Here you can download TISSNET 2022 Time Speed Distance [PDF] by Cracku. Very Important Time Speed Distance Questions for TISSNET 2022 based on asked questions in previous exam papers. These questions will help your TISSNET exam preparation. So kindly download the PDF for reference and do more practice.<\/p>\n
Download Time Speed Distance Questions for TISSNET<\/a><\/p>\n Get 5 TISSNET mocks at just Rs.299<\/a><\/p>\n Download TISSNET previous papers PDF<\/a><\/p>\n Question 1:\u00a0<\/b>A truck covers a certain distance in 12 h at the speed of 70 km\/h. What is the average speed of a car which travels a distance of 120 km more than the truck in the same time ?<\/p>\n a)\u00a076 km\/h<\/p>\n b)\u00a085 km\/h<\/p>\n c)\u00a082 km\/h<\/p>\n d)\u00a078 km\/h<\/p>\n e)\u00a0None of these<\/p>\n Question 2:\u00a0<\/b>A 420 m long train crosses a pole in 70 seconds. What is the speed of the train ?<\/p>\n a)\u00a05 m\/s<\/p>\n b)\u00a07 m\/s<\/p>\n c)\u00a04.5 m\/s<\/p>\n d)\u00a0Cannot be determined<\/p>\n e)\u00a0None of these<\/p>\n Question 3:\u00a0<\/b>Neela, Saroj and Paulami start running around a circular stadium and complete one round in 10 s, 6 s, and 14 s, respectively. In how much time will they meet again at the starting point ?<\/p>\n a)\u00a03 min, 30 s<\/p>\n b)\u00a02 min 28 s<\/p>\n c)\u00a04 min 45 s<\/p>\n d)\u00a01 min 40 s<\/p>\n e)\u00a0None of these<\/p>\n Question 4:\u00a0<\/b>A 240 metre long train crosses a 300 metre long platform in 27 seconds. What is the speed of the train in kmph ?<\/p>\n a)\u00a066<\/p>\n b)\u00a060<\/p>\n c)\u00a076<\/p>\n d)\u00a064<\/p>\n e)\u00a0None of these<\/p>\n Question 5:\u00a0<\/b>A train running at the speed of 60 kmph crosses a 200 metre long platform in 27 seconds. What is the length of the train ?<\/p>\n a)\u00a0250 metres<\/p>\n b)\u00a0200 metres<\/p>\n c)\u00a0240 metres<\/p>\n d)\u00a0450 metres<\/p>\n e)\u00a0None of these<\/p>\n Download TISSNET Previous Papers PDF<\/a><\/p>\n Question 6:\u00a0<\/b>A boat running downstreams covers a distance of 16 km in 2 hours while for covering the same distance upstream it takes 4 hours. What is the speed of the boat in still water?<\/p>\n a)\u00a04 kmph<\/p>\n b)\u00a06 kmph<\/p>\n c)\u00a08 kmph<\/p>\n d)\u00a0Data inadequate<\/p>\n e)\u00a0None of these<\/p>\n Question 7:\u00a0<\/b>A train running at the speed of 66 kmph crosses a signal pole in 18 seconds.\u00a0What is the length of the train?<\/p>\n a)\u00a0330 meters<\/p>\n b)\u00a0300 metres<\/p>\n c)\u00a0360 metres<\/p>\n d)\u00a0320 metres<\/p>\n e)\u00a0None of these<\/p>\n Question 8:\u00a0<\/b>Two cars A and B are running in the same direction. Car \u2018A\u2019 had already covered a distance of 60 kms, when car \u2018B\u2019 started running. The cars meet each other in 3 hours after car \u2018B\u2019 started running. What was the speed of car \u2018A\u2019 ?<\/p>\n a)\u00a040 kmph<\/p>\n b)\u00a060 kmph<\/p>\n c)\u00a045 kmph<\/p>\n d)\u00a0Cannot be determined<\/p>\n e)\u00a0None of these<\/p>\n Question 9:\u00a0<\/b>A 275 metre long train crosses a platform of equal length in 33 seconds What is the speed of the train in kmph ?<\/p>\n a)\u00a066<\/p>\n b)\u00a060<\/p>\n c)\u00a064<\/p>\n d)\u00a072<\/p>\n e)\u00a0None of these<\/p>\n Question 10:\u00a0<\/b>A train running at a speed of 60 kmph crosses a platform double its length in 32.4 seconds. What is the length of the platform?<\/p>\n a)\u00a0108 metres<\/p>\n b)\u00a0240 meters<\/p>\n c)\u00a0360 meters<\/p>\n d)\u00a090 meters<\/p>\n e)\u00a0Cannot be determined<\/p>\n Question 11:\u00a0<\/b>A 160 metre long train running at a speed of 90 kmph crosses a platform in 18 seconds.What is the length of the platform in metres?<\/p>\n a)\u00a0210<\/p>\n b)\u00a0240<\/p>\n c)\u00a0290<\/p>\n d)\u00a0310<\/p>\n e)\u00a0None of these<\/p>\n Question 12:\u00a0<\/b>A tap A fills a tank in 30 hours. Another tap B fills the tank in 24 hours. If the taps are opened for one hour each alternately, in how many hours would the tank be full?<\/p>\n a)\u00a010 hours<\/p>\n b)\u00a040\/3 hours<\/p>\n c)\u00a080\/3 hours<\/p>\n d)\u00a020 hours<\/p>\n e)\u00a030 hours<\/p>\n Question 13:\u00a0<\/b>The speeds of a boat downstream and upstream are 18 km\/hr and 8 km\/hr respectively. What is the speed of the stream?<\/p>\n a)\u00a02 km\/hr<\/p>\n b)\u00a03 km\/hr<\/p>\n c)\u00a04 km\/hr<\/p>\n d)\u00a05 km\/hr<\/p>\n e)\u00a0None of these<\/p>\n Question 14:\u00a0<\/b>A person has to travel from point B in certain time. Travelling at a speed of 5 kmph he reaches 48 minutes late and while travelling at a speed of 8 kmph he reaches 15 minutes early. What is the distance from point A to point B?<\/p>\n a)\u00a015 kms<\/p>\n b)\u00a091 kms<\/p>\n c)\u00a012 kms<\/p>\n d)\u00a018 kms<\/p>\n e)\u00a014 kms<\/p>\n Question 15:\u00a0<\/b>Ram and Shyam are travelling from point A to B, which are 60km apart. Travelling at a certain speed Ram takes one hour more than Shyam to reach point B. If Ram doubles his speed he will take 30 minutes less than Shyam to reach point B. At what speed was Ram driving from point A to B?<\/p>\n a)\u00a015 kmph<\/p>\n b)\u00a035 kmph<\/p>\n c)\u00a030 kmph<\/p>\n d)\u00a025 kmph<\/p>\n e)\u00a020 kmph<\/p>\n Question 16:\u00a0<\/b>The respective ratio between speed of the boat upstream and speed of the boat downstream is 3 : 4. What is the speed of the boat in still water if it covers 70 km downstream in 3 hours 30 minutes? (in km\/h)<\/p>\n a)\u00a018<\/p>\n b)\u00a018.5<\/p>\n c)\u00a017<\/p>\n d)\u00a017.5<\/p>\n e)\u00a016<\/p>\n Question 17:\u00a0<\/b>A train 350 m long takes 36 seconds to cross a man running at a speed of 5 km\/h in the direction opposite to that of train. What is the speed of the train?<\/p>\n a)\u00a030 km\/h<\/p>\n b)\u00a040 km\/h<\/p>\n c)\u00a024 km\/h<\/p>\n d)\u00a034 km\/h<\/p>\n e)\u00a0Other than those given as options<\/p>\n Question 18:\u00a0<\/b>A boat running downstream covers a distance of 24 km in 4 hours, while for covering the same distance upstreams it takes 6 hours. What is the speed of the boat in still water?<\/p>\n a)\u00a05.5 kmph<\/p>\n b)\u00a06 kmph<\/p>\n c)\u00a03.5 kmph<\/p>\n d)\u00a0Data inadequate<\/p>\n e)\u00a0None of these<\/p>\n Question 19:\u00a0<\/b>A motor starts with the speed of 70 kmph with its speed increasing every two hours by 10 kmph. In how many hours will it cover 345 km?<\/p>\n a)\u00a0$2\\frac{1}{4}$hours<\/p>\n b)\u00a0$4\\frac{1}{2}$hours<\/p>\n c)\u00a0$4$ hours $5$ minutes<\/p>\n d)\u00a0Cannot be determined<\/p>\n e)\u00a0None of these<\/p>\n Question 20:\u00a0<\/b>Swati walks 150 m everyday.\u00a0How many kilometers will she walk in three weeks ?<\/p>\n a)\u00a02.04<\/p>\n b)\u00a05.92<\/p>\n c)\u00a04.18<\/p>\n d)\u00a03.15<\/p>\n e)\u00a0None of these<\/p>\n Take TISSNET Mock Tests<\/a><\/p>\n Answers & Solutions:<\/strong><\/span><\/p>\n 1)\u00a0Answer\u00a0(E)<\/strong><\/p>\n The distance travelled by the truck in 12 hours equals 12*70 = 840 km So, the average speed of the car equals $\\frac{960}{12} = 80$ kmph<\/p>\n 2)\u00a0Answer\u00a0(E)<\/strong><\/p>\n Time taken by the train to cross the pole is 70 seconds. Hence, the speed of the train is $\\frac{420}{70}=6$ seconds.<\/p>\n 3)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Neela completes one round around the circular stadium in 10 seconds. Hence, the three of them meet again at the starting point in LCM(10,6,14) seconds. 4)\u00a0Answer\u00a0(E)<\/strong><\/p>\n The total distance travelled by the train equals 240+300 = 540 metres. Hence, the speed of the train equals $\\frac{540}{27} = 20$ m\/s As this is not given in the options, the correct answer is option (e)<\/p>\n 5)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Let the length of the train be S. So, $S+200 = \\frac{50}{3}*27 = 450$ 6)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Let the speed of the boat in still water be B and the speed of the water be W. From the information given, the speed of the boat downstream is 16\/2 = 8 kmph Hence, B+W = 8 and B-W =4 7)\u00a0Answer\u00a0(A)<\/strong><\/p>\n 66 kmph = 66 *5\/18 m\/s<\/p>\n It takes 18 secs to cross the post. So, length = 66 * 18* 5\/18 = 330 metres.<\/p>\n 8)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Let the speed of car A be ‘x’ kmph and the speed of car B be ‘y’ kmph. Distance covered by B in three hours is 3y So, 3y = 3x + 60 or y=x+20 9)\u00a0Answer\u00a0(B)<\/strong><\/p>\n The length of the train is 275 m.\u00a0Hence, the length of the platform is also 275 m. Hence, the speed of the train is $\\frac{550}{33} = \\frac{50}{3}$ m\/s Hence, the speed of the train in kmph is $\\frac{50}{3}*\\frac{18}{5} = 60$ kmph 10)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Let the length of the train be ‘x’ metres 11)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Let the length of the platform be ‘x’ metres 12)\u00a0Answer\u00a0(C)<\/strong><\/p>\n In one hour, A fills 1\/30th of the tank Hence, they will take 2\/(3\/40) = 80\/3 hours to fill the tank.<\/p>\n 13)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Let the speed of the boat in still water be \u2018u\u2019. 14)\u00a0Answer\u00a0(E)<\/strong><\/p>\n Let the distance between A and B be ‘d’ km and time taken be ‘t’ hrs. 15)\u00a0Answer\u00a0(E)<\/strong><\/p>\n Let the speed of Ram be ‘v’ kmph 16)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Let the speed of boat in still water and speed of river be B km\/hr and R km\/hr respectively<\/p>\n Speed of boat in downstream = (B+R)km\/hr<\/p>\n Speed of boat in upstream = (B-R) km\/hr<\/p>\n It is given that $\\frac{B-R}{B+R} = \\frac{3}{4}$<\/p>\n we get , B = 7 R<\/p>\n Now it is given that boat covers 70 km in 3.5 hours downstream<\/p>\n so ,<\/p>\n 70 = (B+R)3.5<\/p>\n B+R = 20<\/p>\n R = 2.5 km\/hr<\/p>\n B = 17.5 km\/hr<\/p>\n 17)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Let the speed of the train be x m\/s 18)\u00a0Answer\u00a0(E)<\/strong><\/p>\n Let the speed of the boat be S and the speed of the stream be R.<\/p>\n So, 24 \/ 4 = 6 = S + R<\/p>\n 24 \/ 6 = 4 = S – R<\/p>\n So, 2S = 10 => S = 5 and R = 1<\/p>\n So, speed of the boat in still water = 1 kmph<\/p>\n 19)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Distance = Speed $\\times$ Time<\/p>\n Initial speed = 70 kmph<\/p>\n In first 2 hours, motor covers a distance = $70 \\times 2 = 140~km$<\/p>\n Speed after 2 hours = 70 + 10 = 80 kmph<\/p>\n In the next 2 hours, it covers a distance = $80 \\times 2 = 160~km$<\/p>\n Distance covered = 300 km<\/p>\n Now, the speed is 90 kmph<\/p>\n Remaining 45 km is covered in $\\frac{45}{90}$ = 0.5 hr<\/p>\n Total time taken to cover 345 km = 2 + 2 + 0.5 = 4.5 hr<\/p>\n 20)\u00a0Answer\u00a0(D)<\/strong><\/p>\n The number of days in 3 weeks is 3*7 = 21 Hence, the distance covered by Swati in 3 weeks equals 150*21 = 3150 metres
\nHence, the car travels 840 + 120 = 960 kms in 12 hours.<\/p>\n
\nThe length of the train is 420 metres.<\/p>\n
\nSaroj completes one round around the circular stadium in 6 seconds.
\nPaulami completes one round around the circular stadium in 14 seconds.<\/p>\n
\nThe least common multiple (LCM) of 10,6 and 14 is 210 seconds.
\nSo, the three of them meet again after 210 seconds which is 3 minutes 30 seconds.<\/p>\n
\nThis distance is covered by the train in 27 seconds.<\/p>\n
\nThis speed when converted to kmph equals $20 * \\frac{18}{5} = 72$ kmph<\/p>\n
\nSo, the total distance travelled by the train while crossing the platform is S+200.
\nThe speed of the train is 60 Kmph and the time taken is 27 seconds.
\nThe speed of the train in m\/s is $60*\\frac{5}{18} = \\frac{50}{3}$ m\/s<\/p>\n
\nHence, S = 250 metres.<\/p>\n
\nSo, speed of the boat downstream is B+W and the speed of the boat upstream is B-W.<\/p>\n
\nSpeed of the boat upstream is 16\/4 = 4 kmph<\/p>\n
\nSo, B = 6 kmph and W = 2 kmph<\/p>\n
\nBy the time car B\u00a0started running, car A covered 60 Km.<\/p>\n
\nDistance covered by A in three hours is 3x<\/p>\n
\nHence, the speed of B is 20 kmph more than the speed of A. As we don’t know the speed of car B, we can’t find the exact speed of car A. We can just infer that the speed of car A is 20 kmph less than the speed of car\u00a0B.<\/p>\n
\nThe train covers a total distance of 550 m in 33 seconds.<\/p>\n
\nTo convert this speed into kmph, we need to multiply it by $\\frac{18}{5}$<\/p>\n
\nSo, the correct option is option (b)<\/p>\n
\nLength of the platform = 2x
\nDistance travelled by the train = x + 2x = 3x
\nSpeed of the train = 60 kmph = $60 \\times \\frac{5}{18}$ m\/sec
\nDistance = Speed $\\times$ Time
\n$3x = 60 \\times \\frac{5}{18} \\times 32.4$
\n$x = 180$
\nThe length of the platform = 2x = 360 m<\/p>\n
\nDistance travelled by the train = 160 + x
\nSpeed of the train = 90 kmph = $90\\times \\frac{5}{18}$ = 25 m\/sec
\nDistance = Speed $\\times$ Time
\n$160 + x = 25 \\times 18$
\n$x = 290$
\nLength of the platform = 290 m<\/p>\n
\nIn one hour, B fills 1\/24th of the tank
\nIn two hours, A and B alternately fill 1\/30 + 1\/24 = 4\/120 + 5\/120 = 9\/120 = 3\/40th of the tank<\/p>\n
\nLet the speed of the stream be \u2018v\u2019.
\nThe speed of the boat upstream = u-v
\nThe speed of the boat downstream = u+v
\nIt is given that,
\nu-v = 8 and u+v = 18
\nSolving them we get, u = 13 and v = 5.
\nThus the speed of the stream is 5 km\/hr.
\nHence the answer to this question is Option D.<\/p>\n
\nIn both the cases, distance travelled is the same.
\nDistance = Speed $\\times$ Time
\nCase (i) Time taken = 48 min late = (t + 0.8) hrs
\n$d = 5 \\times (t + 0.8)$
\nCase (ii) Time taken = 15 min early = (t – 0.25) hrs
\n$d = 8 \\times (t – 0.25)$
\nOn equating them, we get
\n5t + 4 = 8t – 2
\nt = 2
\nDistance, d = 5 (2 + 0.8) = 14 km<\/p>\n
\nTime taken by Shyam be ‘t’ hrs
\nDistance = Speed $\\times$ Time
\n60 = v (t + 1)
\nAfter doubling the speed,
\n60 = 2v(t – 0.5)
\nSimplifying them, we get
\nv (t + 1) = 2v (t – 0.5)
\nt = 2
\nv = 60\/3 = 20 kmph<\/p>\n
\nSpeed of the man = 5km\/hr = 1.388m\/s
\nRelative speed of man when he is running in opposite direction = (x+1.388)
\nHowever train crossess him in 36 seconds = 350\/36 =\u00a0 9.722 m\/s
\nx+1.388 = 9.722
\nx = 8.334 m\/s
\nx = 30 km\/hr<\/p>\n
\nSwati walks 150 metres everyday.<\/p>\n
\n1000 metres equal one kilometre. Hence, the distance covered by Swati in 3 weeks is 3.15 km<\/p>\n