* 3 +\u00a04 = 139<\/p>\n 139\u00a0* 3 + 5 = 422<\/p>\n 422 * 3 + 6 =\u00a01272<\/strong><\/p>\n Question 20:\u00a0<\/b>What is the least number to be added to 2530 to make it a perfect square ?<\/p>\n a)\u00a050<\/p>\n b)\u00a065<\/p>\n c)\u00a075<\/p>\n d)\u00a080<\/p>\n e)\u00a0None of these<\/p>\n 20)\u00a0Answer\u00a0(E)<\/strong><\/p>\n Solution:<\/b><\/p>\n We know that $50^2 = 2500$ and $51^2 = 2601$<\/p>\n $\\because$ 2500\u00a0< 2530\u00a0< 2601<\/p>\n $\\therefore$ Required number = 2601 – 2530 = 71<\/p>\n
\n5 \u00a0 (a) \u00a0(b) \u00a0(c) \u00a0 \u00a0 (d) \u00a0 \u00a0 \u00a0 (e)
\nWhat will come in place of (c) ?<\/p>\n
\n60 \u00a0 \u00a0 (a) \u00a0 \u00a0( b) \u00a0 \u00a0 (c) \u00a0 \u00a0(d) \u00a0 \u00a0 \u00a0(e)
\nWhat will come in place of (e) ?<\/p>\n
\n2 \u00a0 \u00a0(a) \u00a0 \u00a0(b) \u00a0 \u00a0 \u00a0(c) \u00a0 \u00a0 \u00a0(d) \u00a0 \u00a0(e)
\nWhat will come in place of (d) ?<\/p>\n
\n5 \u00a0 (a) \u00a0 (b) \u00a0 \u00a0 (c) \u00a0 \u00a0 (d) \u00a0 (e)
\nWhat will come in place of (c) ?<\/p>\n
\n2 \u00a09 \u00a028 \u00a065 ?<\/p>\n
\n9\u00a0 10\u00a0 39\u00a0 220\u00a0 ?\u00a0 14382<\/p>\n
\n121\u00a0 238\u00a0 472\u00a0 ?\u00a0 1876\u00a0 3748<\/p>\n
\n44\u00a0 ?\u00a0 99\u00a0 \u00a0148.5 \u00a0222.75\u00a0 334.125<\/p>\n
\n33\u00a0 16.5\u00a0 ?\u00a0 24.75\u00a0 \u00a0 49.5\u00a0 123.75<\/p>\n
\n20\u00a0 23\u00a0 30\u00a0 43\u00a0 64\u00a0 ?<\/p>\n
\n1, 5, 17, 53, 161, 485, ?<\/p>\n
\n$54.786 \\div 10.121 \\times 4.454 = ?$<\/p>\n
\n2 5 11 23 47 95 ?<\/p>\n
\n1 4 14 45 139 422 ?<\/p>\n