Get 5 CMAT mocks at just Rs.299<\/a><\/p>\n Download CMAT previous papers PDF<\/a><\/p>\n Question 1:\u00a0<\/b>Three friends J, K and L jog around a circular stadium and complete one round in 12, 18 and 20 seconds respectively. In how many minutes will all the three meet again at the starting point<\/p>\n a)\u00a05<\/p>\n b)\u00a08<\/p>\n c)\u00a012<\/p>\n d)\u00a03<\/p>\n e)\u00a0None of these<\/p>\n Question 2:\u00a0<\/b>The speed of a boat when travelling downstream is 32 Kms. \/ Hr. , whereas when travelling upstream it is 28 kms\/hr. What is the speed of the boat in still water ?<\/p>\n a)\u00a027 Kms.\/Hr.<\/p>\n b)\u00a029 Kms.\/ Hr.<\/p>\n c)\u00a031 Kms.\/ Hr.<\/p>\n d)\u00a0Cannot be determined<\/p>\n e)\u00a0None of these<\/p>\n Question 3:\u00a0<\/b>A pump can fill a tank with water in 2 hours. Because of a leak, it took 2$\\frac{1}{3}$ hours to fill the tank. The leak can drain all the water of the tank in<\/p>\n a)\u00a04$\\frac{1}{3}$ hours<\/p>\n b)\u00a07 hours<\/p>\n c)\u00a08 hours<\/p>\n d)\u00a014 hours<\/p>\n e)\u00a0None of these<\/p>\n Question 4:\u00a0<\/b>If I walk at 4 km\/h, I miss the bus by 10 min. If I walk at 5 km\/h, I reach 5 min before the arrival of the bus. How far I walk to reach the bus stand?<\/p>\n a)\u00a05 km<\/p>\n b)\u00a05.5 km<\/p>\n c)\u00a06 km<\/p>\n d)\u00a07.5 km<\/p>\n e)\u00a0None of these<\/p>\n Question 5:\u00a0<\/b>The speed of a boat in still water is 15 km\/hr and the rate of current is 3 km\/hr. The distance travelled down steam in 12 minutes is:<\/p>\n a)\u00a03.3 km<\/p>\n b)\u00a02.9 km<\/p>\n c)\u00a02.4 km<\/p>\n d)\u00a03.6 km<\/p>\n e)\u00a0None of these<\/p>\n Download CMAT Previous Papers PDF<\/a><\/p>\n Take CMAT Mock Tests<\/a><\/p>\n Question 6:\u00a0<\/b>An express train travelled at an average speed of 75 km\/h stopping for 5 min every 125 km. How long did it take to reach its destination 375 km from the starting point?<\/p>\n a)\u00a06 h 30 min<\/p>\n b)\u00a04 h 45 min<\/p>\n c)\u00a03 h 15 min<\/p>\n d)\u00a05 h 10 min<\/p>\n e)\u00a0None of these<\/p>\n Question 7:\u00a0<\/b>A boat\u2019s speed with the current is 15 kmph and the boat\u2019s speed against the current is 5 kmph. What is the speed of the current?<\/p>\n a)\u00a015 kmph<\/p>\n b)\u00a010 kmph<\/p>\n c)\u00a05 kmph<\/p>\n d)\u00a020 kmph<\/p>\n e)\u00a0None of the above<\/p>\n Question 8:\u00a0<\/b>A 400 meter long train crosses a man who is travelling in opposite direction with a speed of 10 kmph in 4 seconds. Find the speed of the train (in km\/h)?<\/p>\n a)\u00a0250<\/p>\n b)\u00a0350<\/p>\n c)\u00a0270<\/p>\n d)\u00a0380<\/p>\n e)\u00a0320<\/p>\n Question 9:\u00a0<\/b>The average speed of a bus is 8 times the average speed of a bike. The bike covers a distance of 186 km in 3 hours. How much distance will the bus cover in 10 hours ?<\/p>\n a)\u00a04069 km<\/p>\n b)\u00a04096 km<\/p>\n c)\u00a04960 km<\/p>\n d)\u00a04690 km<\/p>\n e)\u00a0None of these<\/p>\n Question 10:\u00a0<\/b>A 210 m long train takes 6 s to cross a man running at 9 km\/h in a direction opposite to that of the train. What is the speed of the train? (in km\/h)<\/p>\n a)\u00a0127<\/p>\n b)\u00a0121<\/p>\n c)\u00a0117<\/p>\n d)\u00a0108<\/p>\n e)\u00a0111<\/p>\n Question 11:\u00a0<\/b>A truck covers a distance of 640 km in 10 h. A car covers the same distance in 8 h. What is the respective ratio between the speed of the truck and the car?<\/p>\n a)\u00a03: 4<\/p>\n b)\u00a01: 2<\/p>\n c)\u00a05: 6<\/p>\n d)\u00a06: 7<\/p>\n e)\u00a0None of these<\/p>\n Question 12:\u00a0<\/b>Faisal walks 325 m every day .How many kilometers will he walk in four weeks?<\/p>\n a)\u00a06.2<\/p>\n b)\u00a09.1<\/p>\n c)\u00a08.6<\/p>\n d)\u00a07.8<\/p>\n e)\u00a0None of these<\/p>\n Question 13:\u00a0<\/b>A 280 m long train crosses a platform thrice its length in 6 min 40 s. What is the speed of the train?<\/p>\n a)\u00a03.2 m\/s<\/p>\n b)\u00a01.4 m\/s<\/p>\n c)\u00a02.8 m\/s<\/p>\n d)\u00a0Cannot be determined<\/p>\n e)\u00a0None of these<\/p>\n Question 14:\u00a0<\/b>Harish, Dilip and Asha start running around a circular stadium and complete one round in 27 s, 9 s and 36 s respectively. In how much time will they meet again at the same point?<\/p>\n a)\u00a01 min 48 s<\/p>\n b)\u00a02 min 36 s<\/p>\n c)\u00a03 min 11 s<\/p>\n d)\u00a02 min 25 s<\/p>\n e)\u00a0None of these<\/p>\n Question 15:\u00a0<\/b>The radius of a circular field is equal to the side of a square field whose perimeter is 784 feet. What is the area of the circular field?<\/p>\n a)\u00a0107914 sq ft<\/p>\n b)\u00a0120736 sq ft<\/p>\n c)\u00a0107362 sq ft<\/p>\n d)\u00a0127306 sq ft<\/p>\n e)\u00a0None of these<\/p>\n Take CMAT Mock Tests<\/a><\/p>\n Question 16:\u00a0<\/b>Three friends J K and L jog around a circular stadium and complete one round in 12, 18 and 20 seconds respectively In how many minutes will all the three meet again at the starting point ?<\/p>\n a)\u00a05<\/p>\n b)\u00a08<\/p>\n c)\u00a012<\/p>\n d)\u00a03<\/p>\n e)\u00a0None of these<\/p>\n Question 17:\u00a0<\/b>The speed of boat when travelling downstream is 32 km\/hr whereas when travelling upstream it is 28 km\/hr. What is the speed of the boat in still water ?<\/p>\n a)\u00a027 km\/hr<\/p>\n b)\u00a029 km\/hr<\/p>\n c)\u00a031 km\/hr<\/p>\n d)\u00a0Cannot be determined<\/p>\n e)\u00a0None of these<\/p>\n Question 18:\u00a0<\/b>A 200 meter long train crosses a platform double its length in 36 seconds What is the speed of train in kmph ?<\/p>\n a)\u00a060<\/p>\n b)\u00a048<\/p>\n c)\u00a064<\/p>\n d)\u00a066<\/p>\n e)\u00a0None of these<\/p>\n Question 19:\u00a0<\/b>Ajay walked 2m towards east, took a right turn and walked 7m. He then took a left turn and walked 5m before taking a left turn and walking 7m. He then took a final right turn and walked 1 m before stopping. How far is Ajay from the starting point?<\/p>\n a)\u00a08m<\/p>\n b)\u00a07m<\/p>\n c)\u00a06m<\/p>\n d)\u00a05m<\/p>\n e)\u00a09m<\/p>\n Question 20:\u00a0<\/b>A truck covers a distance of 360 Km in 8 h. A car covers the same distance in 6 h What is the respective ratio between the speed of the truck and the car ?<\/p>\n a)\u00a03:5<\/p>\n b)\u00a03:4<\/p>\n c)\u00a01:2<\/p>\n d)\u00a04:5<\/p>\n e)\u00a0None of these<\/p>\n Enroll to CAT 2022 Complete Course<\/a><\/p>\n Answers & Solutions:<\/strong><\/span><\/p>\n 1)\u00a0Answer\u00a0(D)<\/strong><\/p>\n All the three friends will meet at the starting point again after X seconds, such that X is the LCM of the times taken by J, K and L to complete one round.<\/p>\n => LCM of 12, 18 and 20 = 180 seconds = 3 minutes.<\/p>\n Hence 3 minutes is the answer.<\/p>\n 2)\u00a0Answer\u00a0(E)<\/strong><\/p>\n Let the speed of boat in still water be v and the speed of water be x.<\/p>\n Boat speed while going upstream = v-x = 28<\/p>\n Boat speed while going downstream = v+x = 32<\/p>\n => 2v = 60 => v = 30<\/p>\n Hence, none of these is the correct answer.<\/p>\n 3)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Part of tank emptied in 1 hour by the $\\frac{1}{2}$ – $\\frac{2}{7}$ = $\\frac{1}{14}$<\/p>\n The leak will empty the tank in 14 hours.<\/p>\n 4)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Suppose the required distance be d km\/h<\/p>\n Then, d\/4-d\/5=15min=1\/4 h \u21d2d 1\/20=1\/4\u21d2d=5km<\/p>\n 5)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Speed downstream = (15 + 3) kmph = 18 kmph.<\/p>\n Distance traveled =(18\u00d712\/60)km = 3.6 km.<\/p>\n 6)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Time taken to cover 375 km = (375\/75)h = 5h<\/p>\n Number of stoppages = 375\/125-1 = 2<\/p>\n Total time to stoppages = (5 \u00d7 2 ) min = 10 min<\/p>\n Hence, total time taken = 5 h 10 min<\/p>\n 7)\u00a0Answer\u00a0(C)<\/strong><\/p>\n With the current => downstream 8)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Let the speed of the train be x kmph. $(x+10) = 360$ 9)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Let x be the speed of bike and y be the speed of bus.<\/p>\n y=8x<\/p>\n Also, bike covers 186 kilometers of distance in 3 hours<\/p>\n Therefore, x = 186\/3 = 62km\/hr<\/p>\n Now, y = 8x = 496km\/hr<\/p>\n Distance covered by bus in 10 hours with this speed = 4960 km\/hr<\/p>\n 10)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Speed of train = x<\/p>\n Relative speed = x + 9(5\/18) = x + 2.5<\/p>\n Speed = 210\/6 = 35m\/s<\/p>\n x + 2.5\u00a0= 35 => x = 32.5\u00a0m\/s = 32.5 * (18\/5) = 6.5 * 18 = 117 kmph<\/p>\n 11)\u00a0Answer\u00a0(E)<\/strong><\/p>\n We know the formula of speed which is Speed = Distance\/Time<\/p>\n Speed of a truck = 640\/10 = 64<\/p>\n Speed of a car = 640\/8 = 80<\/p>\n Ratio of speed of truck and car = 64:80 = 4:5<\/p>\n 12)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Number of days in 4 weeks = 4*7 = 28<\/p>\n Since Faisal walks 325 m every day<\/p>\n Distance walked in 28 days = 325*28 = 9100m<\/p>\n 9100m = 9.1km<\/p>\n 13)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Length of the train = 280m<\/p>\n Length of the platform = (280*3)m<\/p>\n Since the train passes the platform completely<\/p>\n Total disttance travelled by train = 280+(3*280) = 4*280<\/p>\n Time take = 6min 40s = 360+40 = 400s<\/p>\n Speed = 4*280\/400 = 2.8 m\/s<\/p>\n 14)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Least common multipke of 36,27 and 9 is 108. Perimeter of square field = 784 ft.<\/p>\n Radius of circular field = Side of square field = $\\frac{784}{4}$ = 196 ft.<\/p>\n Area of circular field = $\\pi r^2 = \\frac{22}{7}\\times196\\times196 = 120736$ sq ft<\/p>\n 16)\u00a0Answer\u00a0(D)<\/strong><\/p>\n LCM of 12, 18 and 20 = 180<\/p>\n Hence, they’ll meet again after 180 seconds => 3 minutes.<\/p>\n 17)\u00a0Answer\u00a0(E)<\/strong><\/p>\n Let the speed of boat be b and that of water be w.<\/p>\n Hence, b+w = 32<\/p>\n and b-w = 28<\/p>\n Adding both eqns together, 2b = 60<\/p>\n b=30km\/hr<\/p>\n 18)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Length of platform = 200*2 = 400 For ease, we represent this in diagrammatic form. Speed of the truck = 360\/8 = 45 km\/hr
\nleak<\/p>\n
\nAgainst the current => upstream
\nLet the speed of the boat be \u2018s\u2019 and the speed of the river be \u2018r\u2019.
\nSo, s – r = 5 and s + r = 15
\n=>2s = 20 => s = 10 and r = 5 kmph
\nSpeed of the current = 5 kmph<\/p>\n
\nSpeed of the man = 10 kmph
\nRelative speed = (x+10) kmph
\n$(x+10)\\times\\dfrac{4}{60\\times60} = \\dfrac{400}{1000}$<\/p>\n
\n$x=\u00a0 350$
\nHence, Speed of the train = 350 kmph.<\/p>\n
\nHence Harish, Dilip and Asha will meet at 108 second i.e 1 minute and 48 seconds.
\nTherefore, the correct option is option A.
\n15)\u00a0Answer\u00a0(B)<\/strong><\/p>\n
\nThe actual distance covered by train in 36 seconds = Length of platform + Length of train = 400+200= 600
\nSpeed of the train = 600\/36 = 16.67m\/s = 60km\/hr
\nHence, ther correct option is A.
\n19)\u00a0Answer\u00a0(A)<\/strong><\/p>\n
\n
\nNow distance of Ajay from starting point = 2+5+1 = 8 metres.
\nHence, option A is correct.
\n20)\u00a0Answer\u00a0(B)<\/strong><\/p>\n
\nNow,
\nSpeed of the car = 360\/6 = 60km\/hr
\nRatio of speed of truck and car = 45\/60 = 3:4
\nTherefore, option B is correct.<\/p>\n