Algebra and equations are important for the SSC CGL exam. We have provided some SSC CGL algebra questions and answers with solutions and detailed explanations. Practice questions on maths algebra.<\/p>\n
Download App to Access Questions Directly<\/a><\/p>\n 25 SSC CGL Mocks – Just Rs. 149<\/a><\/p>\n Question 1: If 3.352 – (9.759 – x ) – 19.64 = 7.052, then what is the value of x?<\/p>\n a) -6.181 Question 2: If 7 + 3x \u2265 5 – x\/2 and 2x + 3 \u2264 5 – 2x; then x can take which of the following values?<\/p>\n a) 0 Question 3: Coefficient of $x^2$ in (x + 3)(2 – 4x)(5x – 6)\u00a0 is<\/p>\n a) 26 Question 4: If a + b = 10 and $a^2 + b^2$ = 58, then find ab<\/p>\n a) 21 Question 5: If 2x – 2(4 – x) < 2x – 3 < 3x + 3; then x can take which of the following values?<\/p>\n a) 2 SSC CGL Previous Papers Download PDF<\/a><\/p>\n Take SSC CGL Free Mock Test<\/a><\/p>\n Question 6: a) 37 <\/p>\n Question 7:<\/strong><\/p>\n If x – y = -9 and xy = -20, then \ufb01nd $x^{2} + y^{2}$<\/p>\n a) 61 Question 8: a) 1 Question 9: Which of the following is correct?<\/p>\n a) $(6x + y)(x – 6y) = 6x^2 + 35xy – 6y^2$ Question 10: If a – b = -5 and $a^2 + b^2$ = 73, then find ab.<\/p>\n a) 35 SSC CGL 2018 Syllabus PDF<\/a><\/p>\n 18000+ Questions – Free SSC Study Material<\/a><\/p>\n Solutions: (1 to 10)<\/strong><\/p>\n 1) Answer (c)<\/strong><\/p>\n Expression\u00a0:\u00a03.352 – (9.759 – x ) – 19.64 = 7.052<\/p>\n => 3.352 – 9.759 + x = 7.052 + 19.64 2) Answer (a)<\/strong><\/p>\n Expression 1\u00a0:\u00a07 + 3x \u2265 5 – x\/2 3) Answer (d)<\/strong><\/p>\n A coefficient is a numerical or constant quantity placed before and multiplying the variable in an algebraic expression. Eg :\u00a0In $ax^2$, coefficient is $a$<\/p>\n Expression\u00a0: $(x + 3)(2 – 4x)(5x – 6)$ 4) Answer (a) Given\u00a0: $(a + b) = 10$ and $a^2 + b^2 = 58$ 5) Answer (a)<\/strong><\/p>\n Expression\u00a01\u00a0:\u00a0$2x – 3 < 3x + 3$ 6) Answer (c) A coefficient is a numerical or constant quantity placed before and multiplying the variable in an algebraic expression. Eg :\u00a0In $ax^2$, coefficient is $a$ Top Rated APP for SSC CGL Preparation<\/a><\/p>\n 7) Answer (b)<\/strong><\/p>\n Given\u00a0: $(x – y) = -9$ and $xy = -20$ 8) Answer (b)<\/strong><\/p>\n Expression\u00a01\u00a0:\u00a0$2x + 3$ > $2 – 3x$ 9) Answer (b)<\/strong><\/p>\n Expression\u00a0: $(6x + y)(x – 6y)$ 10) Answer (b)<\/strong><\/p>\n Given\u00a0: $(a – b) = -5$ and $a^2 + b^2 = 73$
\n<\/strong><\/p>\n
\nb) 13.581
\nc) 33.099
\nd) 39.803<\/p>\n
\n<\/strong><\/p>\n
\nb) 1
\nc) 2
\nd) -1<\/p>\n
\n<\/strong><\/p>\n
\nb) -74
\nc) 74
\nd) -26<\/p>\n
\n<\/strong><\/p>\n
\nb) 24
\nc) 25
\nd) 16<\/p>\n
\n<\/strong><\/p>\n
\nb) 3
\nc) 4
\nd) 5<\/p>\n
\n<\/strong>Coef\ufb01cient of x in (x + 9)(8 – 5x) is<\/p>\n
\nb) -53
\nc) -37
\nd) 53<\/p>\n
\nb) 41
\nc) 85
\nd) 113<\/p>\n
\n<\/strong>If 4x – 5(2x – 1) > 2x + 3 > 2 – 3x; then x can take which of the following values?<\/p>\n
\nb) 0
\nc) 2
\nd) -3<\/p>\n
\n<\/strong><\/p>\n
\nb) $(6x + y)(x – 6y) = 6x^2 – 35xy – 6y^2$
\nc) $(6x + y)(x – 6y) = 6x^2 – 37xy – 6y^2$
\nd) $(6x + y)(x – 6y) = 6x^2 + 37xy – 6y^2$<\/p>\n
\n<\/strong><\/p>\n
\nb) 14
\nc) 50
\nd) 24<\/p>\n
\n=> x =\u00a026.692 + 9.759 – 3.352
\n=> x = 36.451\u00a0– 3.352
\n=> x = 33.099
\n=> Ans – (C)<\/p>\n
\n=> $3x + \\frac{x}{2} \\geq 5 – 7$
\n=> $\\frac{7x}{2} \\geq -2$
\n=> $x \\geq \\frac{-4}{7}$ ———(i)
\nExpression 2\u00a0:\u00a02x + 3 \u2264 5 – 2x
\n=> $2x + 2x \\leq 5 – 3$
\n=> $4x \\leq 2$
\n=> $x \\leq \\frac{2}{4} = \\frac{1}{2}$ ———-(ii)
\nCombining inequalities (i) and (ii), we get\u00a0: $\\frac{-4}{7} \\leq x \\leq \\frac{1}{2}$
\nThus, the only possible value that $x$ can take among the given options = 0
\n=> Ans – (A)<\/p>\n
\n= $(2x – 4x^2 + 6 – 12x)(5x – 6)$
\n= $(-4x^2 – 10x + 6)(5x – 6)$
\n=\u00a0$5x(-4x^2 – 10x + 6) – 6(-4x^2 – 10x + 6)$
\n= $-20x^3 – 50x^2 + 30x + 24x^2 + 60x – 36$
\n= $-20x^3 – 26x^2 + 90x – 36$
\n$\\therefore$ Coefficient of $x^2$ = -26
\n=> Ans – (D)<\/p>\n
\n<\/strong><\/p>\n
\nUsing $(a + b)^2 = a^2 + b^2 + 2ab$
\n=> $(10)^2 = 58 + (2 \\times ab)$
\n=> $2 ab = 100 – 58 = 42$
\n=> $ab = \\frac{42}{2} = 21$
\n=> Ans – (A)<\/p>\n
\n=> $3x – 2x$\u00a0> $-3 – 3$
\n=> $x$\u00a0> $-6$ ———-(i)
\nExpression 2\u00a0:\u00a0$2x – 2(4 – x) < 2x – 3$
\n=> $4x – 8$ < $2x – 3$
\n=> $4x – 2x$ < $8 – 3$
\n=> $x$ < $\\frac{5}{2}$ ——(ii)
\nCombining inequalities (i) and (ii), we get\u00a0: $-6$ < $x$ < $\\frac{5}{2}$
\nThus, only value that $x$ can take among the options =\u00a02
\n<\/b>=> Ans – (A)<\/p>\n
\n<\/strong><\/p>\n
\nExpression\u00a0: $(x + 9)(8 – 5x)$
\n= $8x – 5x^2 + 72 – 45x$
\n= $-5x^2 – 37x + 72$
\n$\\therefore$ Coefficient of $x$ = -37
\n=> Ans – (C)<\/p>\n
\nUsing $(x – y)^2 = x^2 + y^2 – 2xy$
\n=> $(-9)^2 = (x^2 + y^2) – (2 \\times -20)$
\n=> $(x^2 + y^2) = 81 – 40 = 41$
\n=> Ans – (B)<\/p>\n
\n=> $2x + 3x$\u00a0> $2 – 3$
\n=> $x$\u00a0> $\\frac{-1}{5}$ ———-(i)
\nExpression 2\u00a0:\u00a0$4x – 5(2x – 1)$ > $2x + 3$
\n=> $-6x + 5$ > $2x + 3$
\n=> $2x + 6x$ < $5 – 3$
\n=> $x$ < $\\frac{1}{4}$ ——(ii)
\nCombining inequalities (i) and (ii), we get\u00a0: $\\frac{-1}{5}$ < $x$ < $\\frac{1}{4}$
\nThus, only value that $x$ can take among the options =\u00a00
\n<\/strong>=> Ans – (B)<\/p>\n
\n= $6x^2 – 36xy + xy – 6y^2$
\n= $6x^2 – 35xy – 6y^2$
\n=> Ans – (B)<\/p>\n
\nUsing $(a – b)^2 = a^2 + b^2 – 2ab$
\n=> $(-5)^2 = 73 – (2 \\times ab)$
\n=> $2 ab = 73 – 25 = 48$
\n=> $ab = \\frac{48}{2} = 24$
\n=> Ans – (D)<\/p>\n