In the following questions two equations numbered I and II are given. You have to solve both the equations and
Give answer a: if x >y
Give answer b: if x ≥ y
Give answer c: if x < y
Give answer d: if x ≤ y
Give answer e: if x = y or the relationship between x and y cannot be established.
I. $$25x^{2}+35x+12=0$$
II. $$10y^{2}+9y+2=0$$
I.$$25x^{2} + 35x + 12 = 0$$
=> $$25x^2 + 20x + 15x + 12 = 0$$
=> $$5x (5x + 4) + 3 (5x + 4) = 0$$
=> $$(5x + 4) (5x + 3) = 0$$
=> $$x = \frac{-4}{5} , \frac{-3}{5}$$
II.$$10y^{2} + 9y + 2 = 0$$
=> $$10y^2 + 5y + 4y + 2 = 0$$
=> $$5y (2y + 1) + 2 (2y + 1) = 0$$
=> $$(2y + 1) (5y + 2) = 0$$
=> $$y = \frac{-1}{2} , \frac{-2}{5}$$
Therefore $$x < y$$
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