Question 5
The height of a light house is 20 meters above sea level. The angle of depression (from the top of the lighthouse) of a ship in the sea is 30°. What is the distance of the ship from the foot of the light house?
Solution
angle of depression = 30° = angle of elevation from the boat
height of light house = 20m
let the distance btw the light house and boat be x
tanФ= $$\frac{opp}{adj}$$
tan30°= $$20\div \text{distance btw the light house and boat}$$
$$\dfrac{1}{\sqrt{3}}=20\div x$$
x=$$20\sqrt{3}$$
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