Question 18

A bag contains 6 red balls, 11 yellow balls and 5 pink balls. If two balls are drawn at a random from the bag, one after another. What is the probability that the first ball drawn was red and the second ball drawn was yellow in colour?

Solution

There are 6 red balls, 11 yellow balls and 5 pink balls

Total number of balls = 6 + 11 + 5 = 22

Probability of selecting red ball = $$\frac{6}{22}$$

After selecting one ball, there are 21 balls left

Probability of selecting yellow ball = $$\frac{11}{21}$$

Therefore, probability = $$\frac{6}{22}\times\ \frac{11}{21}$$ = $$\frac{1}{7}$$

Answer is option C.

Video Solution

video

Create a FREE account and get:

  • All Quant Formulas and shortcuts PDF
  • 40+ previous papers with detau solutions PDF
  • Top 500 MBA exam Solved Questions for Free

cracku

Boost your Prep!

Download App