x is 5 times longer than y. The percentage by which y is less than x is :
It is given that x is 5 times longer than y, => $$x=5y$$
=> $$\frac{x}{y}=\frac{5}{1}$$
Let $$x=5$$ and $$y=1$$
=> Percentage by which y is less than x = $$\frac{x-y}{x} \times 100$$
= $$\frac{5-1}{5} \times 100$$
= $$4 \times 20=80\%$$
=> Ans - (C)
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