Download CMAT 2022 Simple and Compound Interest Questions pdf by Cracku. Very Important Simple and Compound Interest Questions for CMAT 2022 based on asked questions in previous exam papers. These questions will help your CMAT preparation. So kindly download the PDF for reference and do more practice.<\/p>\n
Download Simple and Compound Interest Questions for CMAT<\/a><\/p>\n Get 5 CMAT mocks at just Rs.299<\/a><\/p>\n Download CMAT previous papers PDF<\/a><\/p>\n Question 1:\u00a0<\/b>The present worth of Rs. 2809 due 2 yr hence at 6% per annum, is<\/p>\n a)\u00a0Rs. 2100<\/p>\n b)\u00a0Rs. 2600<\/p>\n c)\u00a0Rs. 2400<\/p>\n d)\u00a0Rs. 2500<\/p>\n e)\u00a0None of these<\/p>\n Question 2:\u00a0<\/b>If a sum of money at simple interest doubles in 6 years, it will become 4 times in<\/p>\n a)\u00a017 years<\/p>\n b)\u00a015 years<\/p>\n c)\u00a016 years<\/p>\n d)\u00a018 years<\/p>\n e)\u00a0None of these<\/p>\n Question 3:\u00a0<\/b>The compound interest on Rs.10240 at 6 1\/4% per annum for 2 yr 73 days is<\/p>\n a)\u00a0Rs. 1464.50<\/p>\n b)\u00a0Rs. 1664.50<\/p>\n c)\u00a0Rs. 1480<\/p>\n d)\u00a0Rs. 1580.50<\/p>\n e)\u00a0None of these<\/p>\n Instructions<\/b><\/p>\n Directions for the next five questions: Study the following table carefully to answer the questions. <img “=”” alt=”” class=”img-responsive” src=”https:\/\/cracku.in\/media\/radpress\/entry_images\/5484.png “\/><\/p>\n Question 4:\u00a0<\/b>Company D offers compound interest under scheme II and Simple Interest under Scheme IV. Abhijt invested Rs. 25000 with this company under Scheme IV and after one year switched to Scheme II along with the interest for one more year. What is the total amount he will get at the end of two years?<\/p>\n a)\u00a0Rs. 28939.25<\/p>\n b)\u00a0Rs. 29838.75<\/p>\n c)\u00a0Rs. 31748.25<\/p>\n d)\u00a0Rs. 31738.75<\/p>\n e)\u00a0None of these<\/p>\n Question 5:\u00a0<\/b>Company E offers compound interest under Scheme I and Company A offers simple interest under scheme IV. What will be the difference between the interest earned under Scheme I of company E and Scheme IV of company A respectively in two years on an amount of Rs. 1.2 lakh?<\/p>\n a)\u00a0Rs 1428<\/p>\n b)\u00a0Rs. 1328<\/p>\n c)\u00a0Rs. 1528<\/p>\n d)\u00a0Rs. 1548<\/p>\n e)\u00a0None of these<\/p>\n Download CMAT Previous Papers PDF<\/a><\/p>\n Question 6:\u00a0<\/b>Mr. X deposited an amount in Scheme II with company C for two years. After that he withdrew the amount and reinvested only the principal amount in scheme IV of Company B for two years. Total amount of simple interest accrued from the two schemes is Rs. 14800. What was the principal amount?<\/p>\n a)\u00a0Rs. 48000<\/p>\n b)\u00a0Rs. 42000<\/p>\n c)\u00a0Rs. 40000<\/p>\n d)\u00a0Can\u2019t be determined<\/p>\n e)\u00a0None of these<\/p>\n Question 7:\u00a0<\/b>Vinod borrows money from Shyam at compound interest compounded annually at 25% per annum. If Vinod repays the money with installments of Rs.625 each year for 4 years, then what is the amount he has borrowed from Shyam ?<\/p>\n a)\u00a0Rs. 2500<\/p>\n b)\u00a0Rs. 1476<\/p>\n c)\u00a0Rs. 900<\/p>\n d)\u00a0Rs. 644<\/p>\n e)\u00a0Rs. 1820<\/p>\n Question 8:\u00a0<\/b>The compound interest on a certain sum of money for a period of 3 years at 10% per annum is Rs 331. Find the principal.<\/p>\n a)\u00a0Rs 500<\/p>\n b)\u00a0Rs 1500<\/p>\n c)\u00a0Rs 1000<\/p>\n d)\u00a0Rs 2000<\/p>\n e)\u00a0None of the above<\/p>\n Question 9:\u00a0<\/b>Find the compound interest accrued over three years on a principal amount of 40000 at the rate of 20% per annum.<\/p>\n a)\u00a029120<\/p>\n b)\u00a018640<\/p>\n c)\u00a032120<\/p>\n d)\u00a024680<\/p>\n e)\u00a036440<\/p>\n Question 10:\u00a0<\/b>What is the compound interest obtained on Rs. 1600 in two years at an interest rate of 12.5% p.a ?<\/p>\n a)\u00a0Rs. 425<\/p>\n b)\u00a0Rs. 400<\/p>\n c)\u00a0Rs. 450<\/p>\n d)\u00a0Rs. 430<\/p>\n e)\u00a0Rs. 420<\/p>\n Question 11:\u00a0<\/b>The difference between the simple interest and compound interest on a sum of money borrowed for 2 years at 10% per annum is Rs 500. Find the sum of money borrowed.<\/p>\n a)\u00a0Rs 55000<\/p>\n b)\u00a0Rs 50000<\/p>\n c)\u00a0Rs 45000<\/p>\n d)\u00a0Rs 40000<\/p>\n e)\u00a0None of the above<\/p>\n Question 12:\u00a0<\/b>The simple interest accrued in 2 years on a principal of Rs. 24000 is one-eighth of the principal. What is the rate of simple interest p.c.p.a. ?<\/p>\n a)\u00a05<\/p>\n b)\u00a04.5<\/p>\n c)\u00a06.25<\/p>\n d)\u00a07.25<\/p>\n e)\u00a0None of these<\/p>\n Question 13:\u00a0<\/b>Find the compound interest accrued on a principal amount of Rs 45000 at the rate 20% per annum for two years.<\/p>\n a)\u00a018600<\/p>\n b)\u00a019100<\/p>\n c)\u00a019800<\/p>\n d)\u00a020500<\/p>\n e)\u00a021600<\/p>\n Question 14:\u00a0<\/b>An amount of 20,000 is invested in a mutual fund named Funds-R-us that calculates compound interest semiannually at 8% pa. What will be the interest obtained in 1.5 years?<\/p>\n a)\u00a02155.09<\/p>\n b)\u00a02497.28<\/p>\n c)\u00a02355.09<\/p>\n d)\u00a02455.09<\/p>\n e)\u00a0None of the above<\/p>\n Question 15:\u00a0<\/b>Find the rate of interest if the principal doubles itself after 4 years at simple interest.<\/p>\n a)\u00a015% p.a<\/p>\n b)\u00a020% p.a<\/p>\n c)\u00a025% p.a<\/p>\n d)\u00a050% p.a<\/p>\n e)\u00a0None of these<\/p>\n Take CMAT Mock Tests<\/a><\/p>\n Question 16:\u00a0<\/b>Find the simple interest offered by the bank on the principal of Rs 20,000 at the rate of 10% per annum for the time period of 3 years.<\/p>\n a)\u00a04000<\/p>\n b)\u00a05000<\/p>\n c)\u00a06000<\/p>\n d)\u00a07000<\/p>\n e)\u00a0None of these<\/p>\n Question 17:\u00a0<\/b>If the difference between the compound interest and simple interest on a sum is Rs. 240 accrued in two years at the rate of 10 percent per annual, then what is the principal amount?<\/p>\n a)\u00a048000<\/p>\n b)\u00a035000<\/p>\n c)\u00a024000<\/p>\n d)\u00a012000<\/p>\n e)\u00a010000<\/p>\n Question 18:\u00a0<\/b>What will be the simple interest accrued on an amount of Rs. 25000 with a rate of 20% for 3 years?<\/p>\n a)\u00a0Rs. 19000<\/p>\n b)\u00a0Rs. 16000<\/p>\n c)\u00a0Rs. 17000<\/p>\n d)\u00a0Rs. 18000<\/p>\n e)\u00a0Rs. 15000<\/p>\n Question 19:\u00a0<\/b>If the amount Rs. 102300 is distributed among 33 children. What would be the difference in the amount that each child would have got had the number of children been 100?<\/p>\n a)\u00a02385<\/p>\n b)\u00a02077<\/p>\n c)\u00a02763<\/p>\n d)\u00a02173<\/p>\n e)\u00a01984<\/p>\n Question 20:\u00a0<\/b>Mr. sharma deposits an amount of Rs. 50000 to obtain a simple interest at the rate of 12 p.c.p.a. for 4 years. What total amount will Mr. Sharma get at the end of 4 years?<\/p>\n a)\u00a075000<\/p>\n b)\u00a074000<\/p>\n c)\u00a073000<\/p>\n d)\u00a072000<\/p>\n e)\u00a071000<\/p>\n Question 21:\u00a0<\/b>What amount of simple interest can be obtained on an amount of Rs. 30000 at the rate of 40% for 3 years?<\/p>\n a)\u00a032000<\/p>\n b)\u00a033000<\/p>\n c)\u00a034000<\/p>\n d)\u00a035000<\/p>\n e)\u00a036000<\/p>\n Question 22:\u00a0<\/b>If the total amount, with simple interest incurred for 2 years on an amount of 15000 is Rs. 21000. What will be the rate of interest?<\/p>\n a)\u00a010<\/p>\n b)\u00a020<\/p>\n c)\u00a030<\/p>\n d)\u00a040<\/p>\n e)\u00a050<\/p>\n Question 23:\u00a0<\/b>What is the ratio of the simple interest and compound interest on Rs. 2000 which is lent at an interest rate of 10% for two years?<\/p>\n a)\u00a010:11<\/p>\n b)\u00a04:5<\/p>\n c)\u00a019:20<\/p>\n d)\u00a020:21<\/p>\n e)\u00a0100:121<\/p>\n Question 24:\u00a0<\/b>What is the difference between compound interest and simple interest on an amount of Rs. 5000 with a rate of 40% for 2 years?<\/p>\n a)\u00a01000<\/p>\n b)\u00a02000<\/p>\n c)\u00a0300<\/p>\n d)\u00a0800<\/p>\n e)\u00a01200<\/p>\n Question 25:\u00a0<\/b>What will be the simple interest on a principal amount of 15000 with a rate of 10% for 3 years?<\/p>\n a)\u00a05000<\/p>\n b)\u00a04500<\/p>\n c)\u00a04000<\/p>\n d)\u00a05500<\/p>\n e)\u00a06000<\/p>\n Question 26:\u00a0<\/b>What will be simple interest on an amount of Rs. 1200 with 20% annual rate for 3 years?<\/p>\n a)\u00a0700<\/p>\n b)\u00a0720<\/p>\n c)\u00a0800<\/p>\n d)\u00a0850<\/p>\n e)\u00a0870<\/p>\n Question 27:\u00a0<\/b>Simple interest on a certain sum at 10% rate is 200 for 2 years. What will be the compound interest on the sum with a rate of 10% for 2 years?<\/p>\n a)\u00a0220<\/p>\n b)\u00a0210<\/p>\n c)\u00a0250<\/p>\n d)\u00a0300<\/p>\n e)\u00a0330<\/p>\n Question 28:\u00a0<\/b>What will be the simple interest on a principal amount of 10000 with an annual rate of 20% for a duration of 2 years?<\/p>\n a)\u00a06000<\/p>\n b)\u00a03000<\/p>\n c)\u00a04000<\/p>\n d)\u00a08000<\/p>\n e)\u00a02000<\/p>\n Question 29:\u00a0<\/b>What is the amount to be paid at the end of 10 years on a sum of Rs 25000 borrowed at 8% p.a.?<\/p>\n a)\u00a0Rs 45000<\/p>\n b)\u00a0Rs 20000<\/p>\n c)\u00a0Rs 30000<\/p>\n d)\u00a0Rs 35000<\/p>\n e)\u00a0Rs 40000<\/p>\n Question 30:\u00a0<\/b>What is the simple interest on a sum of Rs 30000 borrowed for 2 years at 5% p.a.?<\/p>\n a)\u00a0Rs 2500<\/p>\n b)\u00a0Rs 4000<\/p>\n c)\u00a0Rs 2000<\/p>\n d)\u00a0Rs 3000<\/p>\n e)\u00a0None of the above<\/p>\n Take CMAT Mock Tests<\/a><\/p>\n Answers & Solutions:<\/strong><\/span><\/p>\n 1)\u00a0Answer\u00a0(D)<\/strong><\/p>\n PW= Rs. ${2809\/(1+6\/100)^2 }$ = Rs. (2809\u00d750\/53\u00d750\/53) = Rs. 2500<\/p>\n 2)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Let the sum be x. Then, S.I. =x. 3)\u00a0Answer\u00a0(A)<\/strong><\/p>\n P = Rs. 10240, R=25\/4%, T = 2 years 73 days<\/p>\n A=$[10240\\times(1+25\/(4\\times100))^2\\times(1+73\/365\\times25\/(4\\times100))]$<\/p>\n = Rs. $[10240\\times17\/16\\times17\/16\\times(1+1\/80)]$ = Rs.$(10240\\times17\/16 \\times17\/16\\times81\/80)$ = Rs.11704.50<\/p>\n CI = Rs. (11704.50-10240) = Rs. 1464.50<\/p>\n 4)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Interest for the first year = 25000 \u00d7 1x 9.5\/100 = 2375<\/p>\n Hence amount obtained = 25000+2375 = 27375.<\/p>\n This amount is invested again on compound interest,<\/p>\n So interest obtained = 27375 \u00d7 1×9\/100 = Rs. 2463.75<\/p>\n Hence the total amount = 27375+2463.75 = Rs. 29838. 75<\/p>\n 5)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Scheme I of company E Scheme IV of company A 6)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Let principal amount be Rs. x. 7)\u00a0Answer\u00a0(B)<\/strong><\/p>\n The formula for installments is : 8)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Let the principal be P. 9)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Compound Interest = $P(1 + \\frac{r}{100})^n – P$ 10)\u00a0Answer\u00a0(A)<\/strong><\/p>\n The amount received after two years at a compounded rate of 12.5 % p.a is $1600*(1+12.5\\%)^2 = 1600*\\frac{112.5}{100}*\\frac{112.5}{100} =2025$ 11)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Let the amount borrowed by P.<\/p>\n Simple Interest for the first year = P*1*10\/100 = P\/10<\/p>\n Simple interest for the second year = P\/10<\/p>\n Total simple interest = P\/5<\/p>\n Compound interest for the first year = P*1*10\/100 = P\/10<\/p>\n Principal for the second year = P + CI for first year = P + P\/10 = 11P\/10<\/p>\n CI for second year = 11P\/10 * 1 * 10\/100 = 11P\/100<\/p>\n Total CI = P\/10 + 11P\/100 = 21P\/100<\/p>\n Difference between CI and SI for the two years = 21P\/100 – P\/5 = P\/100 = 500<\/p>\n => Sum borrowed = 500*100 = Rs 50,000<\/p>\n 12)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Let the rate be r.<\/p>\n SI = Prt\/100 = P\/8<\/p>\n r * 2 \/ 100 = 1\/8<\/p>\n r = 50\/ 8 = 6.25<\/p>\n 13)\u00a0Answer\u00a0(C)<\/strong><\/p>\n CI = $P(1+(\\frac{r}{100})^n – P$ 14)\u00a0Answer\u00a0(B)<\/strong><\/p>\n The interest rate is 8% pa. So, semi annual interest is 4%. The amount after 1.5 years (3 time periods) is 15)\u00a0Answer\u00a0(C)<\/strong><\/p>\n SI = P*R*T\/100 16)\u00a0Answer\u00a0(C)<\/strong><\/p>\n SI = P*R*T\/100 = 20000*10*3\/100 = Rs 6000<\/p>\n 17)\u00a0Answer\u00a0(C)<\/strong><\/p>\n As we know that, when difference in the compound interest and simple interest for 2 years with a rate equals to r% on a sum is x, then sum will be = $ x \\times (\\frac{100}{r})^{2} $ 18)\u00a0Answer\u00a0(E)<\/strong><\/p>\n Simple Interest will be = $\\frac{25000 \\times 20 \\times 3}{100}$ = Rs. 15000<\/p>\n 19)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Amount received by each child = $\\frac{102300}{33} = 3100$ 20)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Simple Interest = (50000)($\\frac{12}{100}$)(4) = 24000 21)\u00a0Answer\u00a0(E)<\/strong><\/p>\n Simple interest = $(30000 \\times \\frac{40}{100} \\times 3) = 36000$<\/p>\n 22)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Simple interest = 6000 = $ 15000 \\times \\frac{r}{100} \\times 2$ (Where r is the rate of interest) 23)\u00a0Answer\u00a0(D)<\/strong><\/p>\n The simple interest on Rs. 2000 for two years at 10% p.a is 2000*10%*2=Rs. 400 24)\u00a0Answer\u00a0(D)<\/strong><\/p>\n compound interest = 5000 – 5000(140\/100)(140\/100) = 4800 25)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Simple Interest = PRT\/100 26)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Simple Interest = 1200*(20\/100)*3 = 720<\/p>\n 27)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Principal amount = 200*100\/10*2= 1000 28)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Simple interest will be = 10000*(20\/100)*2 = 4000<\/p>\n 29)\u00a0Answer\u00a0(A)<\/strong><\/p>\n A = P + SI = P + PTR\/100 = 25000 + 25000*10*8\/100 = 45000 30)\u00a0Answer\u00a0(D)<\/strong><\/p>\n SI = PTR\/100 = 30000 * 2 * 5\/100 = Rs 3000<\/p>\n
\nRate of interest (pcpa) offered by five companies on deposits under different schemes<\/strong><\/p>\n
\n\u2234 Rate = ((100\u00d7x)\/(x\u00d76))%=50\/3%
\nNow, sum = x, S.I. = 3x, Rate = 50\/3 %.
\nTime= (100\u00d73x)\/(x\u00d750\/3) = 18 years.<\/p>\n
\nCI = 120000 [(1+ 9\/100)^2- 1]
\n= 120000 [((109\u00d7109)\/(100\u00d7100)-1)]
\n= 120000 \u00d7 1881\/10000 = Rs. 22572<\/p>\n
\nSI = (120000\u00d72\u00d710)\/100 = Rs. 24000
\nDifference = 24000 – 22572 = Rs. 1428<\/p>\n
\n(x\u00d79\u00d72)\/100 + (x\u00d79.5\u00d72)\/100 = 14800
\nor (0.18+0.19) = 14800
\nX = 14800\/0.37 = Rs. 40000<\/p>\n
\nP = $\\frac{x}{1 + r\/100} + \\frac{x}{(1 + r\/100)^2} + \\frac{x}{(1 + r\/100)^3}……\\frac{x}{(1 + r\/100)^n}$
\nthus, P = $\\frac{625}{1 + 25\/100} + \\frac{625}{(1 + 25\/100)^2} + \\frac{625}{(1 + 25\/100)^3} + \\frac{625}{(1 + 25\/100)^4}$
\n= 500 + 400 + 320 + 256
\n= Rs. 1476<\/p>\n
\nSo, amount = $P(1+10\/100)^3$
\nInterest = $P(1+10\/100)^3 – P$ = 331
\nFrom the options, if P = 1000,
\n$P(1.1)^3$ – P = 331
\nSo, the principal is Rs 1000<\/p>\n
\n=> CI = $40000 *(1 + 0.2)^3$ – 40000
\n= (40000 * 1.728) – 40000
\n= 40000 * 0.728
\n= 728 * 40
\n= 29120<\/p>\n
\nSo, the interest obtained on the principal equals 2025-1600 = Rs. 425<\/p>\n
\n=> CI = $45000(1.2)^2 – 45000$ = 45000*0.44 = 19800<\/p>\n
\n20,000 x (1 + $ \\frac {4}{100}) ^ {3}$ = 22,497.28
\nSo, the interest = 22,497.28 – 20,000 = 2497.28 rupees<\/p>\n
\nLet principal be x
\nIf the principal doubles itself after 4 years, then SI = 2x-x = x
\nx = x*r*4\/100
\nr = 25% p.a<\/p>\n
\nSo sum = $ 240 \\times (\\frac{100}{10})^{2} $ = $ 240 \\times 100 $ = 24000<\/p>\n
\nIf there were 100 children then the amount received by each child = 102300\/100 = 1023
\nHence the required difference = 3100 – 1023 = 2077
\nThus option B is correct.<\/p>\n
\nTotal amount = 50000+24000 = 74000<\/p>\n
\nHence, r=20%<\/p>\n
\nThe compound interest on Rs. 2000 for two years at 10% p.a is 2000*(100%+10%)*(100%+10%) – 2000 = 2000*1.1*1.1 – 2000 = Rs. 420
\nHence, the ratio is 400:420 = 20:21<\/p>\n
\nsimple interest = 4000
\nDifference = 800<\/p>\n
\nP=15000
\nR=10%
\nT=3 years
\nSo simple interest will be = 4500<\/p>\n
\nCompound Interest = 1000-1000*(110\/100)*(110\/100) = 210<\/p>\n
\nSo, amount to be paid = Rs 45000<\/p>\n