Probability questions for Bank PO & Clerk exams of SBI PO based on asked previous questions in SBI PO & other banking exams. Download Probability questions and answers PDF with solutions and explanations (Important aptitude questions useful for prelims & mains)<\/p>\n
Download Probability Questions of SBI PO PDF<\/a><\/p>\n 20 SBI PO Mocks Offer (latest pattern mocks) – Rs. 125<\/a><\/p>\n Question 1: A die is thrown twice. What is the probability of getting a sum 7 from the two throws? Question 2: In how many different ways can the letters of the word ‘THERAPY’ be arranged so that the vowels never come together? Question 3: If 6 boys and 6 girls have to sit in a round circular music chair. So, that there is a girl between every 2 boys. Find the number of ways they can sit? Question 4: What is the number of words formed from the letters of the word \u2018JOKE\u2019 So that the vowels and consonants alternate? Daily SBI Exams GK – Current Affairs test<\/a><\/p>\n Question 5: In how many different ways can 5 men and 3 women be seated in a row such that no two women are next to each other? Question 6: In how many different ways can the letter of the word ‘SIMPLE’ be arranged ? Question 7: In how many different ways can the letters of the word ‘SECOND’ be arranged ? Take a Free Mock test for SBI PO<\/a><\/p>\n SBI PO Solved Previous Papers<\/a><\/p>\n Question 8: In how many different ways can the letters of the word \u2018VENTURE\u2019 be arranged? Question 9: In how many different ways can the letters of the word BAKERY be arranged ? Question 10: In how many different ways can the letters of the word DAILY be arranged ? Banking 1 Year Plan – 350 Mocks for just Rs. 499<\/a><\/p>\n Daily Free GK – Current Affairs Tests<\/a><\/p>\n Answers & Solutions 2 Answer(D) 3 Answer(A) 4 Answer(B) 5 Answer(B) 6 Answer(E) 7 Answer(A) 8 Answer(D) 9 Answer(C) 10Answer(D)
\na) 5\/18
\nb) 1\/18
\nc) 1\/9
\nd) 1\/6
\ne)5\/36<\/p>\n
\na) 720
\nb) 1440
\nc) 5040
\nd) 3600
\ne)4800<\/p>\n
\na) 6! \u00d7 5!
\nb) 6! \u00d7 4!
\nc) 6! \u00d7 3!
\nd) 6! \u00d7 2!
\ne)None of these<\/p>\n
\na) 4
\nb) 8
\nc) 12
\nd) 18
\ne)None of these<\/p>\n
\na) 12200
\nb) 14400
\nc) 15600
\nd) 16400
\ne)None of the above<\/p>\n
\na) 520
\nb) 120
\nc) 5040
\nd) 270
\ne)None of these<\/p>\n
\na) 720
\nb) 120
\nc) 5040
\nd) 270
\ne)None of these<\/p>\n
\na) 840
\nb) 5040
\nc) 1260
\nd) 2520
\ne)None of these<\/p>\n
\na) 2400
\nb) 2005
\nc) 720
\nd) 5040
\ne)None of these<\/p>\n
\na) 60
\nb) 48
\nc) 160
\nd) 120
\ne)None of these<\/p>\n
\n1 Answer(D)
\nNumber of ways in which the sum is 7 = (1,6),(2,5),(3,4),(4,3),(5,2),(6,1) => 6 ways
\nTotal number of possibilities = 6 * 6 = 36
\nProbability that sum is 7 = 636\\frac{6}{36}<\/span>3<\/span>6<\/span><\/span><\/span><\/span>6<\/span><\/span><\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span> = 16\\frac{1}{6}<\/span>6<\/span><\/span><\/span><\/span>1<\/span><\/span><\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span> \u200b<\/p>\n
\nNumber of ways of arranging seven letters = 7!
\nLet us consider the two vowels as a group
\nNow the remaining five letters and the group of two vowels = 6
\nThese six letters can be arranged in 6!2! ways( 2! is the number of ways the two vowels can be arranged among themselves)
\nThe number of ways of arranging seven letters such that no two vowels come together
\n= Number of ways of arranging seven letters – Number of ways of arranging the letters with the two vowels being together
\n= 7! – (6!2!)
\n= 3600<\/p>\n
\nCircular permutation = n! (n – 1)!
\n\u2234 Number of ways = 6! (6 – 1)! = 6! \u00d7 5!<\/p>\n
\nSolution: Word name: \u2018JOKE\u2019 Vowels: O, E
\nConsonants: J, K
\n\u2234 Possible arrangement beginning with consonant: JOKE, KOJE, JEKO, KEJO = 4 Numbers
\nbeginning with vowel: OJEK, OKEJ, EJOK, EKOJ = 4 Numbers
\nRequired number = 4+4 = 8 numbers<\/p>\n
\nNo two women would be seated next to each other if they sit between men. So, first the men can be arranged in 5! ways. There are six spots between the men. Number of ways to arrange the 3 women in those six spots is P63 P_6^3 P63\u200b ways. So, total number of ways = 120*120 = 14400 ways.<\/p>\n
\nIf there are n different letter in a word then n! different words can be formed.
\nIn SIMPLE there are 6 different letters and hence 6! new words can be formed by different arangement.
\nHence, 720 new words can be formed.<\/p>\n
\nIf a word has n different letters in it, then they can be arranged in n! different ways.
\nHere SECOND has 6 different letters and they can be arranged in 6! ways i.e 720 different ways.<\/p>\n
\nIn “VENTURE”, there are 7 letters of which E is repeated twice.
\nNumber of ways of arranging the letters of the word VENTURE = 7!\/2! = 5040\/2 = 2520<\/p>\n
\nAs there are 6 different letters in the word “Bakery” hence, total number of ways of arranging it will be = 6! = 720<\/p>\n
\nIf a word has n different letters then they can be arranged in n! different ways.
\nDAILY has 5 different letters which can bve arranged in 5! different ways.
\n5!=5*4*3*2*1=120
\nTherefore, option D is answer.<\/p>\n