Question 1
In how many ways a committee consisting of 5 men and 6 women can be formed from 8 men and 10 women ?
Solution
Number of ways a committee consisting of 5 men and 6 women can be formed from 8 men and 10 women
= $$C^{10}_6\times C^8_5$$
= $$C^{10}_4\times C^8_3$$
= $$\frac{10\times9\times8\times7}{1\times2\times3\times4}\times\frac{8\times7\times6}{1\times2\times3}$$
= $$(10\times3\times7)\times(8\times7)$$
= $$210\times56=11760$$
=> Ans - (D)
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