Enroll to CMAT crash course<\/a><\/p>\n Take CMAT mock tests here<\/a><\/p>\n Download CMAT previous papers PDF<\/a><\/p>\n Question 1:\u00a0<\/b>The wheat sold by a grocer contained 10% low quality wheat. What quantity of good quality wheat should be added to 150 kgs of wheat so that the percentage of low quality wheat becomes 5%<\/p>\n a)\u00a0150 kgs<\/p>\n b)\u00a0135 kgs<\/p>\n c)\u00a050 kgs<\/p>\n d)\u00a085 kgs<\/p>\n e)\u00a0None of these<\/p>\n Question 2:\u00a0<\/b>Matthew scored 42 marks in biology, 51 marks in chemistry, 58 marks in mathematics, 35 marks in physics and 48 marks in English. The maximum marks a student can score in each subject are 60. How much overall percentage did Matthew get in this exam?<\/p>\n a)\u00a076<\/p>\n b)\u00a082<\/p>\n c)\u00a068<\/p>\n d)\u00a078<\/p>\n e)\u00a0None of these<\/p>\n Instructions<\/b><\/p>\n <p “=””>Study the following information carefully to answer the questions that follow :\u00a0 <p “=””>There are two Trains, Train-A and Train-B. Both Trains have four different types of Coaches viz. General Coaches, Sleeper Coaches, First Class Coaches and AC Coaches. In Train A there are total 700 passengers. Train-B has thirty percent more passengers than Train A. Twenty percent of the passengers of Train-A are in General Coaches. One-fourth of the total number of passengers of Train-A are in AC coaches. Twenty three percent of the passengers of Train-A are in Sleeper Class Coaches. Remaining passengers of Train-A are in first class coaches. Total number of passengers in AC coaches in both the trains together is 480. Thirty percent of the number of passengers of Train-B is in Sleeper Class Coaches. Ten percent of the total passengers of Train-B are in first class coaches. Remaining passengers of Train-B are in general class coaches.<\/p>\n Question 3:\u00a0<\/b>Total number of passengers in General Class coaches in both the Trains together is approximately what percentage of total number of passengers in Train-B ?<\/p>\n a)\u00a035<\/p>\n b)\u00a042<\/p>\n c)\u00a046<\/p>\n d)\u00a038<\/p>\n e)\u00a031<\/p>\n Question 4:\u00a0<\/b>If tax on a commodity is reduced by 10%, total revenue remains unchanged. What is the percentage increase in its consumption?<\/p>\n a)\u00a0$11\\frac{1}{9}$<\/p>\n b)\u00a0$20$%<\/p>\n c)\u00a0$10$%<\/p>\n d)\u00a0$9\\frac{1}{11}$<\/p>\n e)\u00a0None of these<\/p>\n Question 5:\u00a0<\/b>Sujata scored 2240 marks in an examination that is 128 marks more than the minimum passing percentage of 64%. What is the percentage of marks obtained by Meena if she scores 907 marks less than Sujata?<\/p>\n a)\u00a035<\/p>\n b)\u00a040<\/p>\n c)\u00a045<\/p>\n d)\u00a036<\/p>\n e)\u00a048<\/p>\n Get 5 CMAT mocks at just Rs.299<\/a><\/p>\n Download CMAT Previous Papers PDF<\/a><\/p>\n Question 6:\u00a0<\/b>Sohail scored 33 marks in English, 37 marks in Science, 28 marks in Mathematics, 26 marks in Hindi and 32 marks in Social studies. The maximum marks a student can score in each subject in 60. How much percentage did Sohail get in this exam ?<\/p>\n a)\u00a052<\/p>\n b)\u00a054<\/p>\n c)\u00a048<\/p>\n d)\u00a053<\/p>\n e)\u00a0None of these<\/p>\n Question 7:\u00a0<\/b>In a test, minimum passing percentage for reserved and unreserved category is 40% and 54% respectively. A candidate from unreserved category secured 300 marks and failed by 24 marks. What are the minimum passing marks of reserved category in that test ?<\/p>\n a)\u00a0280<\/p>\n b)\u00a0254<\/p>\n c)\u00a0230<\/p>\n d)\u00a0240<\/p>\n e)\u00a0None of these<\/p>\n Question 8:\u00a0<\/b>Koel scored 49 marks in English, 37 marks in Science, 45 marks in Mathematics, 53 marks in Hindi and 55 marks in Social studies. The maximum marks a student can score in each subject is 70. How much approximate percentage did Koel get in this exam?<\/p>\n a)\u00a053<\/p>\n b)\u00a079<\/p>\n c)\u00a068<\/p>\n d)\u00a073<\/p>\n e)\u00a088<\/p>\n Question 9:\u00a0<\/b>The wheat sold by a grocer contained 10% low-quality wheat. What quantity of good-quality wheat should be added to 150 kg of wheat so that the percentage of low-quality wheat becomes 5% ?<\/p>\n a)\u00a0150 kg<\/p>\n b)\u00a0135 kg<\/p>\n c)\u00a050 kg<\/p>\n d)\u00a085 kg<\/p>\n e)\u00a0None of these<\/p>\n Question 10:\u00a0<\/b>Paresh got 102 marks in Hindi, 118 marks in Science, 104 marks in Sanskrit, 114 marks in Maths and 96 marks in English.\u00a0The maximum marks of each subject are 120. How much overall percentage of marks did paresh get ?<\/p>\n a)\u00a089<\/p>\n b)\u00a082<\/p>\n c)\u00a077<\/p>\n d)\u00a071<\/p>\n e)\u00a0None of these<\/p>\n Take CMAT Mock Tests<\/a><\/p>\n Answers & Solutions:<\/strong><\/span><\/p>\n 1)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Let $x$ kg of good quality wheat should be added.<\/p>\n Acc to ques,<\/p>\n => $\\frac{10}{100} \\times x = \\frac{5}{100} \\times (x + 150)$<\/p>\n => $10x = 5x + 750$<\/p>\n => $x = \\frac{750}{5} = 150$ kg<\/p>\n 2)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Total marks obtained by Matthew<\/p>\n = 42 + 51 + 58 + 35 + 48 = 234<\/p>\n Maximum marks of the five subjects = 5 * 60 = 300<\/p>\n => Required % = $\\frac{234}{3} \\times 100$ = 78\u00a0%<\/p>\n 3)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Total passengers in train A = 700<\/p>\n => Total passengers in train B = $\\frac{130}{100} \\times 700 = 910$<\/p>\n Number of passengers In train A\u00a0in the class :<\/p>\n General = $\\frac{20}{100} \\times 700 = 140$<\/p>\n AC = $\\frac{1}{4} \\times 700 = 175$<\/p>\n Sleeper = $\\frac{23}{100} \\times 700 = 161$<\/p>\n First = $700 – 140 – 175 – 161 = 224$<\/p>\n Number of passengers in train B in the class\u00a0:<\/p>\n AC = $480 – 175 = 305$<\/p>\n Sleeper = $\\frac{30}{100} \\times 910 = 273$<\/p>\n First = $\\frac{10}{100} \\times 910 = 91$<\/p>\n General = $910 – 305 – 273 – 91 = 241$<\/p>\n Total number of passengers in General Class coaches in both the Trains together\u00a0= 140 + 241 = 381<\/p>\n Total number of passengers in Train-B\u00a0= 910<\/p>\n => Required % = $\\frac{381}{910} \\times 100$<\/p>\n = $41.86 \\% \\approx 42 \\%$<\/p>\n 4)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Revenue = consumption $\\times$ tax amount<\/p>\n Let consumption = 10 and tax = 10<\/p>\n => Revenue = $10 \\times 10 = 100$<\/p>\n Now, after tax is reduced by 10 %, new tax = $10 – \\frac{10}{100} \\times 10$<\/p>\n = $10 – 1 = 9$<\/p>\n Total revenue remains unchanged<\/p>\n => New consumption = $\\frac{100}{9}$<\/p>\n $\\therefore$ % increase in consumption = $\\frac{\\frac{100}{9} – 10}{10} \\times 100$<\/p>\n = $\\frac{10}{9} \\times 10 = \\frac{100}{9}$<\/p>\n = $11\\frac{1}{9} \\%$<\/p>\n 5)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Let maximum marks in the examination = $100x$<\/p>\n Minimum passing marks = $\\frac{64}{100} \\times 100x = 64x$<\/p>\n Marks scored by Sujata = $2240$<\/p>\n Acc to ques,<\/p>\n => $64x + 128 = 2240$<\/p>\n => $64x = 2240 – 128 = 2112$<\/p>\n => $x = \\frac{2112}{64} = 33$<\/p>\n => Maximum marks = $100 \\times 33 = 3300$<\/p>\n Marks scored by Meena = $2240 – 907 = 1333$<\/p>\n $\\therefore$ % marks obtained by Meena = $\\frac{1333}{3300} \\times 100$<\/p>\n = $40.39 \\% \\approx 40 \\%$<\/p>\n 6)\u00a0Answer\u00a0(A)<\/strong><\/p>\n So Sohail’s overall percentage marks-<\/p>\n =$\\frac{33+37+28+26+32}{300}$ $\\times$100<\/p>\n =$\\frac{156}{300}$ $\\times$100<\/p>\n =52<\/p>\n 7)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Let the Total marks is ‘T’ .<\/p>\n The unreserved guy got 300 but failed by 24 marks i.e. his pass mark is 300 + 24 = 324 .<\/p>\n Given that , the pass mark for unreserved guy is 54% of the total . i.e. $\\frac{54}{100}$T = 324. 8)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Here the total subjects are 5 each subject has maximum 70 marks.<\/p>\n So total marks available are 70 \u00d7<\/span><\/span><\/span><\/span> 5 = 350<\/p>\n Total marks of Koel is = 49 + 37 + 45 + 53 + 55 = 239<\/p>\n Percentage of Koel is = $\\frac{239}{350}\\times100$ = 68.28, which is equal to approximate 68 percent<\/span><\/span><\/p>\n 9)\u00a0Answer\u00a0(A)<\/strong><\/p>\n 150 Kg of weight contains 10% low quality weight that is 15 Kg low quality weight. So X = 150 Kg<\/p>\n 10)\u00a0Answer\u00a0(A)<\/strong><\/p>\n The total marks obtained by Paresh is 102+118+104+114+96 = 534 So, the overall percentage obtained by Paresh is 534\/600 * 100 = 89%<\/p>\n![](\"https:\/\/cracku.in\/media\/uploads\/5710.PNG\")
<\/figure>\n
\nWe get , T = 600 .
\nAlso given that the pass mark for reserved guy is 40% of the total .i.e. {40\/100}* 600 = 240.<\/span><\/p>\n
\nLet the quantity of good quality wheat to be added be X.
\nSo, $15 = \\frac{5}{100}*(150+X)$
\nOr, $300 = 150+X$<\/p>\n
\nThe total marks that could have been obtained is 120*5\u00a0= 600<\/p>\n