Join NMAT 2022 Crash Course<\/a><\/p>\n Take NMAT mock test<\/a><\/p>\n Question 1:\u00a0<\/b>The denominator of a fraction is 2 more than thrice it\u2019s numerator.If the numerator as well as denominator are increased by one,the fraction becomes \u2153 .what was that the original fraction?<\/p>\n a)\u00a02\/8<\/p>\n b)\u00a03\/11<\/p>\n c)\u00a04\/14<\/p>\n d)\u00a05\/17<\/p>\n e)\u00a0Cannot be determined<\/p>\n Question 2:\u00a0<\/b>What should come in place of the question marks in the following equations? a)\u00a012<\/p>\n b)\u00a016<\/p>\n c)\u00a0114<\/p>\n d)\u00a0144<\/p>\n e)\u00a0None of these<\/p>\n Question 3:\u00a0<\/b>A number gets reduced to its one third when 48 is subtracted from it.What is two third of that Number?<\/p>\n a)\u00a024<\/p>\n b)\u00a072<\/p>\n c)\u00a036<\/p>\n d)\u00a048<\/p>\n e)\u00a0None of these<\/p>\n Question 4:\u00a0<\/b>$(299.99999)^{3}$ =?<\/p>\n a)\u00a0270,00,000<\/p>\n b)\u00a09,000,000,000<\/p>\n c)\u00a0180,000<\/p>\n d)\u00a0$2.7\\times10^{7}$<\/p>\n e)\u00a0270,00,00<\/p>\n Question 5:\u00a0<\/b>The sum of three consecutive number is given .What is difference between first and third number?<\/p>\n a)\u00a01<\/p>\n b)\u00a03<\/p>\n c)\u00a0Either 1 or 2<\/p>\n d)\u00a02<\/p>\n e)\u00a0None of these<\/p>\n Get 5 NMAT Mocks for Rs. 499<\/a><\/p>\n Question 6:\u00a0<\/b>What will be come in the place of question mark? a)\u00a099.0819<\/p>\n b)\u00a0100.0819<\/p>\n c)\u00a0100.091<\/p>\n d)\u00a0100.0919<\/p>\n e)\u00a0None of these<\/p>\n Question 7:\u00a0<\/b>What value should come in the question mark a)\u00a03795<\/p>\n b)\u00a03800<\/p>\n c)\u00a03810<\/p>\n d)\u00a03875<\/p>\n e)\u00a03995<\/p>\n Question 8:\u00a0<\/b>if $78^{2}$\u00a0is subtracted from the square of a number, the obtained answer is 6460. What is that number?<\/p>\n a)\u00a0109<\/p>\n b)\u00a0111<\/p>\n c)\u00a0113<\/p>\n d)\u00a0115<\/p>\n e)\u00a0none of these<\/p>\n Question 9:\u00a0<\/b>What is the least number to be added to 4321 to make it a perfect square?<\/p>\n a)\u00a032<\/p>\n b)\u00a034<\/p>\n c)\u00a036<\/p>\n d)\u00a038<\/p>\n e)\u00a0none of these<\/p>\n Question 10:\u00a0<\/b>The product of two successive natural numbers is 8556 .What is the smaller number?<\/p>\n a)\u00a089<\/p>\n b)\u00a094<\/p>\n c)\u00a090<\/p>\n d)\u00a092<\/p>\n e)\u00a0none of these<\/p>\n Join 14K MBA Aspirants Telegram Group<\/a><\/p>\n Download Highly Rated MBA preparation App<\/a><\/p>\n Answers & Solutions:<\/strong><\/span><\/p>\n 1)\u00a0Answer\u00a0(E)<\/strong><\/p>\n Let the numerator = $x$<\/p>\n => Denominator = $(3x+2)$<\/p>\n Fraction = $\\frac{x}{3x+2}$<\/p>\n If the numerator as well as denominator are increased by one<\/p>\n => $\\frac{x+1}{3x+2+1}=\\frac{1}{3}$<\/p>\n => $\\frac{x+1}{3x+3}=\\frac{1}{3}$<\/p>\n => $3x+3=3x+3$<\/p>\n It cannot be solved, thus $x$ can take any value and the fraction can be 2\/8 , 3\/11 , 4\/14 ,….<\/p>\n => Ans – (E)<\/p>\n 2)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Expression\u00a0:\u00a0$\\frac{?}{24}=\\frac{72}{\\sqrt{?}}$<\/p>\n => $(?)^{(1+\\frac{1}{2})}= 72 \\times 24$<\/p>\n => $(?)^{\\frac{3}{2}} = 1728 = 12^3$<\/p>\n Multiplying exponents by $(\\frac{2}{3})$ on both sides<\/p>\n => $(?)^{(\\frac{3}{2} \\times \\frac{2}{3})}= (12)^{(3 \\times \\frac{2}{3})}$<\/p>\n => $(?)=12^2=144$<\/p>\n => Ans – (D)<\/p>\n 3)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Let the number be $x$<\/p>\n According to ques, => $x-48=\\frac{x}{3}$<\/p>\n => $3x-144=x$<\/p>\n => $3x-x=2x=144$<\/p>\n => $x=\\frac{144}{2}=72$<\/p>\n $\\therefore$ $(\\frac{2}{3})^{rd}$ of number = $\\frac{2}{3} \\times 72$<\/p>\n = $2 \\times 24 = 48$<\/p>\n => Ans – (D)<\/p>\n 4)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Expression\u00a0: $(299.99999)^{3}$ =?<\/p>\n $\\approx (300)^3$<\/p>\n = $2,70,00,000$<\/p>\n => Ans – (A)<\/p>\n 5)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Let the 3 consecutive numbers be $(x-1),(x),(x+1)$<\/p>\n Difference between first and third number = $(x+1)-(x-1)$<\/p>\n = $(x-x)+(1+1)=2$<\/p>\n => Ans – (D)<\/p>\n 6)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Expression\u00a0:\u00a0$0.001+9.909\\times1.01\\div0.1$<\/p>\n = $0.001 + \\frac{9.909 \\times 1.01}{0.1}$<\/p>\n = $0.001 + (10.00809 \\times 10)$<\/p>\n = $0.001 + 100.0809 = 100.0819$<\/p>\n 7)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Expression =\u00a0$4275\\div496\\times(21^{2})$=?<\/p>\n = $\\frac{4275}{496} \\times 441$<\/p>\n = $8.62 \\times 441 = 3801.42$<\/p>\n $\\approx 3800$<\/p>\n 8)\u00a0Answer\u00a0(E)<\/strong><\/p>\n Let the number be $x$<\/p>\n According to ques,<\/p>\n => $x^2-78^2=6460$<\/p>\n => $x^2=6460+6084$<\/p>\n => $x=\\sqrt{12544}=112$<\/p>\n => Ans – (E)<\/p>\n 9)\u00a0Answer\u00a0(E)<\/strong><\/p>\n We need to find the approximate value of $\\sqrt{4321} \\approx$ 65.73<\/p>\n We find that $65^2=4225$ < $4321$ and $66^2=4356$ > $4321$<\/p>\n So the least number to be added = 4356 – 4321 = 35<\/p>\n $\\therefore$ 35 can be added to 4321 to make it a perfect square.<\/p>\n => Ans – (E)<\/p>\n 10)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Let the successive natural numbers be $(x),(x+1)$<\/p>\n Product = $x(x+1)=8556$<\/p>\n => $x^2+x-8556=0$<\/p>\n => $x^2+93x-92x-8556=0$<\/p>\n => $x(x+93)-92(x+93)=0$<\/p>\n => $(x+93)(x-92)=0$<\/p>\n => $x=-93,92$<\/p>\n $\\because$ The numbers are natural, thus $x \\neq -93$<\/p>\n $\\therefore$ Smaller number =\u00a0$x=92$<\/p>\n => Ans – (D)<\/p>\n
\n$\\frac{?}{24}=\\frac{72}{\\sqrt{?}}$<\/p>\n![](\"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2026\/03\/CAT-2026-Tejas-Batch-Starts-on-9th-Feb-Mon-1.png\")
<\/a><\/div>\n
\n$0.001+9.909\\times1.01\\div0.1$<\/p>\n
\n$4275\\div496\\times(21^{2})$=?<\/p>\n