Question 89

If the second, third and first terms of a geometric progression (GP) form an arithmetic progression (AP), then find the first term of the GP, given that the sum to infinite terms of the GP is 36

Solution

Let us take terms of GP as $$a,ar,ar^2$$

then the terms in AP will be $$ar,ar^2,a$$

In that case, $$ar^2=\frac{(a+ar)}{2}$$

$$2ar^2=a+ar$$

On simplifying the equation, we get r =  or r = -1/2

r can not be 1 as that will make each term of the GP same which will not make it an infinite GP, so we get r = -1/2

⇒ Also given that sum to infinite terms of the GP = 36

$$\frac{a}{1-r\ }=36$$

plugging r=-1/2 we get

a = 54.

Your Doubts

Ask a Doubt (know more)

Drop Your File Here!

** You can Drag and Drop an Image in the above textarea
add image

cracku

Boost your Prep!

Download App